删除字典中的类似条目
删除字典中的类似条目
提问于 2018-09-08 08:37:01
我有字典：
hostServiceDict = {"http://192.168.1.1:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO'],
"http://192.168.1.2:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'UDDC'],
"http://192.168.1.3:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'HTTPServer'],
"http://192.168.1.4:8080/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'NetcdfSubset'],
"http://192.168.1.5:8080/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'WCS', 'NCSS'],
"http://192.168.1.5:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'WCS', 'NCSS'],
"http://192.168.1.6:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'DAP4'],
"http://192.168.1.7:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'NCML', 'DAP4'],
"http://192.168.1.8:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'NetcdfSubset'],
"http://192.168.1.9:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'UDDC'],
"http://192.168.1.18:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'NetcdfSubset'],
"http://192.168.1.18:8800/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'NetcdfSubset']
}两个条目有一些ip地址，但是端口部分对于http://192.168.1.5 and http://192.168.1.18是不同的。我需要删除第二个复制的，使它像：
hostServiceDict = {"http://192.168.1.1:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO'],
"http://192.168.1.2:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'UDDC'],
"http://192.168.1.3:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'HTTPServer'],
"http://192.168.1.4:8080/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'NetcdfSubset'],
"http://192.168.1.5:8080/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'WCS', 'NCSS'],
"http://192.168.1.6:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'DAP4'],
"http://192.168.1.7:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'NCML', 'DAP4'],
"http://192.168.1.8:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'NetcdfSubset'],
"http://192.168.1.9:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'UDDC'],
"http://192.168.1.18:80/thredds/catalog.xml": ['OPENDAP', 'WMS', 'HTTP', 'ISO', 'NetcdfSubset'],
} 我试过了，但它仍然给了我和原点一样的结果：
result = {}
for urls, services in hostServiceDict.items():
i = urls.strip('http://').strip('thredds/catalog.xml').split(':')
ip = i[0]
if ip not in result.items():
if ip in urls:
result[urls] = services
print(result)回答 2
Stack Overflow用户
回答已采纳
发布于 2018-09-08 09:00:31
if ip not in result.items():永远找不到ip，因为IP不在results中。你必须跟踪你所见过的IP：
result = {}
seen_ips = set()
for url, services in hostServiceDict.items():
ip = url.strip('http://').strip('thredds/catalog.xml').split(':')[0]
if ip not in seen_ips:
seen_ips.add(ip)
result[url] = services
print(result)为了使代码更好，您可以执行真正的url解析：
import re
def get_host(url):
return re.match(r'https?://([^:/]+).*', url).groups(0)这样就可以更容易地制作主机-> (url，services)字典，而不是删除重复的“手动”：
data_by_hostname = {get_host(url): (url, services)
for url, services in hostServiceDict.items()}这个dict负责删除重复的主机名。
然后，如果需要，您可以再次从值构造url ->服务二元化：
result = dict(data_by_hostname.values())Stack Overflow用户
发布于 2018-09-08 09:02:49
您可以通过拥有一个列表并使用已经跟踪的ips验证新ip来跟踪不同的ips --这将需要对您的逻辑进行如下小的更改：
result = {}
distinct_ips = []
for urls, services in hostServiceDict.items():
i = urls.strip('http://').strip('thredds/catalog.xml').split(':')
ip = i[0]
if ip not in distinct_ips:
distinct_ips.append(ip)
if ip in urls:
result[urls] = services
print(result)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/52233524
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