问使用mysql从数据库获取数据时程序没有响应

EN

Table name - catch_estimation
estiamteid int(11) PRI
centerid int(11)
centername varchar(100)
month int(2)
year int(5)
totalcatch int(11)
totalefforts int(11)
totalafh int(11)
noofgears int(11)
created_date datetime
modified_date datetime

id int(11) NO PRI
estimationid int(11)
centername varchar(50)
gearname varchar(20)
gear_totalefforts int(11)
gear_totalafh int(11)
gear_totalcatch int(11)

     $this->db->select('start.*');
    $this->db->from('gearwise_estimation');
    $this->db->join('catch_estimation', 'gearwise_estimation.estimationid = catch_estimation.estiamteid and year = '.$year);

   foreach($month as $mon):
        $this->db->like('catch_estimation.month',trim($mon));
    endforeach;

     foreach($gear as $gr):
        $this->db->like('gearwise_estimation.gearname',trim($gr));
    endforeach; 

   foreach($centername as $zo):
        $this->db->like('catch_estimation.centerid',trim($zo));
    endforeach;

    $this->db->order_by("catch_estimation.month", "asc");   
    $this->db->order_by("catch_estimation.centername", "asc");

SELECT `start`.* FROM `gearwise_estimation` JOIN `catch_estimation` ON `gearwise_estimation`.`estimationid` = `catch_estimation`.`estiamteid` and `year` = 2018 WHERE catch_estimation.month LIKE '%8%' ESCAPE '!' AND catch_estimation.month LIKE '%9%' ESCAPE '!' AND gearwise_estimation.gearname LIKE '%OBGN%' ESCAPE '!' AND catch_estimation.centerid LIKE '%2%' ESCAPE '!' ORDER BY `catch_estimation`.`month` ASC, `catch_estimation`.`centername` ASC