我做了一个卷曲调用函数,如下所示:
public function curl($url, $post = array()){
$ch = curl_init();
curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.0.12) Gecko/20070508 Firefox/1.5.0.12");
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_COOKIEJAR, $this->ckfile);
curl_setopt($ch, CURLOPT_COOKIEFILE, $this->ckfile);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_HEADER, 1);
// curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,2);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,true);
curl_setopt($ch,CURLOPT_URL, $url);
if(!empty($post)){
$post_string = "";
foreach($post as $key=>$value) { $post_string .= $key.'='.urlencode($value).'&'; }
rtrim($post_string, '&');
curl_setopt($ch,CURLOPT_POST, count($post));
curl_setopt($ch,CURLOPT_POSTFIELDS, $post_string);
}
$res = curl_exec($ch);
if (curl_errno($ch)) {
$this->deliver_responce('201','Couldn\'t send request: ' . curl_error($ch));exit();
}
else {
$resultStatus = curl_getinfo($ch, CURLINFO_HTTP_CODE);
if ($resultStatus == 200) {
//echo "Post Successfully!";
return true;
}
else{
$this->deliver_responce('200','Request failed: HTTP status code: ' . $resultStatus);exit();
}
}
}我必须用URL和数组来调用它,这是我想发布的。当数组有键和值时,它就工作了,但是当我有嵌套数组时,它就不能工作了。它的作用是:
array(
'id'=>1,
'name'=>'apple'
)但不是为
array(
'id'=>5,
'cmd'=>array('password','encrypt','decrypt')
)我认为问题在于:
foreach($post as $key=>$value) { $post_string .= $key.'='.urlencode($value).'&'; }但我不知道该怎么做。
发布于 2019-03-28 07:42:57
要创建一个请求uri,有一个http_build_query函数:
if (!empty($post)) {
curl_setopt($ch,CURLOPT_POST, true);
curl_setopt($ch,CURLOPT_POSTFIELDS, http_build_query($post));
}然而,根据manual (由我强调):
这个参数可以作为一个像‘.’一样的用户编码的字符串传递。或者是以字段名为键,字段数据为值的数组。
因此,您可以尝试直接传递$post数组,而无需将其转换为字符串。
https://stackoverflow.com/questions/55392249
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