我需要帮助,根据时间范围计算金额。另外,还需要计算出整个月的时间。它是一种基于签入日期的移位事务计算。
转换01/05/2019开始于8:00,结束于02/05/2019 07:59:59这是我的sql。
Select CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120) Date,
SUM(P.Amount - B.TourismTaxAmount) Amount
From Bookings B
Inner Join BookingPayments BP On B.ID = BP.BookingID
Inner Join Payments P On P.ID = BP.PaymentID
Where BookingStatus IN (2,3,4,6) and
IsNull(CheckInDate, DateCheckIn) >= '2019-05-01 08:00:00' and
IsNull(CheckInDate, DateCheckIn) <= '2019-05-02 07:59:59'
group by CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120)
order by CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120)
输出如下:
-------------------------
| Date | Amount |
-------------------------
| 2019-05-01 | 123.00 |
| 2019-05-02 | 456.00 |
-------------------------
这个SQL已经是正确的。但是,如何使输出如下:
-------------------------
| Date | Amount |
-------------------------
| 2019-05-01 | 579.00 |
-------------------------
从上面..。我需要按日期和产出生成每月轮班汇总如下:
-------------------------
| Date | Amount |
-------------------------
| 2019-05-01 | 579.00 |
| 2019-05-02 | 891.00 |
| 2019-05-03 | 721.00 |
| .......... | ..... |
| .......... | ..... |
-------------------------
感谢你的帮助和解决方案。谢谢
发布于 2019-05-06 10:59:47
在进行聚合前8小时减去。您可以最容易地使用所需的日期表达式定义变量(好,列),结果是:
Select convert(char(10), v.dte, 120) as Date,
sum(P.Amount - B.TourismTaxAmount) as Amount
From Bookings B Inner Join
BookingPayments BP
On B.ID = BP.BookingID Inner Join
Payments P
On P.ID = BP.PaymentID cross apply
(values (convert(date, dateadd(hour, -8, coalesce(CheckInDate, DateCheckIn))))
) v(dte)
Where BookingStatus in (2, 3, 4, 6) and
v.dte >= '2019-05-01' and
v.dte < '2019-05-02'
group by v.dte
order by v.dte;
这也很容易扩展到多个日期或几个月。
发布于 2019-05-06 07:00:12
使用按日期排序的窗口函数sum()
Select CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120) Date,
SUM(P.Amount - B.TourismTaxAmount) over(order by CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120)) Amount
From Bookings B
Inner Join BookingPayments BP On B.ID = BP.BookingID
Inner Join Payments P On P.ID = BP.PaymentID
Where BookingStatus IN (2,3,4,6) and
IsNull(CheckInDate, DateCheckIn) >= '2019-05-01 08:00:00' and
IsNull(CheckInDate, DateCheckIn) <= '2019-05-02 07:59:59'
order by CONVERT(char(10), IsNull(CheckInDate, DateCheckIn), 120)
发布于 2019-05-06 07:03:42
对于Server,我将首先创建一个SQL,它以正确的格式将日期列与
Select Year(myDate)*10000+Month(myDate)*100+Day(myDate) as MyNewDate ...
如果您通过WITH在CTE中使用查询,则更容易对其进行分组。
https://stackoverflow.com/questions/56000179
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