blocks|key|6525595|text|APL+(54)|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525596|'The+hypotenuse+of+this+right+triangle+is',3⍕.5*⍨%2B/⎕*2|code-block|syntax|javascript|6525597|测试：|unstyled|6525598|++++++'The+hypotenuse+of+this+right+triangle+is',3⍕.5*⍨%2B/⎕*2
⎕:
++++++9+10
The+hypotenuse+of+this+right+triangle+is+13.454|6525599|解释：|6525600|⎕*2：将输入中的值提高到第二次幂|unordered-list-item|offset|length|style|CODE|6525601|%2B/：取之和|6525602|.5*⍨：将结果提高到0.5次方|6525603|3⍕：四舍五入至小数点3位|entityMap^0|0|0|0|0|0|0|3|0|0|2|0|0|4|0|0|2^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|I|7|13|8|@]|9|@]|A|$]]|$1|J|3|K|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|L|3|M|5|I|7|15|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|16|8|@$Q|17|R|18|S|T]]|9|@]|A|$]]|$1|U|3|V|5|P|7|19|8|@$Q|1A|R|1B|S|T]]|9|@]|A|$]]|$1|W|3|X|5|P|7|1C|8|@$Q|1D|R|1E|S|T]]|9|@]|A|$]]|$1|Y|3|Z|5|P|7|1F|8|@$Q|1G|R|1H|S|T]]|9|@]|A|$]]]|10|$]]

<h2>APL (54)</h2>

<pre><code>'The hypotenuse of this right triangle is',3⍕.5*⍨+/⎕*2
</code></pre>

<p>Test:</p>

<pre><code>      'The hypotenuse of this right triangle is',3⍕.5*⍨+/⎕*2
⎕:
      9 10
The hypotenuse of this right triangle is 13.454
</code></pre>

<p>Explanation:</p>

<ul>
<li><code>⎕*2</code>: raise the values in the input to the second power</li>
<li><code>+/</code>: take the sum</li>
<li><code>.5*⍨</code>: raise the result to the 0.5th power</li>
<li><code>3⍕</code>: round to 3 decimal places</li>
</ul>


blocks|key|6525445|text|Python2.7-76个字符|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525446|print'The+hypotenuse+of+this+right+triangle+is+%25.3f'%25abs(input()%2B1j*input())|code-block|syntax|javascript|6525447|解释|6525448|unstyled|6525449|%7Ca%2Bbi%7C+=+\sqrt{a%5E2+%2B+b%5E2}+=+c+\\+\implies+a%5E2+%2B+b%5E2+=+c%5E2|atomic|offset|length|style|CODE|mathjax|teX|%7Ca%2Bbi%7C+=+\sqrt{a%5E2+%2B+b%5E2}+=+c+\\+\implies+a%5E2+%2B+b%5E2+=+c%5E2|6525450|6525451|关于低音|6525452|6525453|的PJ|6525454|老师：“你能告诉我什么是低音吗？”LJ：“低音，一个简单的问题。如果昨晚有一个高调的派对，你在报纸上读到了，它叫做”高党新闻“。|blockquote|entityMap^0|0|0|0|0|0|1L|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@]|9|@]|A|$]]|$1|I|3|-4|5|J|7|17|8|@]|9|@]|A|$]]|$1|K|3|L|5|M|7|18|8|@$N|19|O|1A|P|Q]]|9|@]|A|$R|-1|S|T]]|$1|U|3|-4|5|J|7|1B|8|@]|9|@]|A|$]]|$1|V|3|W|5|J|7|1C|8|@]|9|@]|A|$]]|$1|X|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|J|7|1E|8|@]|9|@]|A|$]]|$1|10|3|11|5|12|7|1F|8|@]|9|@]|A|$]]]|13|$]]

<h1>Python 2.7 - 76 Characters</h1>
<pre><code>print'The hypotenuse of this right triangle is %.3f'%abs(input()+1j*input())
</code></pre>
<p><strong>Explanation</strong></p>
<p><span class="math-container">$$|a+bi| = \sqrt{a^2 + b^2} = c \\
\implies a^2 + b^2 = c^2$$</span></p>
<p><strong>PJ on hypotenuse</strong></p>
<blockquote>
<p>Teacher: &quot;Can you tell me, what is hypotenuse?&quot;</p>
<p>LJ: &quot;Hypotenuse, an easy question. If there's a high profile party last night, and you
read it in the news paper, its called High Party
News&quot;</p>
</blockquote>


blocks|key|5345801|text|剪裁，46个字符|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|5345802|글坼各갠方終加감半方갾밈乘增貶껠矽녆둥긆둹댆뭴뉖멵댶넠닶눠덆둩댲걲늖덨덂건댦땡닦덬뉒걩댲밀⓶|code-block|syntax|javascript|5345803|期望输入为两个数字(可以是小数！)被一个空间隔开。|unstyled|5345804|这比APL短，尽管不得不使用一些不方便的技巧。|5345805|解释|5345806|글坼+%7C+split+at+space
各+%7C+for+each...
++갠方+%7C+to+the+power+of+two
終
加+%7C+add
감半方+%7C+to+the+power+of+one+half
갾밈乘+%7C+multiply+by+1000
增貶+%7C+increment,+then+decrement+(kludge+for+rounding)
껠矽+%7C+insert+'.'+at+4th-last+character+position
녆둥긆둹댆뭴뉖멵댶넠닶눠덆둩댲걲늖덨덂건댦땡닦덬뉒걩댲밀⓶+%7C+"The+hypotenuse..."|entityMap|0|LINK|mutability|MUTABLE|url|http://esolangs.org/wiki/Sclipting^0|0|2|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|13|8|@]|9|@]|C|$]]|$1|L|3|M|5|K|7|14|8|@]|9|@]|C|$]]|$1|N|3|O|5|6|7|15|8|@]|9|@]|C|$]]|$1|P|3|Q|5|F|7|16|8|@]|9|@]|C|$G|H]]]|R|$S|$5|T|U|V|C|$W|X]]]]

<h1><a href="http://esolangs.org/wiki/Sclipting">Sclipting</a>, 46 characters</h1>

<pre><code>글坼各갠方終加감半方갾밈乘增貶껠矽녆둥긆둹댆뭴뉖멵댶넠닶눠덆둩댲걲늖덨덂건댦땡닦덬뉒걩댲밀⓶
</code></pre>

<p>Expects the input as two numbers (can be fractional!) separated by a space.</p>

<p>This is shorter than APL, despite having to use a few inconvenient tricks.</p>

<h2>Explanation</h2>

<pre><code>글坼 | split at space
各 | for each...
  갠方 | to the power of two
終
加 | add
감半方 | to the power of one half
갾밈乘 | multiply by 1000
增貶 | increment, then decrement (kludge for rounding)
껠矽 | insert '.' at 4th-last character position
녆둥긆둹댆뭴뉖멵댶넠닶눠덆둩댲걲늖덨덂건댦땡닦덬뉒걩댲밀⓶ | "The hypotenuse..."
</code></pre>


blocks|key|5345517|text|dc+54|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345518|切入APL答案的分数！|unstyled|5345519|2%5Er2%5E%2B3kv[The+hypotenuse+of+this+right+triangle+is+]Pp|code-block|syntax|javascript|5345520|测试：|5345521|$+dc
3+4
2%5Er2%5E%2B3kv[The+hypotenuse+of+this+right+triangle+is+]Pp
The+hypotenuse+of+this+right+triangle+is+5.000|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|Q|8|@]|9|@]|A|$H|I]]|$1|J|3|K|5|D|7|R|8|@]|9|@]|A|$]]|$1|L|3|M|5|G|7|S|8|@]|9|@]|A|$H|I]]]|N|$]]

<h1>dc 54</h1>

<p>Tangents the score of the APL answer!</p>

<pre><code>2^r2^+3kv[The hypotenuse of this right triangle is ]Pp
</code></pre>

<p>Test:</p>

<pre><code>$ dc
3 4
2^r2^+3kv[The hypotenuse of this right triangle is ]Pp
The hypotenuse of this right triangle is 5.000
</code></pre>


blocks|key|6525321|text|C，77或99|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525322|77个字符(如果输入可以是函数参数)：|unstyled|6525323|f(a,b){printf("The+hypotenuse+of+this+right+triangle+is+%25.3f\n",hypot(a,b));}|code-block|syntax|javascript|6525324|99如果必须从stdin读取输入：|6525325|a,b;f(){scanf("%25d+%25d",&a,&b);printf("The+hypotenuse+of+this+right+triangle+is+%25.3f\n",hypot(a,b));}|6525326|非常感谢“益民荣”！|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|S|8|@]|9|@]|A|$H|I]]|$1|J|3|K|5|D|7|T|8|@]|9|@]|A|$]]|$1|L|3|M|5|G|7|U|8|@]|9|@]|A|$H|I]]|$1|N|3|O|5|D|7|V|8|@]|9|@]|A|$]]]|P|$]]

<h2>C, 77 or 99</h2>

<p>77 characters if input can just be the function arguments:</p>

<pre><code>f(a,b){printf("The hypotenuse of this right triangle is %.3f\n",hypot(a,b));}
</code></pre>

<p>99 if input must be read from stdin:</p>

<pre><code>a,b;f(){scanf("%d %d",&amp;a,&amp;b);printf("The hypotenuse of this right triangle is %.3f\n",hypot(a,b));}
</code></pre>

<p>A big thanks to @Yimin Rong!</p>


blocks|key|6525675|text|Powershell|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525676|看看我能不能..。|unstyled|6525677|echo+"The+hypotenuse+of+this+right+triangle+is+"+([math]::round([math]::sqrt(([math]::pow(([double](Read-Host+-p+"A")),2)+%2B+[math]::pow(([double](Read-Host+-p+"B")),2))),3))|code-block|syntax|javascript|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|M|8|@]|9|@]|A|$H|I]]]|J|$]]

<p><strong>Powershell</strong></p>

<p>Just to see if i could...</p>

<pre><code>echo "The hypotenuse of this right triangle is " ([math]::round([math]::sqrt(([math]::pow(([double](Read-Host -p "A")),2) + [math]::pow(([double](Read-Host -p "B")),2))),3))
</code></pre>


blocks|key|6525344|text|C%2B%2B+-+90|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525345|void+h(int+a,int+b){printf("The+hypotenuse+of+this+right+triangle+is+%25.3f\n",hypot(a,b));}|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<h1>C++ - 90</h1>
<pre><code>void h(int a,int b){printf(&quot;The hypotenuse of this right triangle is %.3f\n&quot;,hypot(a,b));}
</code></pre>


blocks|key|5345345|text|Python2.7-80字符|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345346|print'The+hypotenuse+of+this+right+triangle+is+%25.3f'%25(input()**2%2Binput()**2)**.5|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<h1>Python 2.7 - 80 chars</h1>

<pre><code>print'The hypotenuse of this right triangle is %.3f'%(input()**2+input()**2)**.5
</code></pre>


blocks|key|6525633|text|Javascript+(97)|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525634|x=prompt;a=x(),b=x();x('The+hypotenuse+of+this+right+triangle+is+'%2BMath.sqrt(a*a%2Bb*b).toFixed(3))|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<p><strong>Javascript (97)</strong></p>

<pre><code>x=prompt;a=x(),b=x();x('The hypotenuse of this right triangle is '+Math.sqrt(a*a+b*b).toFixed(3))
</code></pre>


blocks|key|5345563|text|C，100个字符(比另一个C解决方案强1!)|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345564|一种效率极低的算法。|unstyled|5345565|x;f(a,b){for(;x-a*a-b*b;x=rand());printf("The+hypotenuse+of+this+right+triangle+is+%25.3f",sqrt(x));}|code-block|syntax|javascript|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|M|8|@]|9|@]|A|$H|I]]]|J|$]]

<h2>C, 100 chars (beats the other C solution by 1!)</h2>

<p>A ridiculously inefficient algorithm.</p>

<pre><code>x;f(a,b){for(;x-a*a-b*b;x=rand());printf("The hypotenuse of this right triangle is %.3f",sqrt(x));}
</code></pre>


blocks|key|6525700|text|DELPHI+/+PASCAL|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525701|缩进(157)|unstyled|6525702|6525703|program+p;
{$APPTYPE+CONSOLE}
var+a,b:integer;
begin
+++++readln(a,b);
+++++writeln('the+hypotenuse+of+this+right+triangle+is',sqrt(b*b%2Ba*a):2:3);
end.|code-block|syntax|javascript|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|M|8|@]|9|@]|A|$]]|$1|E|3|-4|5|6|7|N|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|O|8|@]|9|@]|A|$I|J]]]|K|$]]

<h2>DELPHI / PASCAL</h2>
<h3>With indent (157)</h3>
<pre><code>program p;
{$APPTYPE CONSOLE}
var a,b:integer;
begin
     readln(a,b);
     writeln('the hypotenuse of this right triangle is',sqrt(b*b+a*a):2:3);
end.
</code></pre>


blocks|key|5345992|text|Python+2+(79)|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345993|def+p(a,b):print'The+hypotenuse+of+this+right+triangle+is+%25.3d'%25((a*a%2Bb*b)**.5)|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<h1>Python 2 (79)</h1>

<pre><code>def p(a,b):print'The hypotenuse of this right triangle is %.3d'%((a*a+b*b)**.5)
</code></pre>


blocks|key|6525544|text|C|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525545|方法仅(114)|6525546|void+H(double+a,+double+b)
{
++++Console.Write("The+hypotenuse+of+this+right+triangle+is+{0:N3}",+Math.Sqrt(a+*+a+%2B+b+*+b));+
}|code-block|syntax|javascript|6525547|完整程序(171)|6525548|using+System;
class+P
{++++++++
+++static+void+H(double+a,+double+b)
+++{
+++++Console.Write("The+hypotenuse+of+this+right+triangle+is+{0:N3}",+Math.Sqrt(a+*+a+%2B+b+*+b));
+++}++++++++++++++++
+++static+void+Main()
+++{
++++H(3,+4);
+++}
}|6525549|完整程序(不使用方法-+141)|6525550|using+System;class+P{static+void+Main(){double+a=3,b=4;Console.Write("The+hypotenuse+of+this+right+triangle+is+{0:N3}",Math.Sqrt(a*a%2Bb*b));}}|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|T|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|U|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|V|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|W|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|X|8|@]|9|@]|A|$G|H]]]|Q|$]]

<p><strong>C#</strong></p>

<p><strong>Method Only (114)</strong></p>

<pre><code>void H(double a, double b)
{
    Console.Write("The hypotenuse of this right triangle is {0:N3}", Math.Sqrt(a * a + b * b)); 
}
</code></pre>

<p><strong>Complete Program (171)</strong></p>

<pre><code>using System;
class P
{        
   static void H(double a, double b)
   {
     Console.Write("The hypotenuse of this right triangle is {0:N3}", Math.Sqrt(a * a + b * b));
   }                
   static void Main()
   {
    H(3, 4);
   }
}
</code></pre>

<p><strong>Complete Program (without using method - 141)</strong></p>

<pre><code>using System;class P{static void Main(){double a=3,b=4;Console.Write("The hypotenuse of this right triangle is {0:N3}",Math.Sqrt(a*a+b*b));}}
</code></pre>


blocks|key|6525769|text|JavaScript:+83|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525770|i=prompt,'The+hypotenuse+of+this+right+triangle+is+'%2BMath.hypot(i(),i()).toFixed(3)|code-block|syntax|javascript|6525771|目前使用stdin+:D的最短JS实现|unstyled|offset|length|style|CODE|6525772|6525773|只在火狐27.0%2B+(EcmaScript+6)上工作|6525774|JavaScript:+78|6525775|如果我们只使用两个变量(就像很多脚本在这里所做的那样)：|6525776|a=2,b=3,'The+hypotenuse+of+this+right+triangle+is+'%2BMath.hypot(a,b).toFixed(3)|entityMap^0|0|0|4|5|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|I|7|Z|8|@$J|10|K|11|L|M]]|9|@]|A|$]]|$1|N|3|-4|5|I|7|12|8|@]|9|@]|A|$]]|$1|O|3|P|5|I|7|13|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|14|8|@]|9|@]|A|$]]|$1|S|3|T|5|I|7|15|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|16|8|@]|9|@]|A|$E|F]]]|W|$]]

<h2>JavaScript: 83</h2>

<pre><code>i=prompt,'The hypotenuse of this right triangle is '+Math.hypot(i(),i()).toFixed(3)
</code></pre>

<p>Currently the shortest JS implementation using <code>stdin</code> :D<br>
Works only on Firefox 27.0+ (EcmaScript 6)</p>

<h2>JavaScript: 78</h2>

<p>If we can use just two variables (as lot of scripts do here):</p>

<pre><code>a=2,b=3,'The hypotenuse of this right triangle is '+Math.hypot(a,b).toFixed(3)
</code></pre>


blocks|key|5345728|text|dc，55|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345729|3k?d*?d*%2Bv[The+hypotenuse+of+this+right+triangle+is+]Pp|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<h1>dc, 55</h1>
<pre><code>3k?d*?d*+v[The hypotenuse of this right triangle is ]Pp
</code></pre>


blocks|key|6526514|text|OML，57字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|6526515|"The+hypotenuse+of+this+right+triangle+is+"shnhn%2BA6`*N3eD|code-block|syntax|javascript|6526516|在网上试试！|unstyled|6526517|第1部分|6526518|这只是输出字符串。|6526519|"The+hypotenuse+of+this+right+triangle+is+"s|6526520|第2部分|6526521|hnhn%2BA6`*N3eD
hn++++++++++++++take+input+and+square+it
++hn++++++++++++take+another+input+and+square+it
++++%2B+++++++++++add+them
+++++A6`++++++++push+10%5E6
++++++++*+++++++multiply+the+sum+with+that+number
+++++++++N++++++take+integer+square+root
++++++++++3eD+++output+with+three+places+of+precision
++++++++++++++++implicit+output|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/ConorOBrien-Foxx/OML|1|https://tio.run/##y8/N@f9fKSQjVSGjsiC/JDWvtDhVIT9NoSQjs1ihKDM9o0ShpCgzMS89J1UBKKJUnJGXkaftaJag5Wec6vL/v6GCIQA^0|0|3|0|0|0|0|6|1|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@$A|15|B|16|1|17]]|C|$]]|$1|D|3|E|5|F|7|18|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|19|8|@]|9|@$A|1A|B|1B|1|1C]]|C|$]]|$1|L|3|M|5|6|7|1D|8|@]|9|@]|C|$]]|$1|N|3|O|5|K|7|1E|8|@]|9|@]|C|$]]|$1|P|3|Q|5|F|7|1F|8|@]|9|@]|C|$G|H]]|$1|R|3|S|5|6|7|1G|8|@]|9|@]|C|$]]|$1|T|3|U|5|F|7|1H|8|@]|9|@]|C|$G|H]]]|V|$W|$5|X|Y|Z|C|$10|11]]|12|$5|X|Y|Z|C|$10|13]]]]

<h1><a href="https://github.com/ConorOBrien-Foxx/OML" rel="nofollow noreferrer">OML</a>, 57 bytes</h1>

<pre><code>"The hypotenuse of this right triangle is "shnhn+A6`*N3eD
</code></pre>

<p><a href="https://tio.run/##y8/N@f9fKSQjVSGjsiC/JDWvtDhVIT9NoSQjs1ihKDM9o0ShpCgzMS89J1UBKKJUnJGXkaftaJag5Wec6vL/v6GCIQA" rel="nofollow noreferrer" title="OML – Try It Online">Try it online!</a></p>

<h2>Part 1</h2>

<p>This simply outputs the string</p>

<pre><code>"The hypotenuse of this right triangle is "s
</code></pre>

<h2>Part 2</h2>

<pre><code>hnhn+A6`*N3eD
hn              take input and square it
  hn            take another input and square it
    +           add them
     A6`        push 10^6
        *       multiply the sum with that number
         N      take integer square root
          3eD   output with three places of precision
                implicit output
</code></pre>


blocks|key|5346528|text|果冻，32个字符|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|5346529|,²S½ær3µ,“¡ÆC⁷⁺ɱSoṿȤç½?⁶Ẏtḍỵŀ»ṚK|code-block|syntax|javascript|5346530|在网上试试！|unstyled|5346531|可能有一个更好的字符串压缩，使我能够绕开，需要加入空格，但我有困难找到它。|5346532|解释：|5346533|,²S½ær3µ,“...»ṚK++++Example+inputs:+3,+4
,+++++++++++++++++++Pair+the+inputs.+Result:+[3,+4]
+²++++++++++++++++++Square+them.+Result:+[9,+16]
++S+++++++++++++++++Sum+them.+Result:+25
+++½++++++++++++++++Get+the+square+root+of+the+sum.+Result:+5
++++ær3+++++++++++++Round+to+3+decimal+places.+Result:+5
+++++++µ++++++++++++Take+the+result+of+that...+Result:+5
+++++++++“...»+++++++...and++the+compressed+string+Result:+"The+hypotenuse+of+this+right+triangle+is"
++++++++,+++++++++++And+put+them+into+a+pair.+Result:+[5,+"The+hypotenuse+of+this+right+triangle+is"]
++++++++++++++Ṛ+++++Reverse+that.+Result:+["The+hypotenuse+of+this+right+triangle+is",+5]
+++++++++++++++k++++Join+it+with+spaces.+Result:+"The+hypotenuse+of+this+right+triangle+is+5.0"
++++++++++++++++++++Implicit+output.|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/DennisMitchell/jelly|1|https://tio.run/##AUsAtP9qZWxsef//LMKyU8K9w6ZyM8K1LOKAnMKhw4ZD4oG34oG6ybFTb@G5v8ikw6fCvT/igbbhuo504biN4bu1xYDCu@G5mkv///8z/zQ^0|0|2|0|0|0|0|6|1|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|15|8|@]|9|@$A|16|B|17|1|18]]|C|$]]|$1|L|3|M|5|K|7|19|8|@]|9|@]|C|$]]|$1|N|3|O|5|6|7|1A|8|@]|9|@]|C|$]]|$1|P|3|Q|5|F|7|1B|8|@]|9|@]|C|$G|H]]]|R|$S|$5|T|U|V|C|$W|X]]|Y|$5|T|U|V|C|$W|Z]]]]

<h1><a href="https://github.com/DennisMitchell/jelly" rel="nofollow noreferrer">Jelly</a>, 32 characters</h1>

<pre><code>,²S½ær3µ,“¡ÆC⁷⁺ɱSoṿȤç½?⁶Ẏtḍỵŀ»ṚK
</code></pre>

<p><a href="https://tio.run/##AUsAtP9qZWxsef//LMKyU8K9w6ZyM8K1LOKAnMKhw4ZD4oG34oG6ybFTb@G5v8ikw6fCvT/igbbhuo504biN4bu1xYDCu@G5mkv///8z/zQ" rel="nofollow noreferrer" title="Jelly – Try It Online">Try it online!</a></p>

<p>There is probably a better string compression that allows me to get around needing to join with spaces but I was having trouble finding it.</p>

<p><strong>Explanation:</strong></p>

<pre><code>,²S½ær3µ,“...»ṚK    Example inputs: 3, 4
,                   Pair the inputs. Result: [3, 4]
 ²                  Square them. Result: [9, 16]
  S                 Sum them. Result: 25
   ½                Get the square root of the sum. Result: 5
    ær3             Round to 3 decimal places. Result: 5
       µ            Take the result of that... Result: 5
         “...»       ...and  the compressed string Result: "The hypotenuse of this right triangle is"
        ,           And put them into a pair. Result: [5, "The hypotenuse of this right triangle is"]
              Ṛ     Reverse that. Result: ["The hypotenuse of this right triangle is", 5]
               k    Join it with spaces. Result: "The hypotenuse of this right triangle is 5.0"
                    Implicit output.
</code></pre>


blocks|key|5347118|text|JavaScript，70字节|type|header-two|depth|inlineStyleRanges|entityRanges|data|5347119|(a,b)=>'The+hypotenuse+of+the+triangle+is+'%2B((a*a%2Bb*b)**.5).toFixed(3)|code-block|syntax|javascript|5347120|后一个函数将数字舍入小数点后3位。|unstyled|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|I|7|M|8|@]|9|@]|A|$]]]|J|$]]

<h1>JavaScript, 70 bytes</h1>
<pre class="lang-js prettyprint-override"><code>(a,b)=&gt;'The hypotenuse of the triangle is '+((a*a+b*b)**.5).toFixed(3)
</code></pre>
<p>The latter function rounds the number to 3 decimal places.</p>


blocks|key|6527537|text|图2，36\log_{256}(96)\approx+29.632字节|type|header-two|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|6527538|%2BqDFQ$XS)s2lSXreS8x%25twBEZ:x@KUX"mqS*|code-block|syntax|javascript|6527539|在网上试试！|unstyled|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/Seggan/Fig|1|INLINETEX|IMMUTABLE|teX|36\log_{256}(96)\approx|2|https://fig.fly.dev/#WyIrcURGUSRYUylzMmxTWHJlUzh4JXR3QkVaOnhAS1VYXCJtcVMqIiwiWzMsNF0iXQ==^0|3|N|0|2|0|3|N|1|0|0|0|6|2^^$0|@$1|2|3|4|5|6|7|11|8|@$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]|$9|17|A|18|1|19]]|E|$]]|$1|F|3|G|5|H|7|1A|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|M|7|1B|8|@]|D|@$9|1C|A|1D|1|1E]]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]|U|$5|V|Q|W|E|$X|Y]]|Z|$5|P|Q|R|E|$S|10]]]]

<h1><a href="https://github.com/Seggan/Fig" rel="nofollow noreferrer">Fig</a>, <span class="math-container">\$36\log_{256}(96)\approx\$</span> 29.632 bytes</h1>
<pre><code>+qDFQ$XS)s2lSXreS8x%twBEZ:x@KUX&quot;mqS*
</code></pre>
<p><a href="https://fig.fly.dev/#WyIrcURGUSRYUylzMmxTWHJlUzh4JXR3QkVaOnhAS1VYXCJtcVMqIiwiWzMsNF0iXQ==" rel="nofollow noreferrer">Try it online!</a></p>


blocks|key|6525652|text|Scala+(95c)|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525653|import+Math._;val+x=sqrt(pow(a,2)%2Bpow(b,2));f"The+hypotenuse+of+this+right+triangle+is+$x%251.3g"|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<h2>Scala (95c)</h2>
<pre><code>import Math._;val x=sqrt(pow(a,2)+pow(b,2));f&quot;The hypotenuse of this right triangle is $x%1.3g&quot;
</code></pre>


blocks|key|6525721|text|Java+:+223|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525722|+++class+l+{
++++++++public+static+void+main(String[]+args)+{++++++
++++++++++new+l().H(2,4);
++++++++}+++
++++++++void+H(float+a,+float+b)
++++{
++++++++System.out.printf("The+hypotenuse+of+this+right+triangle+is+%25.3f",Math.hypot(a,b));
++++}
++++}|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<h2>Java : 223</h2>
<pre><code>   class l {
        public static void main(String[] args) {      
          new l().H(2,4);
        }   
        void H(float a, float b)
    {
        System.out.printf(&quot;The hypotenuse of this right triangle is %.3f&quot;,Math.hypot(a,b));
    }
    }
</code></pre>


blocks|key|5345646|text|newLISP，103个字符|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345647|(let(a+3.1+b+4)(println"The+hypotenuse+of+this+right+triangle+is+"(round(pow(add(pow+a)(pow+b)).5)-3)))|code-block|syntax|javascript|5345648|未指定的输入方法非常有用.:)|unstyled|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|I|7|M|8|@]|9|@]|A|$]]]|J|$]]

<h2>newLISP, 103 characters</h2>

<pre><code>(let(a 3.1 b 4)(println"The hypotenuse of this right triangle is "(round(pow(add(pow a)(pow b)).5)-3)))
</code></pre>

<p>The unspecified input method helps a lot... :)</p>


blocks|key|6525818|text|Groovy+:78个字符|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525819|a={x,y->printf"The+hypotenuse+of+this+right+triangle+is+%25.3f",Math.hypot(x,y)}|code-block|syntax|javascript|6525820|假设任务只是编写一个方法。如果您需要接受输入参数：|unstyled|6525821|99个字符|6525822|printf"The+hypotenuse+of+this+right+triangle+is+%25.3f",Math.hypot(args[0].toLong(),args[1].toLong())|6525823|我找到了两种同样长度的方法：|6525824|printf"The+hypotenuse+of+this+right+triangle+is+%25.3f",Math.sqrt(args.collect{it.toLong()**2}.sum())|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|I|7|U|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|V|8|@]|9|@]|A|$]]|$1|L|3|M|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|N|3|O|5|I|7|X|8|@]|9|@]|A|$]]|$1|P|3|Q|5|D|7|Y|8|@]|9|@]|A|$E|F]]]|R|$]]

<h2>Groovy : 78 Characters</h2>
<pre><code>a={x,y-&gt;printf&quot;The hypotenuse of this right triangle is %.3f&quot;,Math.hypot(x,y)}
</code></pre>
<p>Assuming the task is just writing a method. If you need to take input parameters:</p>
<p><strong>99 Characters</strong></p>
<pre><code>printf&quot;The hypotenuse of this right triangle is %.3f&quot;,Math.hypot(args[0].toLong(),args[1].toLong())
</code></pre>
<p>I found two ways to it with the same length:</p>
<pre><code>printf&quot;The hypotenuse of this right triangle is %.3f&quot;,Math.sqrt(args.collect{it.toLong()**2}.sum())
</code></pre>


blocks|key|6525958|text|F#，78|type|header-two|depth|inlineStyleRanges|entityRanges|data|6525959|let+f+a+b=sqrt(a*a%2Bb*b)%7C>printf"The+hypotenuse+of+this+right+triangle+is+%25.3f"|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<h1>F#, 78</h1>

<pre><code>let f a b=sqrt(a*a+b*b)|&gt;printf"The hypotenuse of this right triangle is %.3f"
</code></pre>


blocks|key|5345840|text|Java+:+155|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345841|class+A{A(int+x,int+y){System.out.printf("The+hypotenuse+of+this+right+triangle+is+%25.3f",Math.hypot(x,y));}public+static+void+main(String[]s){new+A(1,4);}}|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<p><strong>Java : 155</strong></p>

<pre><code>class A{A(int x,int y){System.out.printf("The hypotenuse of this right triangle is %.3f",Math.hypot(x,y));}public static void main(String[]s){new A(1,4);}}
</code></pre>


blocks|key|5345909|text|Javascript+98个字符/字节|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345910|这是在一个函数中作为浏览器警报实现的。|unstyled|5345911|function+p(a,b){alert('The+hypotenuse+of+this+right+triangle+is:+'%2BMath.sqrt(a*a%2Bb*b).toFixed(3))};|code-block|syntax|javascript|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|M|8|@]|9|@]|A|$H|I]]]|J|$]]

<h1>Javascript 98 characters/bytes</h1>
<p>This is implemented as a browser alert in a function.</p>
<pre><code>function p(a,b){alert('The hypotenuse of this right triangle is: '+Math.sqrt(a*a+b*b).toFixed(3))};
</code></pre>


blocks|key|5345943|text|Fortran+(90)|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345944|read(*,*)a,b;print'(a,f9.3)',"The+hypotenuse+of+this+right+triangle+is+",sqrt(a*a%2Bb*b);end|code-block|syntax|javascript|5345945|使用隐式类型，以便a,b是单精度区域。|unstyled|offset|length|style|CODE|entityMap^0|0|0|9|3^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|I|7|Q|8|@$J|R|K|S|L|M]]|9|@]|A|$]]]|N|$]]

<h1>Fortran (90)</h1>

<pre><code>read(*,*)a,b;print'(a,f9.3)',"The hypotenuse of this right triangle is ",sqrt(a*a+b*b);end
</code></pre>

<p>Uses implicit typing so that <code>a,b</code> are single precision reals.</p>


blocks|key|5345971|text|Javascript，110个字节|type|header-two|depth|inlineStyleRanges|entityRanges|data|5345972|function+h(a,b){return+a/1==a&&b/1==b?'The+hypotenuse+of+this+right+triangle+is+'%2B(a*a%2Bb*b%7C%7C0).toFixed(3):!1;}|code-block|syntax|javascript|5345973|是个怪物！|unstyled|5345974|但是它可以处理NaN和无效数字，如文本、对象、0/0和其他无效数字。|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|I|7|O|8|@]|9|@]|A|$]]|$1|J|3|K|5|I|7|P|8|@]|9|@]|A|$]]]|L|$]]

<h1>Javascript, 110 bytes</h1>
<pre><code>function h(a,b){return a/1==a&amp;&amp;b/1==b?'The hypotenuse of this right triangle is '+(a*a+b*b||0).toFixed(3):!1;}
</code></pre>
<p>It's a monster!!!</p>
<p>But it can handle NaN and invalid numbers, like text, objects, 0/0 and other invalid numbers.</p>


blocks|key|5346027|text|Ruby+2.1%2B+(73个字符)|type|header-two|depth|inlineStyleRanges|entityRanges|data|5346028|f=->a,b{puts"The+hypotenuse+of+this+right+triangle+is+%25.3f"%25(a%2Bb*1i).abs}|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<h3>Ruby 2.1+ (73 characters)</h3>

<pre><code>f=-&gt;a,b{puts"The hypotenuse of this right triangle is %.3f"%(a+b*1i).abs}
</code></pre>


blocks|key|6526162|text|Prolog|type|header-two|depth|inlineStyleRanges|entityRanges|data|6526163|h(A,B):-X+is+A*A%2BB*B,+C+is+sqrt(X),format('The+hypotenuse+of+this+right+triangle+is+~3f',C).|code-block|syntax|javascript|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|I|8|@]|9|@]|A|$E|F]]]|G|$]]

<h1>Prolog</h1>

<pre><code>h(A,B):-X is A*A+B*B, C is sqrt(X),format('The hypotenuse of this right triangle is ~3f',C).
</code></pre>


blocks|key|5346229|text|Fortran+2008+(87个字符)|type|header-two|depth|inlineStyleRanges|entityRanges|data|5346230|基于Fortran+90的解决方案，但现在在Fortran+2008，低值是一个固有的功能。|unstyled|5346231|read(*,*)a,b;print'(a,f9.3)','The+hypotenuse+of+this+right+triangle+is+',hypot(a,b);end|code-block|syntax|javascript|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|M|8|@]|9|@]|A|$H|I]]]|J|$]]

<h1>Fortran 2008 (87 characters)</h1>

<p>Based on the Fortran 90 solution, but now in Fortran 2008, HYPOT is an intrinsic function.</p>

<pre><code>read(*,*)a,b;print'(a,f9.3)','The hypotenuse of this right triangle is ',hypot(a,b);end
</code></pre>


blocks|key|6526373|text|J，56字节|type|header-two|depth|inlineStyleRanges|entityRanges|data|6526374|'The+hypotenuse+of+this+right+triangle+is+'&,@":@(%2B&.*:)|code-block|syntax|javascript|6526375|解释|6526376|J的“下面”动词&.是一个很好的适合这里。它应用一个转换，执行一个动词，然后将反向转换应用于结果。在这种情况下，平方是转换*:，它的反面是平方根，所讨论的动词是加法。所以我们增加了“在”平方变换。剩下的只是对数字进行格式化，然后把它放在句子上。|unstyled|offset|length|style|CODE|6526377|在网上试试！|entityMap|0|LINK|mutability|MUTABLE|url|https://tio.run/##y/r/P81WT0E9JCNVIaOyIL8kNa@0OFUhP02hJCOzWKEoMz2jRKGkKDMxLz0nVQEooq6m46Bk5aChraanZaXJlZqcka9grJCmYPL/PwA^0|0|0|0|8|2|1P|2|0|0|6|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|K|7|11|8|@$L|12|M|13|N|O]|$L|14|M|15|N|O]]|9|@]|A|$]]|$1|P|3|Q|5|K|7|16|8|@]|9|@$L|17|M|18|1|19]]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]]]

<h1>J, 56 bytes</h1>

<pre><code>'The hypotenuse of this right triangle is '&amp;,@":@(+&amp;.*:)
</code></pre>

<h3>explanation</h3>

<p>J's "Under" verb <code>&amp;.</code> is a nice fit here.  It applies a transformation, executes a verb, and then applies the reverse transformation to the result. In this case, squaring is the transformation <code>*:</code>, its reverse is taking the square root, and the verb in question is addition.  So we do addition "under" the square transformation.  The rest is just formatting the number and cat'ing it onto the sentence.</p>

<p><a href="https://tio.run/##y/r/P81WT0E9JCNVIaOyIL8kNa@0OFUhP02hJCOzWKEoMz2jRKGkKDMxLz0nVQEooq6m46Bk5aChraanZaXJlZqcka9grJCmYPL/PwA" rel="nofollow noreferrer" title="J – Try It Online">Try it online!</a></p>


blocks|key|6526617|text|Jq+1.5，80字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|6526618|"The+hypotenuse+of+this+right+triangle+is+\(1e3*pow(map(.*.)%7Cadd;.5)%7Cfloor/1e3)"|code-block|syntax|javascript|6526619|假设输入为[a,b]|unstyled|style|CODE|6526620|在tio.run或jqplay.org在线试用|entityMap|0|LINK|mutability|MUTABLE|url|https://stedolan.github.io/jq/|1|https://tio.run/##FYmxDsIgFAB3v4J0gqZgam06@Btu1YGktGCQh/BIY8K3i3S63N3rU@ahuz670zx2/eXgdDCX5q4V0V8PqFyKisBKUJtIgtk0EgxGus0qUsuD9mpoPez0LT0VrWBZLstNjCyvFiCc62ZNKT/waMDFwrlL1nLjfMIqQe4cElb5Aw|2|https://jqplay.org/s/-jToMkleLM^0|0|6|0|0|0|5|5|0|1|7|1|9|A|2^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|15|8|@$A|16|B|17|L|M]]|9|@]|C|$]]|$1|N|3|O|5|K|7|18|8|@]|9|@$A|19|B|1A|1|1B]|$A|1C|B|1D|1|1E]]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]|W|$5|R|S|T|C|$U|X]]|Y|$5|R|S|T|C|$U|Z]]]]

<h1><a href="https://stedolan.github.io/jq/" rel="nofollow noreferrer">Jq 1.5</a>, 80 bytes</h1>

<pre><code>"The hypotenuse of this right triangle is \(1e3*pow(map(.*.)|add;.5)|floor/1e3)"
</code></pre>

<p>Assumes input is <code>[a,b]</code></p>

<p>Try it online at <a href="https://tio.run/##FYmxDsIgFAB3v4J0gqZgam06@Btu1YGktGCQh/BIY8K3i3S63N3rU@ahuz670zx2/eXgdDCX5q4V0V8PqFyKisBKUJtIgtk0EgxGus0qUsuD9mpoPez0LT0VrWBZLstNjCyvFiCc62ZNKT/waMDFwrlL1nLjfMIqQe4cElb5Aw" rel="nofollow noreferrer" title="jq – Try It Online"><strong>tio.run</strong></a> or <a href="https://jqplay.org/s/-jToMkleLM" rel="nofollow noreferrer"><strong>jqplay.org</strong></a></p>


blocks|key|6526798|text|05AB1E，53个字符|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|6526799|"The+hypotenuse+of+this+right+triangle+is+"%7CnOt₄*ï₄/«|code-block|syntax|javascript|6526800|在网上试试！|unstyled|6526801|我不知道如何压缩05AB1E字符串。:(|6526802|解释：|6526803|"..."%7CnOt₄*ï₄/«

+++++%7C+++++++++++++Push+array+of+inputs.
++++++n++++++++++++Square+them.
+++++++O+++++++++++Get+the+sum.
++++++++t++++++++++Get+the+square+root.
+++++++++₄*++++++++Multiply+by+1000
+++++++++++ï+++++++Convert+to+integer.+This+rounds+it.
++++++++++++₄/+++++Divide+by+1000
"..."+++++++++«++++Append+it+to+the+string.
+++++++++++++++++++Implicit+print.|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/Adriandmen/05AB1E|1|https://tio.run/##MzBNTDJM/f9fKSQjVSGjsiC/JDWvtDhVIT9NoSQjs1ihKDM9o0ShpCgzMS89J1UBKKJUk@df8qipRevweiCpf2j1//@mZnrm5lxGxgA^0|0|6|0|0|0|0|6|1|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|F|7|14|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|15|8|@]|9|@$A|16|B|17|1|18]]|C|$]]|$1|L|3|M|5|K|7|19|8|@]|9|@]|C|$]]|$1|N|3|O|5|6|7|1A|8|@]|9|@]|C|$]]|$1|P|3|Q|5|F|7|1B|8|@]|9|@]|C|$G|H]]]|R|$S|$5|T|U|V|C|$W|X]]|Y|$5|T|U|V|C|$W|Z]]]]

<h1><a href="https://github.com/Adriandmen/05AB1E" rel="nofollow noreferrer">05AB1E</a>, 53 characters</h1>

<pre><code>"The hypotenuse of this right triangle is "|nOt₄*ï₄/«
</code></pre>

<p><a href="https://tio.run/##MzBNTDJM/f9fKSQjVSGjsiC/JDWvtDhVIT9NoSQjs1ihKDM9o0ShpCgzMS89J1UBKKJUk@df8qipRevweiCpf2j1//@mZnrm5lxGxgA" rel="nofollow noreferrer" title="05AB1E – Try It Online">Try it online!</a></p>

<p>I could not figure out how to compress 05AB1E strings. :(</p>

<p><strong>Explanation:</strong></p>

<pre><code>"..."|nOt₄*ï₄/«

     |             Push array of inputs.
      n            Square them.
       O           Get the sum.
        t          Get the square root.
         ₄*        Multiply by 1000
           ï       Convert to integer. This rounds it.
            ₄/     Divide by 1000
"..."         «    Append it to the string.
                   Implicit print.
</code></pre>


blocks|key|5346589|text|Petit+Computer+BASIC，66字节|type|header-two|depth|inlineStyleRanges|entityRanges|data|5346590|INPUT+A,B?"The+hypotenuse+of+this+right+triangle+is+";SQR(A*A%2BB*B)|code-block|syntax|javascript|5346591|PTC在打印时只显示前3位小数。|unstyled|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|I|7|M|8|@]|9|@]|A|$]]]|J|$]]

<h1>Petit Computer BASIC, 66 bytes</h1>
<pre><code>INPUT A,B?&quot;The hypotenuse of this right triangle is &quot;;SQR(A*A+B*B)
</code></pre>
<p>PTC only displays the first 3 decimal places when printing.</p>


blocks|key|6526871|text|[化]双模拟，51字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|6526872|'The+hypotenuse+of+this+right+triangle+is',3⍕%7C0j1⊥⎕|code-block|syntax|javascript|6526873|在网上试试！|unstyled|6526874|0j1⊥⎕：将输入转换为基本i。例如a+b++->++b%2Bai|style|CODE|6526875|%7C：震级|6526876|3⍕：四舍五入至小数点3位|entityMap|0|LINK|mutability|MUTABLE|url|https://www.dyalog.com/|1|https://tio.run/##SyzI0U2pTMzJT///qKM97b96SEaqQkZlQX5Jal5pcapCfppCSUZmsUJRZnpGiUJJUWZiXnpOqkJmsbqO8aPeqTUGWYaPupY@6psK0v4/jctYwYQrjctcwdAAAA^0|0|6|0|0|0|0|6|1|0|0|5|E|1|I|D|0|0|1|0|0|2^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]]|C|$]]|$1|D|3|E|5|F|7|16|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|17|8|@]|9|@$A|18|B|19|1|1A]]|C|$]]|$1|L|3|M|5|K|7|1B|8|@$A|1C|B|1D|N|O]|$A|1E|B|1F|N|O]|$A|1G|B|1H|N|O]]|9|@]|C|$]]|$1|P|3|Q|5|K|7|1I|8|@$A|1J|B|1K|N|O]]|9|@]|C|$]]|$1|R|3|S|5|K|7|1L|8|@$A|1M|B|1N|N|O]]|9|@]|C|$]]]|T|$U|$5|V|W|X|C|$Y|Z]]|10|$5|V|W|X|C|$Y|11]]]]

<h1><a href="https://www.dyalog.com/" rel="nofollow noreferrer">APL (Dyalog)</a>, 51 bytes</h1>



<pre class="lang-apl prettyprint-override"><code>'The hypotenuse of this right triangle is',3⍕|0j1⊥⎕
</code></pre>

<p><a href="https://tio.run/##SyzI0U2pTMzJT///qKM97b96SEaqQkZlQX5Jal5pcapCfppCSUZmsUJRZnpGiUJJUWZiXnpOqkJmsbqO8aPeqTUGWYaPupY@6psK0v4/jctYwYQrjctcwdAAAA" rel="nofollow noreferrer" title="APL (Dyalog) – Try It Online">Try it online!</a></p>

<p><code>0j1⊥⎕</code>: Convert the input into base <code>i</code>. e.g <code>a b  -&gt;  b+ai</code></p>

<p><code>|</code>: Magnitude</p>

<p><code>3⍕</code>: Round to 3 decimal places</p>


blocks|key|5346762|text|斯塔克斯，24+字节数|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|5346763|╬Z.-êû$P¿[▐Ä√#╙δdr▼▀Ö☺┐ç|code-block|syntax|javascript|5346764|运行并调试它|unstyled|5346765|解压，解压，评论，看起来是这样的。|5346766|`1/yyH\fBXNR&X%2B{.SC`p+++print+"The+hypotenuse+of+this+right+triangle+is+"
:J%2B+++++++++++++++++++++square+and+add+the+inputs
%7CQ++++++++++++++++++++++square+root
3j++++++++++++++++++++++round+to+3+places
p+++++++++++++++++++++++print|5346767|运行这个|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/tomtheisen/stax|1|https://github.com/tomtheisen/stax/blob/master/docs/packed.md#packed-stax|2|https://staxlang.xyz/#p=ce5a2e2d88962450a85bde8efb23d3eb64721fdf9901bf87&i=3%2B4%250A4%2B5&a=1&m=2|3|https://staxlang.xyz/#c=%25601%252FyyH%255CfBXNR%2526X%252B%257B.SC%2560p%2509print%2B%2522The%2Bhypotenuse%2Bof%2Bthis%2Bright%2Btriangle%2Bis%2B%2522%250A%253AJ%252B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2509square%2Band%2Badd%2Bthe%2Binputs%250A%257CQ%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2509square%2Broot%250A3j%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2509round%2Bto%2B3%2Bplaces%250Ap%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2B%2509print&i=3%2B4%250A4%2B5&a=1&m=2^0|0|4|0|8|3|1|0|0|0|6|2|0|0|0|0|4|3^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@$A|15|B|16|1|17]|$A|18|B|19|1|1A]]|C|$]]|$1|D|3|E|5|F|7|1B|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|1C|8|@]|9|@$A|1D|B|1E|1|1F]]|C|$]]|$1|L|3|M|5|K|7|1G|8|@]|9|@]|C|$]]|$1|N|3|O|5|F|7|1H|8|@]|9|@]|C|$G|H]]|$1|P|3|Q|5|K|7|1I|8|@]|9|@$A|1J|B|1K|1|1L]]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]|Y|$5|T|U|V|C|$W|Z]]|10|$5|T|U|V|C|$W|11]]|12|$5|T|U|V|C|$W|13]]]]

<h1><a href="https://github.com/tomtheisen/stax" rel="nofollow noreferrer">Stax</a>, 24 <a href="https://github.com/tomtheisen/stax/blob/master/docs/packed.md#packed-stax" rel="nofollow noreferrer">bytes</a></h1>

<pre><code>╬Z.-êû$P¿[▐Ä√#╙δdr▼▀Ö☺┐ç
</code></pre>

<p><a href="https://staxlang.xyz/#p=ce5a2e2d88962450a85bde8efb23d3eb64721fdf9901bf87&amp;i=3+4%0A4+5&amp;a=1&amp;m=2" rel="nofollow noreferrer">Run and debug it</a></p>

<p>Unpacked, ungolfed, and commented, it looks like this.</p>

<pre><code>`1/yyH\fBXNR&amp;X+{.SC`p   print "The hypotenuse of this right triangle is "
:J+                     square and add the inputs
|Q                      square root
3j                      round to 3 places
p                       print
</code></pre>

<p><a href="https://staxlang.xyz/#c=%601%2FyyH%5CfBXNR%26X%2B%7B.SC%60p%09print+%22The+hypotenuse+of+this+right+triangle+is+%22%0A%3AJ%2B++++++++++++++++++%09square+and+add+the+inputs%0A%7CQ+++++++++++++++++++%09square+root%0A3j+++++++++++++++++++%09round+to+3+places%0Ap++++++++++++++++++++%09print&amp;i=3+4%0A4+5&amp;a=1&amp;m=2" rel="nofollow noreferrer">Run this one</a></p>


blocks|key|5346889|text|JavaScript+(Node.js)，76字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|5346890|a=>b=>'The+hypotenuse+of+this+right+triangle+is+'%2BMath.hypot(a,b).toFixed(3)|code-block|syntax|javascript|5346891|在网上试试！|unstyled|5346892|解释|5346893|a+=>+b+=>+//+the+two+arguments+(curry+method)
++++`The+hypotenuse+of+this+right+triangle+is+//+write+the+text+required
++++${Math.hypot(a,b)}`+//+and+use+JS+Math.hypot+function+to+calculate+the+hypotenuse.+|5346894|或者，如果你免除我写这篇文章的痛苦。|5346895|f=Math.hypot+//+is+also+a+valid+answer|entityMap|0|LINK|mutability|MUTABLE|url|https://nodejs.org/|1|https://tio.run/##HcqxDsIgEADQX7mtEJWlrnR0c/MHru0BZwjXwNXo12PT9eW98YNtqbzprchKPfiOfpr9NLwSQfptolT2RiABNHGDyjEpaGUsMRMcMlyeqMmd1@B1tk7lwV9azWj7IqVJJpclmnCAuVvb/w^0|0|K|0|0|0|0|6|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]]|C|$]]|$1|D|3|E|5|F|7|16|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|17|8|@]|9|@$A|18|B|19|1|1A]]|C|$]]|$1|L|3|M|5|6|7|1B|8|@]|9|@]|C|$]]|$1|N|3|O|5|F|7|1C|8|@]|9|@]|C|$G|H]]|$1|P|3|Q|5|K|7|1D|8|@]|9|@]|C|$]]|$1|R|3|S|5|F|7|1E|8|@]|9|@]|C|$G|H]]]|T|$U|$5|V|W|X|C|$Y|Z]]|10|$5|V|W|X|C|$Y|11]]]]

<h1><a href="https://nodejs.org" rel="nofollow noreferrer">JavaScript (Node.js)</a>, 76 bytes</h1>



<pre class="lang-javascript prettyprint-override"><code>a=&gt;b=&gt;'The hypotenuse of this right triangle is '+Math.hypot(a,b).toFixed(3)
</code></pre>

<p><a href="https://tio.run/##HcqxDsIgEADQX7mtEJWlrnR0c/MHru0BZwjXwNXo12PT9eW98YNtqbzprchKPfiOfpr9NLwSQfptolT2RiABNHGDyjEpaGUsMRMcMlyeqMmd1@B1tk7lwV9azWj7IqVJJpclmnCAuVvb/w" rel="nofollow noreferrer" title="JavaScript (Node.js) – Try It Online">Try it online!</a></p>

<h1>Explanation</h1>

<pre class="lang-javascript prettyprint-override"><code>a =&gt; b =&gt; // the two arguments (curry method)
    `The hypotenuse of this right triangle is // write the text required
    ${Math.hypot(a,b)}` // and use JS Math.hypot function to calculate the hypotenuse. 
</code></pre>

<p>Alternately, if the you spare me the pain of writing this text. </p>

<pre class="lang-javascript prettyprint-override"><code>f=Math.hypot // is also a valid answer
</code></pre>


blocks|key|6527105|text|杰夫特，37字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|6527106|`T+hypÇQ«e++È+ght+â0Ø8++`%2BNx²¬x3|code-block|syntax|javascript|6527107|试试看|unstyled|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/ETHproductions/japt|1|https://ethproductions.github.io/japt/?v=1.4.6&code=YFSUIGh5cMdRq2UgjyDIESCdZ2h0IOIw2DggiSBgK054sqx4Mw==&input=OAo4^0|0|3|0|0|0|0|3|1^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]]]

<h1><a href="https://github.com/ETHproductions/japt" rel="nofollow noreferrer">Japt</a>, 37 bytes</h1>
<pre><code>`T hypÇQ«e  È ght â0Ø8  `+Nx²¬x3
</code></pre>
<p><a href="https://ethproductions.github.io/japt/?v=1.4.6&amp;code=YFSUIGh5cMdRq2UgjyDIESCdZ2h0IOIw2DggiSBgK054sqx4Mw==&amp;input=OAo4" rel="nofollow noreferrer">Try it</a></p>


blocks|key|6527143|text|外壳，41字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|6527144|%2B¨ΣŸṗ¤μe₀fı≤ṙ↔ẏ«G¹∫¨J"."msλ‰⁰i*⁰)1000√¤%2B□|code-block|syntax|javascript|6527145|在网上试试！|unstyled|6527146|由于四舍五入，我肯定没有选择合适的语言来完成这项任务.|6527147|%2B++++++++++++++++++++++++++++++The+concatenation+of
+¨...¨+++++++++++++++++++++++++the+compressed+prefix+for+the+output
++++++++++ms+++++++++++++++++++with+the+stringified+elements+of
++++++++++++λ‰⁰+++)1000++++++++the+divmod+by+1000+of
+++++++++++++++++++++++√+++++++the+square+root+of+
+++++++++++++++++++++++++%2B+++++the+sum+of
++++++++++++++++++++++++¤+□++++the+squares+of+the+two+arguments
++++++++++++++++*⁰+++++++++++++times+1000
+++++++++++++++i+++++++++++++++converted+to+an+integer
++++++J"."+++++++++++++++++++++with+a+period+inserted+between+them.|6527148|计算低值值的实际长度只需4个字节，小数点取3位需要17个字节，将The+hypotenuse+of+this+right+triangle+is添加到输出需要20个字节。90.244%25的答案只是格式化！|style|CODE|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/barbuz/Husk|1|https://tio.run/##AVgAp/9odXNr//8rwqjOo8W44bmXwqTOvGXigoBmxLHiiaThuZnihpThuo/Cq0fCueKIq8KoSiIuIm1zzrvigLDigbBpKuKBsCkxMDAw4oiawqQr4pah////NP80^0|0|2|0|0|0|0|6|1|0|0|0|W|14^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]]|C|$]]|$1|D|3|E|5|F|7|16|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|17|8|@]|9|@$A|18|B|19|1|1A]]|C|$]]|$1|L|3|M|5|K|7|1B|8|@]|9|@]|C|$]]|$1|N|3|O|5|F|7|1C|8|@]|9|@]|C|$G|H]]|$1|P|3|Q|5|K|7|1D|8|@$A|1E|B|1F|R|S]]|9|@]|C|$]]]|T|$U|$5|V|W|X|C|$Y|Z]]|10|$5|V|W|X|C|$Y|11]]]]

<h1><a href="https://github.com/barbuz/Husk" rel="nofollow noreferrer">Husk</a>, 41 bytes</h1>

<pre><code>+¨ΣŸṗ¤μe₀fı≤ṙ↔ẏ«G¹∫¨J"."msλ‰⁰i*⁰)1000√¤+□
</code></pre>

<p><a href="https://tio.run/##AVgAp/9odXNr//8rwqjOo8W44bmXwqTOvGXigoBmxLHiiaThuZnihpThuo/Cq0fCueKIq8KoSiIuIm1zzrvigLDigbBpKuKBsCkxMDAw4oiawqQr4pah////NP80" rel="nofollow noreferrer" title="Husk – Try It Online">Try it online!</a></p>

<p>With rounding being involved, I sure didn't pick the right language for the task...</p>

<pre><code>+                              The concatenation of
 ¨...¨                         the compressed prefix for the output
          ms                   with the stringified elements of
            λ‰⁰   )1000        the divmod by 1000 of
                       √       the square root of 
                         +     the sum of
                        ¤ □    the squares of the two arguments
                *⁰             times 1000
               i               converted to an integer
      J"."                     with a period inserted between them.
</code></pre>

<p>Computing the actual length of the hypotenuse only takes four bytes, rounding to three decimal places takes seventeen bytes, and adding on <code>The hypotenuse of this right triangle is</code> to the output takes twenty bytes. 90.244% of this answer is just formatting!</p>


blocks|key|5347040|text|皮斯，51字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|5347041|%2B."+y¢ó³-.n?ãÜPŽýD'9¹i¾5ŠÁ«£¿9WhI‚".R@s%5ERJ2QJ3|code-block|syntax|javascript|5347042|在网上试试！|unstyled|5347043|实际的数学只占8个字节。|5347044|尽管具有内置的字符串压缩功能，但是Pyth在压缩字符串方面非常糟糕。|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/isaacg1/pyth|1|https://tio.run/##AU4Asf9weXRo//8rLiIgeQLCohoOw7PCsy0ubhY/w6PDnFDCjsO9RCc5wrkCacK@NcKKw4HCq8Kjwr85V2hJwoIiLlJAc15SSjJRSjP//zcsMjQ^0|0|2|0|0|0|0|6|1|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|13|8|@]|9|@$A|14|B|15|1|16]]|C|$]]|$1|L|3|M|5|K|7|17|8|@]|9|@]|C|$]]|$1|N|3|O|5|K|7|18|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]|W|$5|R|S|T|C|$U|X]]]]

<h1><a href="https://github.com/isaacg1/pyth" rel="nofollow noreferrer">Pyth</a>, 51 bytes</h1>
<pre><code>+." y&#2;¢&#26;&#14;ó³-.n&#22;?ãÜP&#142;ýD'9¹&#2;i¾5&#138;Á«£¿9WhI&#130;".R@s^RJ2QJ3
</code></pre>
<p><a href="https://tio.run/##AU4Asf9weXRo//8rLiIgeQLCohoOw7PCsy0ubhY/w6PDnFDCjsO9RCc5wrkCacK@NcKKw4HCq8Kjwr85V2hJwoIiLlJAc15SSjJRSjP//zcsMjQ" rel="nofollow noreferrer" title="Pyth – Try It Online">Try it online!</a></p>
<hr />
<p>The actual math only takes up 8 bytes.</p>
<p>Despite having built-in string compression capabilities, Pyth is pretty bad at compressing strings.</p>


blocks|key|6527382|text|果冻，28字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|6527383|ÆḊær3“¡ÆC⁷⁺ɱSoṿȤç½?⁶Ẏtḍỵŀ»,K|code-block|syntax|javascript|6527384|在网上试试！|unstyled|6527385|是如何工作的|6527386|ÆḊær3“¡ÆC⁷⁺ɱSoṿȤç½?⁶Ẏtḍỵŀ»,K+-+Main+link.+Takes+a+pair+[a,+b]+as+input
ÆḊ+++++++++++++++++++++++++++-+Take+the+norm+√(a²%2Bb²)
++ær3++++++++++++++++++++++++-+Round+the+3+decimal+places
+++++“¡ÆC⁷⁺ɱSoṿȤç½?⁶Ẏtḍỵŀ»+++-+"The+hypotenuse+of+this+right+triangle+is"
++++++++++++++++++++++++++,++-+Pair+the+string+with+the+norm
+++++++++++++++++++++++++++K+-+Insert+a+space+between+the+two|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/DennisMitchell/jelly|1|https://tio.run/##AUYAuf9qZWxsef//w4bhuIrDpnIz4oCcwqHDhkPigbfigbrJsVNv4bm/yKTDp8K9P@KBtuG6jnThuI3hu7XFgMK7LEv///8zLCA0^0|0|2|0|0|0|0|6|1|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|13|8|@]|9|@$A|14|B|15|1|16]]|C|$]]|$1|L|3|M|5|6|7|17|8|@]|9|@]|C|$]]|$1|N|3|O|5|F|7|18|8|@]|9|@]|C|$G|H]]]|P|$Q|$5|R|S|T|C|$U|V]]|W|$5|R|S|T|C|$U|X]]]]

<h1><a href="https://github.com/DennisMitchell/jelly" rel="nofollow noreferrer">Jelly</a>, 28 bytes</h1>
<pre><code>ÆḊær3“¡ÆC⁷⁺ɱSoṿȤç½?⁶Ẏtḍỵŀ»,K
</code></pre>
<p><a href="https://tio.run/##AUYAuf9qZWxsef//w4bhuIrDpnIz4oCcwqHDhkPigbfigbrJsVNv4bm/yKTDp8K9P@KBtuG6jnThuI3hu7XFgMK7LEv///8zLCA0" rel="nofollow noreferrer" title="Jelly – Try It Online">Try it online!</a></p>
<h2>How it works</h2>
<pre><code>ÆḊær3“¡ÆC⁷⁺ɱSoṿȤç½?⁶Ẏtḍỵŀ»,K - Main link. Takes a pair [a, b] as input
ÆḊ                           - Take the norm √(a²+b²)
  ær3                        - Round the 3 decimal places
     “¡ÆC⁷⁺ɱSoṿȤç½?⁶Ẏtḍỵŀ»   - &quot;The hypotenuse of this right triangle is&quot;
                          ,  - Pair the string with the norm
                           K - Insert a space between the two
</code></pre>


blocks|key|5347243|text|生锈，72字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|5347244|%7Ca,b%7Cprint!("The+hypotenuse+of+this+right+triangle+is+{:.3}",a.hypot(b))|code-block|syntax|javascript|5347245|在网上试试！|unstyled|5347246|喔，铁锈已经为这个做好了准备。hypot方法计算数字之间的低音值。与通常的"{}"格式替换不同，我使用了"{:.3}"，它强制数字以三位小数的方式显示。|style|CODE|entityMap|0|LINK|mutability|MUTABLE|url|https://www.rust-lang.org/|1|https://tio.run/##HcpBCoQwDEDRvafIuEqhFEGZhTK3mAtUaGzAidLGxaCevYqLv3n8tGUtJPDzLGj2OShQT4L07uyd@ZTD2/FYE4u@sP7GAPG/LhpkywEWAo2cIfEUFTSxl2kOcMveu/asrXfPjaMxZagIW9fYzjVmqM5yAQ^0|0|2|0|0|0|0|6|1|0|F|5|11|4|1G|7^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|F|7|12|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|13|8|@]|9|@$A|14|B|15|1|16]]|C|$]]|$1|L|3|M|5|K|7|17|8|@$A|18|B|19|N|O]|$A|1A|B|1B|N|O]|$A|1C|B|1D|N|O]]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]|W|$5|R|S|T|C|$U|X]]]]

<h1><a href="https://www.rust-lang.org/" rel="nofollow noreferrer">Rust</a>, 72 bytes</h1>

<pre class="lang-rust prettyprint-override"><code>|a,b|print!(&quot;The hypotenuse of this right triangle is {:.3}&quot;,a.hypot(b))
</code></pre>
<p><a href="https://tio.run/##HcpBCoQwDEDRvafIuEqhFEGZhTK3mAtUaGzAidLGxaCevYqLv3n8tGUtJPDzLGj2OShQT4L07uyd@ZTD2/FYE4u@sP7GAPG/LhpkywEWAo2cIfEUFTSxl2kOcMveu/asrXfPjaMxZagIW9fYzjVmqM5yAQ" rel="nofollow noreferrer" title="Rust – Try It Online">Try it online!</a></p>
<p>Woohoo, rust has built-ins for this. The <code>hypot</code> method calculates the hypotenuse between the numbers. Instead of the usual <code>&quot;{}&quot;</code> format substitution I used <code>&quot;{:.3}&quot;</code> which forces the number to display with three decimal places.</p>


blocks|key|6527571|text|去，108个字节|type|header-two|depth|inlineStyleRanges|entityRanges|offset|length|data|6527572|import(."fmt";."math")
func+f(a,b+float64){Printf("The+hypotenuse+of+the+triangle+is+%25.3f\n",Sqrt(a*a%2Bb*b))}|code-block|syntax|javascript|6527573|在网上试试！|unstyled|entityMap|0|LINK|mutability|MUTABLE|url|https://go.dev/|1|https://ato.pxeger.com/run?1=LY7BCoJAGITvPsWyEezaJpgSQS8R1LHLr-yvS-6u6e8hpCfpIkG3Xqi3yczTMMPwzTyehR_eNeQXKDSzYNyrI1zvPpWxtW9IRBwt8X3ELVDJZYCdyxkKUBnDygNtU9kfGuMIBT-VmpW32pN2XauZR0ZjQo0BV1SamZYtowTPjqvjdURDCKsszKS8z5uLCf47IWQfoIhVPA6KRKVychsZzNVh-OsX^0|0|1|0|0|0|0|6|1^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|K|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]]]

<h1><a href="https://go.dev" rel="nofollow noreferrer">Go</a>, 108 bytes</h1>
<pre class="lang-go prettyprint-override"><code>import(.&quot;fmt&quot;;.&quot;math&quot;)
func f(a,b float64){Printf(&quot;The hypotenuse of the triangle is %.3f\n&quot;,Sqrt(a*a+b*b))}
</code></pre>
<p><a href="https://ato.pxeger.com/run?1=LY7BCoJAGITvPsWyEezaJpgSQS8R1LHLr-yvS-6u6e8hpCfpIkG3Xqi3yczTMMPwzTyehR_eNeQXKDSzYNyrI1zvPpWxtW9IRBwt8X3ELVDJZYCdyxkKUBnDygNtU9kfGuMIBT-VmpW32pN2XauZR0ZjQo0BV1SamZYtowTPjqvjdURDCKsszKS8z5uLCf47IWQfoIhVPA6KRKVychsZzNVh-OsX" rel="nofollow noreferrer">Attempt This Online!</a></p>


blocks|key|5347398|text|图诺+Kj，46+\log_{256}(96)+\approx++37.86字节|type|header-two|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5347399|AO3Zu"The+hypotenuse+of+this+right+triangle+is|code-block|syntax|javascript|5347400|在网上试试！|unstyled|5347401|在这样的挑战中，没有字符串压缩确实会带来伤害。|5347402|解释|5347403|+++++++++++#+Implicit+input
AO+++++++++#+Push+the+hypotenuse+of+the+inputs+(yes,+this+is+a+built-in)
++3Zu++++++#+Round+to+three+decimal+places
+++++"...++#+Push+the+string
+++++++++++#+Flags+join+the+stack+by+spaces
+++++++++++#+Implicit+output|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/Thunno/Thunno|1|INLINETEX|IMMUTABLE|teX|46+\log_{256}(96)+\approx+|2|https://ato.pxeger.com/run?1=m72sJKM0Ly9_WbSSd5ZS7IKlpSVpuhY39Rz9jaNKlUIyUhUyKgvyS1LzSotTFfLTFEoyMosVijLTM0oUSooyE_PSc1IVMoshuqCaFyw25jKBMAE^0|3|2|6|Q|0|2|0|6|Q|1|0|0|0|6|2|0|0|0^^$0|@$1|2|3|4|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@$9|1C|A|1D|1|1E]|$9|1F|A|1G|1|1H]]|E|$]]|$1|F|3|G|5|H|7|1I|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|M|7|1J|8|@]|D|@$9|1K|A|1L|1|1M]]|E|$]]|$1|N|3|O|5|M|7|1N|8|@]|D|@]|E|$]]|$1|P|3|Q|5|6|7|1O|8|@]|D|@]|E|$]]|$1|R|3|S|5|H|7|1P|8|@]|D|@]|E|$I|J]]]|T|$U|$5|V|W|X|E|$Y|Z]]|10|$5|11|W|12|E|$13|14]]|15|$5|V|W|X|E|$Y|16]]]]

<h1><a href="https://github.com/Thunno/Thunno" rel="nofollow noreferrer">Thunno</a> <code>Kj</code>, <span class="math-container">\$ 46 \log_{256}(96) \approx \$</span> 37.86 bytes</h1>
<pre><code>AO3Zu&quot;The hypotenuse of this right triangle is
</code></pre>
<p><a href="https://ato.pxeger.com/run?1=m72sJKM0Ly9_WbSSd5ZS7IKlpSVpuhY39Rz9jaNKlUIyUhUyKgvyS1LzSotTFfLTFEoyMosVijLTM0oUSooyE_PSc1IVMoshuqCaFyw25jKBMAE" rel="nofollow noreferrer">Attempt This Online!</a></p>
<p>Not having string compression really hurts in challenges like these.</p>
<h4>Explanation</h4>
<pre><code>           # Implicit input
AO         # Push the hypotenuse of the inputs (yes, this is a built-in)
  3Zu      # Round to three decimal places
     &quot;...  # Push the string
           # Flags join the stack by spaces
           # Implicit output
</code></pre>


<p>Who doesn't love the Pythagorean theorem <span class="math-container">\$a^2+b^2=c^2\$</span>? Write the shortest method you can in any language that takes in value <code>a</code> and <code>b</code> and prints out <code>The hypotenuse of this right triangle is c</code>.  Keep <code>c</code> to only three decimal places.</p>


Shortest method to implement the Pythagorean Theorem

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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谁不喜欢毕达哥拉斯定理a^2+b^2=c^2？用任何接受值a和b并打印出The hypotenuse of this right triangle is c的语言编写最短的方法。将c保持在小数点后的三位。

问用最短法实现毕达哥拉斯定理
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