我想使用RamdaJS转换这个对象数组。从这个对象数组中
let children = [
{ "name": "Bob", "age": 8, "father": "Mike" },
{ "name": "David", "age": 10, "father": "Mike" },
{ "name": "Amy", "age": 2, "father": "Mike" },
{ "name": "Jeff", "age": 11, "father": "Jack" }
]
到这个对象数组中
let fatherAndKids = [
{
"father": "Mike",
"count" : 3,
"kids": [
{ "name": "Bob", "age": 8 },
{ "name": "David", "age": 10 },
{ "name": "Amy", "age": 2
}
]
},
{
"father": "Jack",
"count" : 1,
"kids": [
{ "name": "Jeff", "age": 11 }
]
}
]
这是我迄今为止所做的。但我没能把父亲的钥匙从孩子们的数组里拿掉
R.pipe(
R.groupBy(R.prop('father')),
R.map(kids => ({
father: R.head(kids)["father"],
count: kids.length,
kids: kids
})),
R.values()
)(children)
发布于 2019-04-03 09:53:54
使用R.applySpec创建对象,并使用R.map和R.dissoc删除“父”属性:
const { pipe, groupBy, prop, applySpec, head, length, map, dissoc, values } = R
const fn = pipe(
groupBy(prop('father')),
map(applySpec({
father: pipe(head, prop('father')),
count: length,
kids: map(dissoc('father'))
})),
values
)
const children = [
{ "name": "Bob", "age": 8, "father": "Mike" },
{ "name": "David", "age": 10, "father": "Mike" },
{ "name": "Amy", "age": 2, "father": "Mike" },
{ "name": "Jeff", "age": 11, "father": "Jack" }
]
const result = fn(children)
console.log(result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.26.1/ramda.js"></script>
https://stackoverflow.com/questions/55492066
复制相似问题