我使用以下sql来计算% total:
SELECT tblTourns_atp.ID_Ti,
Sum([FS_1]/(SELECT Sum(FSOF_1)
FROM stat_atp
WHERE stat_atp.ID_T = tblTourns_atp.ID_T)) AS S1_IP
FROM stat_atp
INNER JOIN tblTourns_atp ON stat_atp.ID_T = tblTourns_atp.ID_T
GROUP BY tblTourns_atp.ID_Ti我得到了“聚合错误”,因为它希望将ID_T字段分组或放在聚合函数中。我读过很多例子,但当有问题的字段是“WHERE”的主题时,这些例子似乎都不适用。
表和输出如下:
+----------+------+--------+--+---------------+-------+--+--------+--------+
| stat_atp | | | | tblTourns_atp | | | Output | |
+----------+------+--------+--+---------------+-------+--+--------+--------+
| ID_T | FS_1 | FSOF_1 | | ID_T | ID_Ti | | ID_Ti | S1_IP |
| 1 | 20 | 40 | | 1 | 1 | | 1 | 31.03% |
| 2 | 30 | 100 | | 2 | 1 | | 2 | 28.57% |
| 3 | 40 | 150 | | 3 | 1 | | 3 | 33.33% |
| 4 | 30 | 100 | | 4 | 2 | | | |
| 5 | 30 | 100 | | 5 | 2 | | | |
| 6 | 40 | 150 | | 6 | 2 | | | |
| 7 | 20 | 40 | | 7 | 3 | | | |
| 8 | 30 | 100 | | 8 | 3 | | | |
| 9 | 40 | 150 | | 9 | 3 | | | |
| 10 | 20 | 40 | | 10 | 3 | | | |
+----------+------+--------+--+---------------+-------+--+--------+--------+发布于 2019-08-30 05:05:40
因为在两个表之间已经有了一个inner join,所以不需要单独的子查询:
select t.id_ti, sum(s.fs_1)/sum(s.fsof_1) as pct
from tbltourns_atp t inner join stat_atp s on t.id_t = s.id_t
group by t.id_tihttps://stackoverflow.com/questions/57716246
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