blocks|key|2699277|text|如果allowners数组中的这些ids是Mongoose+ObjectID，则需要在ObjectID对象上使用.equals方法进行比较：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2699278|user._id+=+"5d6caefdbb6f2921f45caf1d";+//even+if+this+is+an+ObjectID+of+mongoose
const+userid+=+user._id;
const+vendors+=+allowners.filter(item+=>+!item.equals(userid));|code-block|syntax|javascript|2699279|另一种方式：在ObjectID上使用toString()+(仅当与字符串-userid相比时才能工作)|BOLD|2699280|vendors+=+allowners.filter(item+=>+item.toString()+!==+userid);|2699281|输出：|2699282|console.info("Filtered+IDs::",+vendors);
Filtered+IDs::+[+5d6caee9bb6f2921f45caf1b,+5d6dfcd6e3b11807944348b8+]|2699283|entityMap|0|LINK|mutability|MUTABLE|url|https://mongodb.github.io/node-mongodb-native/3.3/api/ObjectID.html#equals|1|https://docs.mongodb.com/manual/reference/method/ObjectId.toString/^0|2|9|L|H|1K|7|0|0|0|0|6|I|A|1|0|0|0|3|0|0^^$0|@$1|2|3|4|5|6|7|13|8|@$9|14|A|15|B|C]|$9|16|A|17|B|C]]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|F|3|G|5|H|7|1B|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1C|8|@$9|1D|A|1E|B|M]]|D|@$9|1F|A|1G|1|1H]]|E|$]]|$1|N|3|O|5|H|7|1I|8|@]|D|@]|E|$I|J]]|$1|P|3|Q|5|6|7|1J|8|@$9|1K|A|1L|B|M]]|D|@]|E|$]]|$1|R|3|S|5|H|7|1M|8|@]|D|@]|E|$I|J]]|$1|T|3|-4|5|6|7|1N|8|@]|D|@]|E|$]]]|U|$V|$5|W|X|Y|E|$Z|10]]|11|$5|W|X|Y|E|$Z|12]]]]

If these ids in <code>allowners</code> array are <code>Mongoose ObjectID</code> you'll need to use <a href="https://mongodb.github.io/node-mongodb-native/3.3/api/ObjectID.html#equals" rel="nofollow noreferrer">.equals</a> method on the ObjectID object to compare:

<pre><code>user._id = "5d6caefdbb6f2921f45caf1d"; //even if this is an ObjectID of mongoose
const userid = user._id;
const vendors = allowners.filter(item =&gt; !item.equals(userid));
</code></pre>

Another Way: Using <a href="https://docs.mongodb.com/manual/reference/method/ObjectId.toString/" rel="nofollow noreferrer">toString()</a> on ObjectID (will only work when compared to a string -- userid)

<pre><code>vendors = allowners.filter(item =&gt; item.toString() !== userid);
</code></pre>

Output:

<pre><code>console.info("Filtered IDs::", vendors);
Filtered IDs:: [ 5d6caee9bb6f2921f45caf1b, 5d6dfcd6e3b11807944348b8 ]
</code></pre>

blocks|key|2068786|text|如果数据类型正确匹配，您的结果应该计算到预期的结果。例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2068787|//+Your+array+of+IDs+of+type+{String}
const+allowners+=+['5d6caefdbb6f2921f45caf1d',+'5d6caee9bb6f2921f45caf1b',+'5d6dfcd6e3b11807944348b8',+'5d6caefdbb6f2921f45caf1d'];

//+Your+user+object+with+an+id+of+type+{String}
const+userObject+=+{
++++id:+'5d6caefdbb6f2921f45caf1d'
}

//+Extract+the+id+from+your+user+object,+and+store+in+a+userId+variable+If+you+wish+:-)
const+userId+=+userObject.id;

//+Using+your+code+with+just+changes+in+the+variable+name+(userid+->+userId)
const+vendors+=+allowners.filter((item)+=>+userId+!==+item);

//+The+result
console.log(vendors);+//+[+'5d6caee9bb6f2921f45caf1b',+'5d6dfcd6e3b11807944348b8'+]|code-block|syntax|javascript|2068788|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Your result should compute to the expected result if your data type match properly. For example:

<pre><code>// Your array of IDs of type {String}
const allowners = ['5d6caefdbb6f2921f45caf1d', '5d6caee9bb6f2921f45caf1b', '5d6dfcd6e3b11807944348b8', '5d6caefdbb6f2921f45caf1d'];

// Your user object with an id of type {String}
const userObject = {
 id: '5d6caefdbb6f2921f45caf1d'
}

// Extract the id from your user object, and store in a userId variable If you wish :-)
const userId = userObject.id;

// Using your code with just changes in the variable name (userid -&gt; userId)
const vendors = allowners.filter((item) =&gt; userId !== item);

// The result
console.log(vendors); // [ '5d6caee9bb6f2921f45caf1b', '5d6dfcd6e3b11807944348b8' ]
</code></pre>

i have four object ids in an array . i also have a user id. i would like to remove the user id from array of object ids 

<pre><code>allowners= [ 5d6caefdbb6f2921f45caf1d, 5d6caee9bb6f2921f45caf1b, 
5d6dfcd6e3b11807944348b8, 5d6caefdbb6f2921f45caf1d]
user._id = 5d6caefdbb6f2921f45caf1d
</code></pre>

what i tried 

<pre><code> const userid = user._id
 const vendors = allowners.filter((item) =&gt; userid !== item)
</code></pre>

The result i got is 

<pre><code> vendors = [ 5d6caefdbb6f2921f45caf1d,
 5d6caee9bb6f2921f45caf1b,
 5d6dfcd6e3b11807944348b8,
 5d6caefdbb6f2921f45caf1d ]
</code></pre>

the result i am expecting is

<pre><code> vendors = [ 5d6caee9bb6f2921f45caf1b,5d6dfcd6e3b11807944348b8]
</code></pre>

remove user id from array of object ids

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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数组中有四个对象in。我也有一个用户id。我想从对象id数组中删除用户id。allowners= [ 5d6caefdbb6f2921f45caf1d, 5d6caee9bb6f2921f45caf1b, 5d6dfcd6e3b11807944348b8, 5d6caefdbb6f2921f45caf1d]user._...

问从对象id数组中删除用户id
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