问加法-字符串中数字的减法

EN

k=[int(a)for a in input()if'/'<a<':']
print sum(a-(-1)**a*b for a,b in zip(k,k[1:]+k))

s=>s.map(c=>1/c?r+=p*(p=c*2&2,n=n||c,c):0,n=p=r=0)|r+p*n

s =>                     // given the input array s[]
  s.map(c =>             // for each character c in s[]:
    1 / c ?              //   if c is a digit:
      r +=               //     update r:
        p * (            //       p = either 0 or 2 (always 0 on the 1st iteration)
          p = c * 2 & 2, //       p = 0 if c is even, 2 if c is odd
          n = n || c,    //       if n is still equal to 0 (as an integer), set it to c
          c              //       compute p * c
        )                //     add the result to r
    :                    //   else:
      0,                 //     do nothing
    n = p = r = 0        //   n = first digit, p = previous digit, r = result
  )                      // end of map()
  | r + p * n            // compute the last operation with the 1st digit and add it to r

function(x,y=strtoi(x[x%in%0:9]))sum(c(y[-1],y[1])*y%%2*2)