blocks|key|1832881|text|您可以使用Array.map实现这一点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1832882|​|1832883|var+rule+=+
+{
++"c":+"d",
++"a":+"o",
++"t":+"g",
++"h":+"a",
++"e":+"n",
++"n":+"t",
+}
+
+function+output(str)+{
++return+[...str].map(d+=>+rule[d]).join('')
+}
+
+console.log(output('cat'))|code-block|syntax|javascript|1832884|1832885|entityMap^0|5|9|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|T|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|U|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|O|$]]

<p>You can achieve this using <code>Array.map</code></p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var rule = 
 {
  "c": "d",
  "a": "o",
  "t": "g",
  "h": "a",
  "e": "n",
  "n": "t",
 }
 
 function output(str) {
  return [...str].map(d =&gt; rule[d]).join('')
 }
 
 console.log(output('cat'))</code></pre>
</div>
</div>
</p>


blocks|key|2103095|text|下面的代码返回dog。假设输入字符串的顺序并不重要。tac将返回god|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2103096|var+rule+=+
+{
++"c":+"d",
++"a":+"o",
++"t":+"g",
++"h":+"a",
++"e":+"n",
++"n":+"t",
+};

+const+input+=+"cat";
+let+output+=+"";

+for+(let+value+of+input)+{
++++console.log(rule[value]);
++++output+%2B=+rule[value];
}

console.log(output);+|code-block|syntax|javascript|2103097|您必须处理那些不存在于散列中的键之类的边缘情况。|2103098|entityMap^0|7|3|Q|3|W|3|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|N|$]]

<p>The following code returns <code>dog</code>.  The assumption is that order of input string does not matter.  e.g. <code>tac</code> will return <code>god</code></p>

<pre><code>var rule = 
 {
  "c": "d",
  "a": "o",
  "t": "g",
  "h": "a",
  "e": "n",
  "n": "t",
 };

 const input = "cat";
 let output = "";

 for (let value of input) {
    console.log(rule[value]);
    output += rule[value];
}

console.log(output); 
</code></pre>

<p>You will have to handle the edge cases like those keys not present in the hash.  </p>


blocks|key|4028102|text|您可以尝试以下功能：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4028103|function+returnValue(){+
++var+result+=+"";
++++for(var+i=0;i<arguments.length;i%2B%2B){
++++result%2B=rule[arguments[i]];
}
return+result;
}|code-block|syntax|javascript|4028104|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>You can try the following function :</p>

<pre><code>function returnValue(){ 
  var result = "";
    for(var i=0;i&lt;arguments.length;i++){
    result+=rule[arguments[i]];
}
return result;
}
</code></pre>


blocks|key|2103146|text|使用给定的键创建一个接受obj并遍历它的函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2103147|​|2103148|+var+rule+=+
+{
++"c":+"d",
++"a":+"o",
++"t":+"g",
++"h":+"a",
++"e":+"n",
++"n":+"t",
+}
++++
++++function+keys(obj)
++++{
++++++++var+values+=+[];
++++
++++++++for(var+key+in+obj)
++++++++{
+++++++++++values.push(obj[key]);
++++++++}
++++
++++++++return+values;
++++}

++++console.log(keys(rule));|code-block|syntax|javascript|2103149|2103150|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>Create a function that accepts an obj and iterate through it, using given keys: </p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code> var rule = 
 {
  "c": "d",
  "a": "o",
  "t": "g",
  "h": "a",
  "e": "n",
  "n": "t",
 }
    
    function keys(obj)
    {
        var values = [];
    
        for(var key in obj)
        {
           values.push(obj[key]);
        }
    
        return values;
    }

    console.log(keys(rule));</code></pre>
</div>
</div>
</p>


blocks|key|1838107|text|如果要使用内联代码，可以使用Objec.keys。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1838108|​|1838109|var+rule+=+
{
++"c":+"d",
++"a":+"o",
++"t":+"g",
++"h":+"a",
++"e":+"n",
++"n":+"t"
};
+
var+input+=+'cat';

var+output+=+Object.keys(rule).filter(x+=>+input.indexOf(x)+!==+-1)
+++++++++++++++++++.map(x+=>+rule[x]).join('');

console.log(output);|code-block|syntax|javascript|1838110|1838111|如果输入值为cen，则输出值应为dnt。|1838112|entityMap^0|E|A|0|0|0|0|6|3|G|3|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|U|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|V|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|W|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]]|D|@]|E|$]]|$1|P|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|Q|$]]

<p>If you want to use inline code, you can use <code>Objec.keys</code></p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var rule = 
{
  "c": "d",
  "a": "o",
  "t": "g",
  "h": "a",
  "e": "n",
  "n": "t"
};
 
var input = 'cat';

var output = Object.keys(rule).filter(x =&gt; input.indexOf(x) !== -1)
                   .map(x =&gt; rule[x]).join('');

console.log(output);</code></pre>
</div>
</div>
</p>

<p>If the input value is <code>cen</code>, the output value should be <code>dnt</code>.</p>


blocks|key|2103158|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2103159|var+rule+=+
{
++"c":+"d",
++"a":+"o",
++"t":+"g",
++"h":+"a",
++"e":+"n",
++"n":+"t"
};

let+input+=+'cat';

let+output+=+input.split('').map(key+=>rule[key]).join("");

console.log(`Result:+${output}`);|code-block|syntax|javascript|2103160|2103161|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var rule = 
{
  "c": "d",
  "a": "o",
  "t": "g",
  "h": "a",
  "e": "n",
  "n": "t"
};

let input = 'cat';

let output = input.split('').map(key =&gt;rule[key]).join("");

console.log(`Result: ${output}`);</code></pre>
</div>
</div>
</p>


<p>I created Hashmap array with keys and values:</p>

<pre><code> var rule = 
 {
  "c": "d",
  "a": "o",
  "t": "g",
  "h": "a",
  "e": "n",
  "n": "t",
 }
</code></pre>

<p>Now I want to create function that check above arrays which returns values respective to keys given input.
i.e Suppose if I give input "cat" then it must give output "dog" according to hashmap value.</p>

<p>Note: This can be easily done by using switch case where value of the expression is compared with the values of each case and we return output if there is a match.</p>

<p>But I am looking for more reliable method where we can create function that check above arrays which returns values respective to keys given input. i.e Input = cat then Output = dog </p>


How to check keys and values of Hashmap using function and then return output?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我创建了包含键和值的Hashmap数组： var rule =  {  "c": "d",  "a": "o",  "t": "g",  "h": "a",  "e": "n",  "n": "t", }现在，我想创建一个函数来检查上面的数组，它返回相应的值给给定的输入键。也就是说，假设我输入了"cat“，那么它必须根据hashmap值给出输出”狗“。注意:这可以很容易地使用开关大小写，其中表达式

问如何使用函数检查Hashmap的键和值，然后返回输出？
EN

回答 6

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问如何使用函数检查Hashmap的键和值，然后返回输出？EN

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问如何使用函数检查Hashmap的键和值，然后返回输出？
EN