我正在尝试更新D_WINTEL_HEALTH表,下面是我正在使用的查询
UPDATE D_WINTEL_HEALTH A
SET A.HEALTH = 7
FROM D_WINTEL_HEALTH A JOIN D_REPORTER_STATUS B ON A.HOST = B.HOST
WHERE B.ALERTKEY = 'kph_netport_xlzc_ilo' AND
B.SEVERITY = 0 AND
A.HEALTH <> 0 我还尝试了另一个查询:
UPDATE D_WINTEL_HEALTH A SET A.HEALTH = 7
FROM (Select D_WINTEL_HEALTH A JOIN D_REPORTER_STATUS B
ON lower(A.HOST) = lower(B.HOST)) s
WHERE s.ALERTKEY = 'kph_netport_xlzc_ilo' AND s.SEVERITY = 0 AND s.HEALTH <> 0 但这两种方法都返回错误如下:
更新-0行,0.000秒DB2 SQL错误: SQLCODE=-104,SQLSTATE=42601,SQLERRMC=FROM;A SET A.HEALTH =7 ;LEFT_BRACKET,DRIVER=4.15.82
测试了工作良好的select查询,不确定问题是什么,它在IBM中是否不同。
发布于 2019-06-04 08:29:50
使用合并语句代替。
MERGE INTO D_WINTEL_HEALTH A
USING D_REPORTER_STATUS B ON A.HOST = B.HOST
AND B.ALERTKEY = 'kph_netport_xlzc_ilo'
AND B.SEVERITY = 0 AND A.HEALTH <> 0
WHEN MATCHED THEN UPDATE SET HEALTH = 7;发布于 2019-06-04 07:36:00
尝试使用下面的查询。
merge into AD_WINTEL_HEALTH A
using (select SEVERITY, ALERTKEY from D_REPORTER_STATUS) b
ON A.HOST = B.HOST
when matched and B.ALERTKEY = 'kph_netport_xlzc_ilo' and B.SEVERITY = 0 and A.HEALTH <> 0
then update SET A.HEALTH = 7 https://stackoverflow.com/questions/56439096
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