未能在CentOS6上生成C.UTF-8区域设置:
# locale
locale: Cannot set LC_CTYPE to default locale: No such file or directory
locale: Cannot set LC_MESSAGES to default locale: No such file or directory
locale: Cannot set LC_ALL to default locale: No such file or directory
LANG=C.UTF-8
LC_CTYPE="C.UTF-8"
LC_NUMERIC="C.UTF-8"
LC_TIME="C.UTF-8"
LC_COLLATE="C.UTF-8"
LC_MONETARY="C.UTF-8"
LC_MESSAGES="C.UTF-8"
LC_PAPER="C.UTF-8"
LC_NAME="C.UTF-8"
LC_ADDRESS="C.UTF-8"
LC_TELEPHONE="C.UTF-8"
LC_MEASUREMENT="C.UTF-8"
LC_IDENTIFICATION="C.UTF-8"
LC_ALL=
# localedef -v -c -i C -f UTF-8 C.UTF-8
cannot open locale definition file `C': No such file or directory
我怎么能在CentOS6上做到这一点?
发布于 2022-07-20 15:50:52
您首先需要提供一个兼容的/usr/share/i18n/locales/C
文件,因为RHEL / CentOS 6.x没有用于C语言环境的文件。
我认为,当RHEL 6是新的,RedHat的建议过去是“使用en_US.utf8
代替”。事实上,在RHEL 6中,en_US
语言环境提供了24小时的时间表示,如果这正是您所追求的。
此外,RHEL 6似乎更喜欢.utf8
表单来指定UTF-8字符编码,而不是.UTF-8
,这是locale -a
和localedef --list-archive
的证明。
https://unix.stackexchange.com/questions/710530
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