blocks|key|1634517|text|您可以使用str.replace和ast.literal_eval将字符串转换为字典，然后重构：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1634518|from+ast+import+literal_eval

x+=+'{"key"=>"Number+of+Contents+in+Sales+Package",+"value"=>"Pack+of+3"}'

d+=+literal_eval(x.replace('=>',+':'))
d+=+{d['key']:+d['value']}

print(d)

{'Number+of+Contents+in+Sales+Package':+'Pack+of+3'}|code-block|syntax|javascript|1634519|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3/library/stdtypes.html#str.replace|1|https://docs.python.org/3/library/ast.html#ast.literal_eval^0|5|B|H|G|5|B|0|H|G|1|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]|$9|12|A|13|1|14]]|E|$]]|$1|F|3|G|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]|S|$5|N|O|P|E|$Q|T]]]]

You can use <a href="https://docs.python.org/3/library/stdtypes.html#str.replace" rel="noreferrer"><code>str.replace</code></a> and then <a href="https://docs.python.org/3/library/ast.html#ast.literal_eval" rel="noreferrer"><code>ast.literal_eval</code></a> to convert your string to a dictionary, then restructure:

<pre><code>from ast import literal_eval

x = '{"key"=&gt;"Number of Contents in Sales Package", "value"=&gt;"Pack of 3"}'

d = literal_eval(x.replace('=&gt;', ':'))
d = {d['key']: d['value']}

print(d)

{'Number of Contents in Sales Package': 'Pack of 3'}
</code></pre>

blocks|key|1600186|text|你可以这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1600187|result+=+dict([k_v.replace('"',+'').split('=>')
+++++++++++++++for+k_v+in+string[1:-1].split(',+')])|code-block|syntax|javascript|1600188|这将要求您的数据以下列形式显示：|1600189|'{key1=>value1,+key2=>value2}'|1600190|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You could do:

<pre><code>result = dict([k_v.replace('"', '').split('=&gt;')
 for k_v in string[1:-1].split(', ')])
</code></pre>

This would require your data to be in the form:

<pre><code>'{key1=&gt;value1, key2=&gt;value2}'
</code></pre>

blocks|key|3562561|text|使用具有多个键值对的示例的re|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3562562|import+re

s+=+"""{"key"=>"Number+of+Contents+in+Sales+Package",+"value"=>"Pack+of+3"},+
++++{"key"=>"Number+of+Contents+in+Sales+Package+2",+"value"=>"Pack+of+5"}"""

pattern+=+re.compile(r'''{"key"=>"(?P<key>.*?)",+"value"=>"(?P<value>.*?)"}''')
dict(pattern.findall(s))|code-block|syntax|javascript|3562563|{“销售包中的内容数量”：“3包”，“销售包2中的内容数”：“5包”}|blockquote|3562564|entityMap^0|D|2|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|S|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|M|7|T|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|O|$]]

using <code>re</code> with an example with more than 1 key-value pair

<pre><code>import re

s = """{"key"=&gt;"Number of Contents in Sales Package", "value"=&gt;"Pack of 3"}, 
 {"key"=&gt;"Number of Contents in Sales Package 2", "value"=&gt;"Pack of 5"}"""

pattern = re.compile(r'''{"key"=&gt;"(?P&lt;key&gt;.*?)", "value"=&gt;"(?P&lt;value&gt;.*?)"}''')
dict(pattern.findall(s))
</code></pre>

<blockquote>
<pre><code>{'Number of Contents in Sales Package': 'Pack of 3',
 'Number of Contents in Sales Package 2': 'Pack of 5'}
</code></pre>
</blockquote>

blocks|key|1600225|text|下面是一种对字符串进行拆分和清理的方法，然后在奇数和偶数列表元素(键为偶数，值为奇数)的切片上使用zip()来生成正在寻找的输出(并且将处理包含多个键值对的字符串，但如果字符串包含嵌套的dicts、list等，则不会很好地处理这些字符串)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1600226|尽管如此，@jpp的答案确实很聪明。|1600227|text+=+'{"key"=>"Number+of+Contents+in+Sales+Package",+"value"=>"Pack+of+3"}'

items+=+[t.split('=>')[1].replace('"',+'')+for+t+in+text[1:-1].split(',')]
result+=+{k:+v+for+k,+v+in+zip(items[::2],+items[1::2])}

print(result)
#+OUTPUT
#+{'Number+of+Contents+in+Sales+Package':+'Pack+of+3'}|code-block|syntax|javascript|1600228|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/users/9209546/jpp^0|1D|5|0|5|4|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@$9|Y|A|Z|1|10]]|E|$]]|$1|H|3|I|5|J|7|11|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

Here is an approach that splits and cleans up the string a bit and then uses dict comprehension with <code>zip()</code> on slices of odd and even list elements (keys are even, values are odd) to generate the output you are looking for (and will work on strings that contain multiple key value pairs but not very well if your strings contain nested dicts, lists, etc).

That said, the answer from <a href="https://stackoverflow.com/users/9209546/jpp">@jpp</a> is really clever.

<pre><code>text = '{"key"=&gt;"Number of Contents in Sales Package", "value"=&gt;"Pack of 3"}'

items = [t.split('=&gt;')[1].replace('"', '') for t in text[1:-1].split(',')]
result = {k: v for k, v in zip(items[::2], items[1::2])}

print(result)
# OUTPUT
# {'Number of Contents in Sales Package': 'Pack of 3'}
</code></pre>

How do I convert a string

<pre><code>{"key"=&gt;"Number of Contents in Sales Package", "value"=&gt;"Pack of 3"}
</code></pre>

into a dictionary like 

<pre><code>{'Number of Contents in Sales Package':'Pack of 3'}?
</code></pre>

The most efficient way to convert a string with keys and values into a python dict

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何转换字符串{"key"=>"Number of Contents in Sales Package", "value"=>"Pack of 3"}变成字典，就像{'Number of Contents in Sales Package':'Pack of 3'}?

问将带键和值的字符串转换为python的最有效方法
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