AWS Lambda：“参数验证失败”
AWS Lambda：“参数验证失败”
提问于 2019-07-24 10:20:37
我有一个lambda函数，我在其中发送电子邮件，邮件模板作为对象从S3桶中获取。我已经在我的电脑中本地运行了代码，而且我工作得很好。当我将它粘贴到lambda函数中时，它会显示以下错误。
Response:
{
"errorMessage": "Parameter validation failed:\nInvalid type for parameter Message.Body.Html.Data, value: b\"<html>\\n<head></head>\\n<body>\\n <h1>Amazon SES Test (SDK for Python)</h1>\\n <p>This email was sent with\\n <a href='https://aws.amazon.com/ses/'>Amazon SES</a> using the\\n <a href='https://aws.amazon.com/sdk-for-python/'>\\n AWS SDK for Python (Boto)</a>.</p>\\n</body>\\n</html>\", type: <class 'bytes'>, valid types: <class 'str'>",
"errorType": "ParamValidationError",
"stackTrace": [
[
"/var/task/lambda_function.py",
65,
"lambda_handler",
"Source=SENDER,"
],
[
"/var/runtime/botocore/client.py",
314,
"_api_call",
"return self._make_api_call(operation_name, kwargs)"
],
[
"/var/runtime/botocore/client.py",
586,
"_make_api_call",
"api_params, operation_model, context=request_context)"
],
[
"/var/runtime/botocore/client.py",
621,
"_convert_to_request_dict",
"api_params, operation_model)"
],
[
"/var/runtime/botocore/validate.py",
291,
"serialize_to_request",
"raise ParamValidationError(report=report.generate_report())"
]
]
}
Request ID:
"7b13a612-97f6-4278-9825-724abeaa3b51"
Function Logs:
START RequestId: 7b13a612-97f6-4278-9825-724abeaa3b51 Version: $LATEST
Parameter validation failed:
Invalid type for parameter Message.Body.Html.Data, value: b"<html>\n<head></head>\n<body>\n <h1>Amazon SES Test (SDK for Python)</h1>\n <p>This email was sent with\n <a href='https://aws.amazon.com/ses/'>Amazon SES</a> using the\n <a href='https://aws.amazon.com/sdk-for-python/'>\n AWS SDK for Python (Boto)</a>.</p>\n</body>\n</html>", type: <class 'bytes'>, valid types: <class 'str'>: ParamValidationError
Traceback (most recent call last):
File "/var/task/lambda_function.py", line 65, in lambda_handler
Source=SENDER,
File "/var/runtime/botocore/client.py", line 314, in _api_call
return self._make_api_call(operation_name, kwargs)
File "/var/runtime/botocore/client.py", line 586, in _make_api_call
api_params, operation_model, context=request_context)
File "/var/runtime/botocore/client.py", line 621, in _convert_to_request_dict
api_params, operation_model)
File "/var/runtime/botocore/validate.py", line 291, in serialize_to_request
raise ParamValidationError(report=report.generate_report())
botocore.exceptions.ParamValidationError: Parameter validation failed:
Invalid type for parameter Message.Body.Html.Data, value: b"<html>\n<head></head>\n<body>\n <h1>Amazon SES Test (SDK for Python)</h1>\n <p>This email was sent with\n <a href='https://aws.amazon.com/ses/'>Amazon SES</a> using the\n <a href='https://aws.amazon.com/sdk-for-python/'>\n AWS SDK for Python (Boto)</a>.</p>\n</body>\n</html>", type: <class 'bytes'>, valid types: <class 'str'>
END RequestId: 7b13a612-97f6-4278-9825-724abeaa3b51
REPORT RequestId: 7b13a612-97f6-4278-9825-724abeaa3b51 Duration: 1608.47 ms Billed Duration: 1700 ms Memory Size: 128 MB Max Memory Used: 71 MB我检查了从S3桶加载模板时，它在lambda中显示了以下错误。当我在代码中声明BODY_HTML而不从Lambda中的S3获取它时，它工作得很好。下面是我的代码：
import json
import os
import boto3
from botocore.exceptions import ClientError
SENDER = "***********"
RECIPIENT = "************"
AWS_REGION = "us-east-1"
def lambda_handler(event, context):
CHARSET = "UTF-8"
client = boto3.client('ses',aws_access_key_id=******,
aws_secret_access_key=*****,region_name='us-east-1')
s3_client = boto3.client('s3',aws_access_key_id=*********,
aws_secret_access_key=***********,region_name='us-east-1')
s3_response_object = s3_client.get_object(Bucket='my s3 bucket', Key='template.html')
object_content = s3_response_object['Body'].read()
BODY_HTML = object_content
SUBJECT = "sqs-poc-lambda test email"
BODY_TEXT = ("This is a test email for sqs-poc-lambda"
)
try:
#Provide the contents of the email.
response = client.send_email(
Destination={
'ToAddresses': [
RECIPIENT,
],
},
Message={
'Body': {
'Html': {
'Charset': CHARSET,
'Data': BODY_HTML,
},
'Text': {
'Charset': CHARSET,
'Data': BODY_TEXT,
},
},
'Subject': {
'Charset': CHARSET,
'Data': SUBJECT,
},
},
Source=SENDER,
)
except ClientError as e:
print(e.response['Error']['Message'])
else:
print("Email sent! Message ID:"),
print(response['MessageId']))
它应该在Function Logs中成功返回消息ID。在这方面有什么帮助吗？我看不出背后有什么逻辑。
回答 1
Stack Overflow用户
回答已采纳
发布于 2019-07-24 10:55:26
很难相信第二个代码能够工作，因为它包含的错误与第一个错误日志中报告的错误相同。我复制了代码，它也以同样的方式失败了。
可以通过从错误日志读取此消息来发现问题。
参数Message.Body.Html.Data的无效类型，值:B“. "，类型:类字节，有效类型:类'str'：ParamValidationError。
主体应该是字符串类型，但object_content类型
object_content = s3_response['Body'].read()类型为字节。你需要把它转换成字符串。例如BODY_HTML = str(object_content)
重要
不要在代码中存储永久凭据，而不是。
client = boto3.client('ses',aws_access_key_id=******,
aws_secret_access_key=*****,region_name='us-east-1')
s3_client = boto3.client('s3',aws_access_key_id=*********,
aws_secret_access_key=***********,region_name='us-east-1')通过lambda执行角色将权限授予您的Lambda函数。
如果您需要提供对lambda函数的跨帐户访问，则在该角色中包含sts:AssumeRole权限，然后使用通过调用sts:AssumeRole获得的临时凭据。
client = boto3.client(
'ses',
aws_access_key_id=...,
aws_secret_access_key=...,
aws_session_token=... // !!!
)但是，从不在函数代码中存储永久凭据。您确定下次将代码放入某个公共存储库时，您不会忘记用******替换这些值吗？每次？
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/57180610
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