blocks|key|1866935|text|Json字符串是无效的，它不是由JSON.stringify()串成的，而是由toString方法串成的，否则嵌套的对象就会被正确地串成字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1866936|​|1866937|📷|atomic|offset|length|1866938|1866939|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://developer.qcloudimg.com/http-save/yehe-900000/5651c8cfbced22ae81883748311faa6d.png|imageAlt^0|0|0|0|1|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@$G|V|H|W|1|X]]|A|$]]|$1|I|3|C|5|6|7|Y|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|Q|R|-4]]]]

Your Json String is not valid and is not stringified by JSON.stringify() instead it was stringified by toString method, otherwise nested objects were stringified properly.

<a href="https://i.stack.imgur.com/zVLF9.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/zVLF9.png" alt="enter image description here"></a>

blocks|key|4481315|text|问题是我没有解析正确的东西。以下是正确的片段：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4481316|let+p+=+JSON.parse(data.project);

++this.employees.push({
++projectName:+p.projectName,
++poNumber:+p.poNumber
})|code-block|syntax|javascript|4481317|谢谢大家的帮助！你的回答都是对的。|4481318|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The problem was that I didn't parse the right thing. Here is the correct snippet:

<pre><code>let p = JSON.parse(data.project);

 this.employees.push({
 projectName: p.projectName,
 poNumber: p.poNumber
})
</code></pre>

Thank you everyone for help! Every answer of you was right.

blocks|key|1866944|text|就像这样：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1866945|JSON.parse(data).array.forEach(element+=>+{
++this.employees.push({
++++projectName:+element.project.projectName,
++++poNumber:+element.project.poNumber
++})
})|code-block|syntax|javascript|1866946|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try like this :

<pre><code>JSON.parse(data).array.forEach(element =&gt; {
 this.employees.push({
 projectName: element.project.projectName,
 poNumber: element.project.poNumber
 })
})
</code></pre>

blocks|key|751217|text|我在JSON格式中得到了同样的错误，但是在在线JSON验证器上验证它之后，它似乎是完美的。在此基础上，我创建了下面的示例，展示了在“员工”数组中获取数据的两种不同方法。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|751218|我希望这会有所帮助。|751219|​|751220|let+data+=+{
	"id":1,"name":"john+doe",
++"project":[
++++++++{
		"projectName":+"proj1",
		"poNumber":+"1"
	},
++++++++{
		"projectName":+"proj2",
		"poNumber":+"2"
	}
++++]
};

let+employees+=+[];


Object.keys(data).map(key+=>+{
++++if(key+===+'project')+{
++++++++//+Method+1
++++++++//+===========================
++++++++data[key].map(obj+=>+{
++++++++++++employees.push(obj);
++++++++});
++++++++
++++++++//+Method+2+:+Shorter+method
++++++++//+===========================
++++++++employees.push(...data[key]);
++++}
});

console.log('Employees+:',+employees);|code-block|syntax|javascript|751221|751222|谢谢你，吉格尼什·拉瓦尔|751223|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Q|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|S|8|@]|9|@]|A|$I|J]]|$1|K|3|E|5|6|7|T|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|U|8|@]|9|@]|A|$]]|$1|N|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|O|$]]

I was getting same error in JSON format, but after validating it on online JSON validator it seems perfect. On the basis of that I have created following example which shows two diffrent ways to get data in your "employees" array.

I hope this will be helpful.

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let data = {
	"id":1,"name":"john doe",
 "project":[
 {
		"projectName": "proj1",
		"poNumber": "1"
	},
 {
		"projectName": "proj2",
		"poNumber": "2"
	}
 ]
};

let employees = [];


Object.keys(data).map(key =&gt; {
 if(key === 'project') {
 // Method 1
 // ===========================
 data[key].map(obj =&gt; {
 employees.push(obj);
 });
 
 // Method 2 : Shorter method
 // ===========================
 employees.push(...data[key]);
 }
});

console.log('Employees :', employees);</code></pre>
</div>
</div>


Thanks,
Jignesh Raval

blocks|key|1866950|text|JSON.parse(data).array.forEach(element+=>+{
+++++this.employees.push({
++++++++projectName:+element.project.projectName,
++++++++poNumber:+element.project.poNumber
+++++})
});|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1866951|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>JSON.parse(data).array.forEach(element =&gt; {
 this.employees.push({
 projectName: element.project.projectName,
 poNumber: element.project.poNumber
 })
});
</code></pre>

I want to parse a string and save <code>projectName</code> and <code>poNumber</code> into 2 variables. This is what I have by now, using JSON.parse()

<pre><code>employees = []
JSON.parse(data).array.forEach(element =&gt; {
 this.employees.push({
 projectName: element.projectName,
 poNumber: element.poNumber
 })
 });

console.log(employees['projectName'])
console.log(employees['poNumber'])
</code></pre>

where <code>data</code> has this format:

<code>{"id":1,"name": "john doe", "project":"[object Object]"}</code>

and <code>project</code> looks like:

<pre><code>"project": [
 {
 "projectName": "proj1",
 "poNumber": "1"
 }
]
</code></pre>

But I get this error

<blockquote>
 ERROR SyntaxError: Unexpected token o in JSON at position 1
</blockquote>

Where am I mistaking? Thank you for your time!

EDIT: I understood why I get this error, because my data is already an object and there is no need to use <code>JSON.parse()</code>, but my code is still not working because I get the error:

<blockquote>
 core.js:1671 ERROR TypeError: Cannot read property 'forEach' of
 undefined
</blockquote>

parse [object Object] Angular 6

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想解析一个字符串，并将projectName和poNumber保存到两个变量中。到目前为止，我已经使用了JSON.parse()employees = []JSON.parse(data).array.forEach(element => {    this.employees.push({      projectName: element.projectName,      poNumber

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