blocks|key|1274050|text|简单地说你可以用这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1274051|+++student.sort(Comparator.comparing(Student::+getName));//Single+Sorting
++++student.sort(Comparator.comparing(Student::+getName).reversed());//Single+reverse+Sorting
++++student.sort(Comparator.comparing(Student::+getName).thenComparing(Student::getScore));//Double|code-block|syntax|javascript|1274052|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

simply you can use this

<pre><code> student.sort(Comparator.comparing(Student:: getName));//Single Sorting
 student.sort(Comparator.comparing(Student:: getName).reversed());//Single reverse Sorting
 student.sort(Comparator.comparing(Student:: getName).thenComparing(Student::getScore));//Double
</code></pre>

blocks|key|27165|text|student.sort(Comparator.comparing(Student::getName));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|27166|阅读更多关于比较器的信息。|unstyled|offset|length|27167|entityMap|0|LINK|mutability|MUTABLE|url|https://www.mkyong.com/java8/java-8-lambda-comparator-example/^0|0|6|3|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>student.sort(Comparator.comparing(Student::getName));
</code></pre>

Read more about <a href="https://www.mkyong.com/java8/java-8-lambda-comparator-example/" rel="nofollow noreferrer">comparators</a>.

blocks|key|1274023|text|您可以定义一个比较器来完成此操作。一种简单的方法是使用匿名类。https://docs.oracle.com/javase/8/docs/api/java/util/Comparator.html|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1274024|Collections.sort(student,+new+Comparator<Student>()+{
++++public+int+compare(Student+a,+Student+b)+{
++++++++return+a.getName().compare(b.getName());
++++}
};|code-block|syntax|javascript|1274025|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/8/docs/api/java/util/Comparator.html^0|V|1V|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

You can define a Comparator to do this. One easy way is with an anonymous class.
<a href="https://docs.oracle.com/javase/8/docs/api/java/util/Comparator.html" rel="nofollow noreferrer">https://docs.oracle.com/javase/8/docs/api/java/util/Comparator.html</a>

<pre><code>Collections.sort(student, new Comparator&lt;Student&gt;() {
 public int compare(Student a, Student b) {
 return a.getName().compare(b.getName());
 }
};
</code></pre>

blocks|key|27153|text|您可以使用Collections.sort方法接受comparator作为其第二个参数。传入一个定义您想要的排序的comparator。例如，给定一个Student类，您可以使用Collections.sort和自定义comparator对Student进行排序，按如下所示的升序排列：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|27154|import+java.util.Arrays;
import+java.util.Collections;
import+java.util.Comparator;
import+java.util.LinkedList;
import+java.util.List;

class+Student+{

++++private+final+String+name;
++++private+final+int+score;

++++Student(String+name,+int+score)+{
++++++++this.name+=+name;
++++++++this.score+=+score;
++++}

++++public+String+getName()+{
++++++++return+name;
++++}

++++public+int+getScore()+{
++++++++return+score;
++++}

++++@Override
++++public+String+toString()+{
++++++++return+"Student+[name="+%2B+name+%2B+",+score="+%2B+score+%2B+"]";
++++}

++++public+static+void+main(String[]+args)+{
++++++++List<Student>+list+=+new+LinkedList<>(
++++++++++++++++Arrays.asList(new+Student("David",+3),+new+Student("Alice",+3),+new+Student("Thomas",+9)));

++++++++System.out.println("Before+Sort:+"+%2B+list);

++++++++Collections.sort(list,+new+Comparator<Student>()+{
++++++++++++@Override
++++++++++++public+int+compare(Student+o1,+Student+o2)+{
++++++++++++++++return+o1.getName().compareTo(o2.getName());
++++++++++++}
++++++++});

++++++++System.out.println("After+Sort:+"+%2B+list);
++++}

}|code-block|syntax|javascript|27155|这将产生输出。|27156|before:+[Student+[name=David,+score=3],+Student+[name=Alice,+score=3],+Student+[name=Thomas,+score=9]]
after:+[Student+[name=Alice,+score=3],+Student+[name=David,+score=3],+Student+[name=Thomas,+score=9]]|27157|entityMap^0|5|G|P|A|1L|A|23|7|2H|G|31|A|3C|7|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|16|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|P|$]]

You can use the <code>Collections.sort</code> method accepts a <code>comparator</code> as its second argument. Pass in a <code>comparator</code> that defines the ordering that you would like. For example given a <code>Student</code> class, you can use <code>Collections.sort</code> with a custom <code>comparator</code> to sort <code>Student</code> by ascending order of name like this:

<pre><code>import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedList;
import java.util.List;

class Student {

 private final String name;
 private final int score;

 Student(String name, int score) {
 this.name = name;
 this.score = score;
 }

 public String getName() {
 return name;
 }

 public int getScore() {
 return score;
 }

 @Override
 public String toString() {
 return "Student [name=" + name + ", score=" + score + "]";
 }

 public static void main(String[] args) {
 List&lt;Student&gt; list = new LinkedList&lt;&gt;(
 Arrays.asList(new Student("David", 3), new Student("Alice", 3), new Student("Thomas", 9)));

 System.out.println("Before Sort: " + list);

 Collections.sort(list, new Comparator&lt;Student&gt;() {
 @Override
 public int compare(Student o1, Student o2) {
 return o1.getName().compareTo(o2.getName());
 }
 });

 System.out.println("After Sort: " + list);
 }

}
</code></pre>

This will produce the output

<pre><code>before: [Student [name=David, score=3], Student [name=Alice, score=3], Student [name=Thomas, score=9]]
after: [Student [name=Alice, score=3], Student [name=David, score=3], Student [name=Thomas, score=9]]
</code></pre>

blocks|key|27159|text|如果您使用java+>+8，您可以使用Lambda表达式，得到如下内容：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|27160|Collections.sort(student,+(p1,+p2)+->+p1.name.compareTo(p2.name));|CODE|27161|或者在列表中使用排序方法|27162|student.sort((p1,+p2)+->+p1.name.compareTo(p2.name));|27163|entityMap^0|J|9|0|0|1U|0|0|0|1H|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@$9|S|A|T|B|H]]|D|@]|E|$]]|$1|I|3|J|5|6|7|U|8|@]|D|@]|E|$]]|$1|K|3|L|5|6|7|V|8|@$9|W|A|X|B|H]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|N|$]]

if you use java > 8. You can use Lambda expression, and you get something like this:

<code>Collections.sort(student, (p1, p2) -&gt; p1.name.compareTo(p2.name));</code>

or Using sort method in List

<code>student.sort((p1, p2) -&gt; p1.name.compareTo(p2.name));</code>

I have a List:

<pre><code> LinkedList&lt;Student&gt; student = new LinkedList&lt;Student&gt;();
</code></pre>

In the Student class, it has an attribute String name. I want to sort the List students by its name.
Is there any way I could do that?

Sort LinkedList in Java

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一份清单： LinkedList<Student> student = new LinkedList<Student>();在Student类中，它有一个属性字符串名。我想按学生的名字对名单进行排序。有什么办法我能做到吗？

问用Java对LinkedList进行排序
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回答 5

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