Uniswap通用路由器-解码执行函数参数
Uniswap通用路由器-解码执行函数参数
提问于 2023-02-07 16:22:43
我使用了这个线程(在ethers.js中解码Uniswap通用路由器事务)中描述的方法，并在这个链接中解码了事务的大部分数据：https://arbiscan.io/tx/0xfd288567b1a9c827a260b28ff0b6b183d256c60881f75c7d86d50a501593c6fd。
Data: 0x3593564c000000000000000000000000000000000000000000000000000000000000006000000000000000000000000000000000000000000000000000000000000000a00000000000000000000000000000000000000000000000000000000063e1579200000000000000000000000000000000000000000000000000000000000000020b000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002000000000000000000000000000000000000000000000000000000000000004000000000000000000000000000000000000000000000000000000000000000a000000000000000000000000000000000000000000000000000000000000000400000000000000000000000000000000000000000000000000000000000000002000000000000000000000000000000000000000000000000002386f26fc1000000000000000000000000000000000000000000000000000000000000000001000000000000000000000000000000000000000000000000000000000000000001000000000000000000000000000000000000000000000000002386f26fc1000000000000000000000000000000000000000000000000000000000000b2c73eba00000000000000000000000000000000000000000000000000000000000000a00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000002b82af49447d8a07e3bd95bd0d56f35241523fbab1002710602eb0d99a5e3e76d1510372c4d2020e12eaea8a000000000000000000000000000000000000000000
ExecuteWithCommandsAndInputs(ExecuteWithCommandsAndInputsCall { commands: Bytes(0x0b00), inputs: [Bytes(0x0000000000000000000000000000000000000000000000000000000000000002000000000000000000000000000000000000000000000000002386f26fc10000), Bytes(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)], deadline: 1675712402 })解码后的数据如下：
- 0x0b00 = execute函数的第一个参数(命令字节)
- 0x0000000000000000000000000000000000000000000000000000000000000002000000000000000000000000000000000000000000000000002386f26fc10000 (二千万0000000000000) =执行函数的第二个参数的第一个输入。这与"WRAP_ETH“所需的数据匹配。
- 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 =这部分让我头疼。基于Uniswap通用路由器技术参考(https://docs.uniswap.org/contracts/universal-router/technical-reference)，应该有5个输入(地址、uint256、uint256、字节、bool)。但是，我将数据分割成64个字符，总共有8行。这是否意味着有8个输入，而不是5个？
回答 1
Ethereum用户
回答已采纳
发布于 2023-02-08 11:45:25
正确的是，V3_SWAP_EXACT_IN本身接受5个参数。
但是第四个参数( path )是一个字节数组，它们还包括费用和一些偏移，以正确构建路径。您可以在他们的V3Path.sol智能合同和V3SwapRouter.sol中查看更多内容。
从您所包含的代码片段判断，您成功地用ethers接口解码了通用函数。我建议您对V3函数也这样做，如下所示：
const abiCoder = new AbiCoder();
decoded = abiCoder.decode(["address", "uint256", "uint256", "bytes", "bool"], inputForFunction);使用它，您可以为V3_SWAP_EXACT_IN函数的每个输入获取相应的参数。基本上，您创建一个迷你界面，只需您需要解码功能。只要你知道输入，它就会给出正确的结果。
运行代码段应该会产生如下结果：
[
'0x0000000000000000000000000000000000000001',
BigNumber { _hex: '0x06ccf946da6cf708', _isBigNumber: true },
BigNumber { _hex: '0x04c72ae4b04a0a42db7f', _isBigNumber: true },
'0xc02aaa39b223fe8d0a0e5c4f27ead9083c756cc200271000c83aecc790e8a4453e5dd3b0b4b3680501a7a7',
false
]现在这里实际上有5个输入(接收者、输入、minOut、路径、fromowner)
下一个挑战是解码路径本身，因为路径仍然是不正确的格式。如果您签出了V3Path.sol，您可以看到不同的地址偏移量，在从路径中提取地址时，您必须考虑到这些费用。
我在我的应用程序中使用了以下函数：
function extractPathFromV3(fullPath, reverse = false) {
const fullPathWithoutHexSymbol = fullPath.substring(2);
let path = [];
let currentAddress = "";
for (let i = 0; i < fullPathWithoutHexSymbol.length; i++) {
currentAddress += fullPathWithoutHexSymbol[i];
if (currentAddress.length === 40) {
path.push('0x' + currentAddress);
i = i + 6;
currentAddress = "";
}
}
if (reverse) {
return path.reverse();
}
return path;
}它从路径中获取每个地址，不包括费用(跳过6个字节)，并且可以反转路径，因为在默认情况下，V3_SWAP_EXACT_OUT路径是反向的，所以这也是必要的。
如果您对单模通用解码器感兴趣，可以在这里查看我的完整实现。
希望它能澄清一点。
页面原文内容由Ethereum提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://ethereum.stackexchange.com/questions/144478
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