blocks|key|2989546|text|var+s+=+"{\r\n++\"Status\":+\"PLANNED\"\r\n}";
var+obj+=+Newtonsoft.Json.JsonConvert.DeserializeObject<StatusModel>(s);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2989547|您定义的模型不正确。你的模型应该是这样的：|unstyled|2989548|public+class+StatusModel
{
++++public+string+Status+{+get;+set;+}
}|2989549|现在，值将被提取到该模型中，您可以访问以下值：|2989550|var+value+=+obj.Status;+//"PLANNED"|2989551|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|P|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$B|C]]|$1|M|3|-4|5|F|7|T|8|@]|9|@]|A|$]]]|N|$]]

<pre><code>var s = "{\r\n \"Status\": \"PLANNED\"\r\n}";
var obj = Newtonsoft.Json.JsonConvert.DeserializeObject&lt;StatusModel&gt;(s);
</code></pre>

The model you have defined is incorrect.
Your model should be like this:

<pre><code>public class StatusModel
{
 public string Status { get; set; }
}
</code></pre>

Now value will be extracted to this model and you can access the value like:

<pre><code>var value = obj.Status; //"PLANNED"
</code></pre>

blocks|key|1084906|text|JSON定义|type|blockquote|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1084907|JSON+(JavaScript对象表示法)是一种轻量级数据交换格式.对人类来说读和写是很容易的。机器很容易解析和生成。它基于JavaScript编程语言的一个子集。|unstyled|1084908|Source|1084909|JSON牛顿软|1084910|Json.NET是一个流行的.NET高性能JSON框架。|1084911|1084912|问题:|1084913|您正在尝试将json反序列化到一个对象，而它正在返回一个null。在我们的上下文中，Deserialization是将json转换为对象的进程。|1084914|var+Result=+Newtonsoft.Json.JsonConvert.DeserializeObject<Model+Class>(String);|CODE|1084915|因此您有一个，因为您知道+json+不对应+Model+，所以要将Json反序列化到模型，这就是为什么Json需要对应于Modele+224，这样才能存储<>E+125JsonE+226的信息。|1084916|您的模型:|1084917|模型可能包含一些不在json中的属性，反之亦然。|1084918|public+class+StatusModel
{
+++public+string+Status+{+get;+set;+}
}|code-block|syntax|javascript|1084919|致以最良好的问候。|1084920|entityMap|0|LINK|mutability|MUTABLE|url|https://www.json.org/|1|https://www.newtonsoft.com/json^0|0|6|0|0|0|6|0|0|0|7|0|0|0|6|1|0|0|3|0|16|F|0|0|27|0|C|6|L|7|1F|4|1O|11|1T|5|2G|5|0|0|5|0|0|O|0|0|0|9|0^^$0|@$1|2|3|4|5|6|7|1J|8|@$9|1K|A|1L|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1M|8|@]|D|@]|E|$]]|$1|I|3|J|5|H|7|1N|8|@]|D|@$9|1O|A|1P|1|1Q]]|E|$]]|$1|K|3|L|5|6|7|1R|8|@$9|1S|A|1T|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|1U|8|@]|D|@]|E|$]]|$1|O|3|J|5|H|7|1V|8|@]|D|@$9|1W|A|1X|1|1Y]]|E|$]]|$1|P|3|Q|5|H|7|1Z|8|@$9|20|A|21|B|C]]|D|@]|E|$]]|$1|R|3|S|5|H|7|22|8|@$9|23|A|24|B|C]]|D|@]|E|$]]|$1|T|3|U|5|H|7|25|8|@$9|26|A|27|B|V]]|D|@]|E|$]]|$1|W|3|X|5|H|7|28|8|@$9|29|A|2A|B|C]|$9|2B|A|2C|B|C]|$9|2D|A|2E|B|C]|$9|2F|A|2G|B|C]|$9|2H|A|2I|B|V]|$9|2J|A|2K|B|V]]|D|@]|E|$]]|$1|Y|3|Z|5|H|7|2L|8|@$9|2M|A|2N|B|C]]|D|@]|E|$]]|$1|10|3|11|5|H|7|2O|8|@$9|2P|A|2Q|B|C]]|D|@]|E|$]]|$1|12|3|13|5|14|7|2R|8|@]|D|@]|E|$15|16]]|$1|17|3|18|5|H|7|2S|8|@$9|2T|A|2U|B|C]]|D|@]|E|$]]|$1|19|3|-4|5|H|7|2V|8|@]|D|@]|E|$]]]|1A|$1B|$5|1C|1D|1E|E|$1F|1G]]|1H|$5|1C|1D|1E|E|$1F|1I]]]]

<blockquote>
 JSON Definition 
</blockquote>

JSON (JavaScript Object Notation) is a lightweight data-interchange format. It is easy for humans to read and write. It is easy for machines to parse and generate. It is based on a subset of the JavaScript Programming Language.

[Source] <a href="https://www.json.org/" rel="nofollow noreferrer">https://www.json.org/</a>

<blockquote>
 JSON Newtonsoft
</blockquote>

Json.NET is a popular high-performance JSON framework for .NET . 

[Source] <a href="https://www.newtonsoft.com/json" rel="nofollow noreferrer">https://www.newtonsoft.com/json</a>

Problem :

Your are trying to deserialize a json to an object and it's returning a null.
In our context a Deserialization is process which transform a json to an object .

<code>var Result= Newtonsoft.Json.JsonConvert.DeserializeObject&lt;Model Class&gt;(String);</code> 

The reason why you have a Null as result is beacause you are deserializing a json to Model, knowing that you Json does not correspond to the Model , this is why the Json need to correspond to the Model so that it can store the information of the Json.

Your Model : 

The model may contain some property that are not in the json and vice versa

<pre><code>public class StatusModel
{
 public string Status { get; set; }
}
</code></pre>

Best Regards .

blocks|key|2989573|text|您可以这样做(使用Newtonsoft+)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2989574|using+System;
using+Newtonsoft.Json;
{
++++public+class+JsonHandler+:+IJsonHandler
++++{
++++++++public+IJsonModel+ReadJson(IJsonModel+model,+StreamReader+reader)
++++++++{
++++++++++++try
++++++++++++{
++++++++++++++++string+jsonFromFile;
++++++++++++++++using+(reader))
++++++++++++++++{
++++++++++++++++++++jsonFromFile+=+reader.ReadToEnd();
++++++++++++++++}

++++++++++++++++status+=+JsonConvert.DeserializeObject<model>(jsonFromFile);
++++++++++++}
++++++++++++catch+(Exception+ex)
++++++++++++{
++++++++++++++++Console.WriteLine(ex.ToString());
++++++++++++}
++++++++++++return+status;
++++++++}
++++}
}|code-block|syntax|javascript|2989575|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can do it like this (using Newtonsoft Framework)

<pre><code>using System;
using Newtonsoft.Json;
{
 public class JsonHandler : IJsonHandler
 {
 public IJsonModel ReadJson(IJsonModel model, StreamReader reader)
 {
 try
 {
 string jsonFromFile;
 using (reader))
 {
 jsonFromFile = reader.ReadToEnd();
 }

 status = JsonConvert.DeserializeObject&lt;model&gt;(jsonFromFile);
 }
 catch (Exception ex)
 {
 Console.WriteLine(ex.ToString());
 }
 return status;
 }
 }
}
</code></pre>

I want to convert json to a specific object. 

<code>String : "{\r\n \"Status\": \"PLANNED\"\r\n}"</code> 

I tried Newtonsoft Json namespace but it is returning a null value.

<code>var Json= Newtonsoft.Json.JsonConvert.DeserializeObject&lt;Model Class&gt;(String )</code>

I want the result in Json format so that I can extract the value from Json as "PLANNED" but I am getting a null.

PS :The model class contains two properties , Name (type of string), Value(type of Object)

How to deserialize Json to an object?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想把json转换成一个特定的对象。String : "{\r\n \"Status\": \"PLANNED\"\r\n}"我尝试了Newtonsoft命名空间，但是它返回了一个空值。var Json= Newtonsoft.Json.JsonConvert.DeserializeObject<Model Clas...

问如何将Json反序列化为对象？
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问如何将Json反序列化为对象？EN