我看不懂下面的代码片段。我尝试调用异步函数,但收到如下所示的错误。我正在尝试连接到Microsoft SQL Server。请检查代码,并请告诉我这些代码片段是什么。
**SyntaxError: await is only valid in async function**
var express = require('express');
var router = express.Router();
var sql = require('mssql');
async function connectDB(){
const pool = new sql.ConnectionPool(global.config.sqlConfig);
try {
await pool.connect();
console.log('Connected to DATABASE');
return pool;
}
catch(err){
console.log('conn failure');
return err;
}
};
async function executeQuery(req, res){
const DB = await connectDB();
try{
var result = await DB.request()
.query(req).then(function () {
console.log("QUERY PASSED");
console.log(result.recordset);
return result.recordset;
});
}
catch(err){
console.log("ERROR QUERYing DATABASE");
return err;
}
finally{
DB.close();
}
};
router.get('/login', function (req, res) {
var strquery = "select fUserPwd from tblUser where fUserID ='ADMIN'";
console.log(strquery);
const result = await executeQuery(strquery, res);
res.send(result);
});
module.exports = router; 我希望在打开链接时显示记录集。有没有办法解决这个问题?
发布于 2019-04-09 02:14:11
问题出在这条路由上。
router.get('/login',async function (req, res) {
var strquery = "select fUserPwd from tblUser where fUserID ='ADMIN'";
console.log(strquery);
const result = await executeQuery(strquery, res);
res.send(result);
});https://stackoverflow.com/questions/55579208
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