Python似乎将实例属性视为类属性
Python似乎将实例属性视为类属性
提问于 2019-04-16 20:47:52
我想在开始之前说，我对Python和编码是非常陌生的，所以我很可能使用了一些不正确的术语。我正在尝试用Python制作一个基本版本的纸牌游戏“炸开小猫”。我正在尝试从一副牌(没有小猫，你想要避免绘制的牌)到每个类玩家的对象的实例属性"hand“中发牌，然后从牌组中移除这张牌。我的问题是，如果不让实例属性看起来像一个类属性，我就不能让它变成hand。我的代码和结果如下所示：
import random
# Deck without kittens to deal out to the Players
deck_no_kittens = ["Attack","Attack","Attack","Attack","Steal","Steal","Steal","Steal","Favor","Favor","Favor","Favor","See the future","See the future","See the future","See the future","See the future","Alter the future","Alter the future","Shuffle","Shuffle","Shuffle","Shuffle","Skip","Skip","Skip","Skip"]
# Default starting hand for each player
start_hand = ["Defuse"]
class Player():
def __init__(self, hand, alive, knowskitten):
# Hand of each Player
self.hand = hand
# Determines if Player is alive
self.alive = True
# Determines if the Player knows if there is a kitten
self.knowskitten = False
# Defines function that deals to Player while also removing it from deck_no_kittens
def deal(player):
random_index = random.randint(0,len(deck_no_kittens)-1)
card_to_add = deck_no_kittens.pop(random_index)
player.hand.append(card_to_add)
# Initialize objects
computer1 = Player(start_hand, True, False)
computer2 = Player(start_hand, True, False)
user = Player(start_hand, True, False)
# Below is where my issue seems to be - the hand remains the same throughout each deal
# Deals 5 times, alternating, to computer1 and computer2, and prints the hand each time
for i in range(5):
deal(computer1)
print("\ncomputer1 hand is "+str(computer1.hand))
deal(computer2)
print("\ncomputer2 hand is"+str(computer2.hand))
# Prints deck_no_kittens
print("\n"+str(deck_no_kittens))结果：
computer1 hand is ['Defuse', 'Attack']
computer2 hand is['Defuse', 'Attack', 'Skip']
computer1 hand is ['Defuse', 'Attack', 'Skip', 'See the future']
computer2 hand is['Defuse', 'Attack', 'Skip', 'See the future', 'Steal']
computer1 hand is ['Defuse', 'Attack', 'Skip', 'See the future', 'Steal', 'Skip']
computer2 hand is['Defuse', 'Attack', 'Skip', 'See the future', 'Steal', 'Skip', 'Attack']
computer1 hand is ['Defuse', 'Attack', 'Skip', 'See the future', 'Steal', 'Skip', 'Attack', 'Attack']
computer2 hand is['Defuse', 'Attack', 'Skip', 'See the future', 'Steal', 'Skip', 'Attack', 'Attack', 'Shuffle']
computer1 hand is ['Defuse', 'Attack', 'Skip', 'See the future', 'Steal', 'Skip', 'Attack', 'Attack', 'Shuffle', 'Favor']
computer2 hand is['Defuse', 'Attack', 'Skip', 'See the future', 'Steal', 'Skip', 'Attack', 'Attack', 'Shuffle', 'Favor', 'Shuffle']
['Attack', 'Steal', 'Steal', 'Steal', 'Favor', 'Favor', 'Favor', 'See the future', 'See the future', 'See the future', 'See the future', 'Alter the future', 'Alter the future', 'Shuffle', 'Shuffle', 'Skip', 'Skip']我预计每个对象的每一只手都是不同的，但每一笔交易都会增加一只通用的手。如有任何帮助/建议，我们不胜感激。
回答 2
Stack Overflow用户
回答已采纳
发布于 2019-04-16 20:54:45
这里的问题是，您使用相同的“对象”start_hand来创建两个播放器。您可以在内部变量hand中存储对同一列表start_hand的引用。
当你在一个播放器中修改hand时，其他玩家可以看到它。
要解决此问题，请改为创建一个新列表。
self.hand = list(start_hand)Stack Overflow用户
发布于 2019-04-16 20:53:44
两个实例的hand属性都是对同一列表的引用，因此当该列表被修改时，它会同时影响这两个实例。
一种简单的解决方法是将列表复制到类的__init__中
from copy import copy
class Player():
def __init__(self, hand, alive, knowskitten):
# Hand of each Player
self.hand = copy(hand)
# Determines if Player is alive
self.alive = True
# Determines if the Player knows if there is a kitten
self.knowskitten = False页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/55708537
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