比较数组中的JavaScript对象时出现问题
比较数组中的JavaScript对象时出现问题
提问于 2020-11-26 00:01:00
我有这两个信息数组。我想解决这个问题：(给定用户名和所需的权限，如果用户具有该权限，则返回true，否则返回false。)
const groups = [
{
id: 1,
name: 'admins',
permissions: ['CREATE', 'DELETE', 'READ', 'WRITE'],
},
{
id: 2,
name: 'readers',
permissions: ['READ'],
},
{
id: 3,
name: 'writers',
permissions: ['WRITE'],
},
{
id: 4,
name: 'managers',
permissions: ['CREATE', 'DELETE'],
}
];
const users = [
{
name: 'john',
groups: [1],
},
{
name: 'mary',
groups: [2, 3],
},
{
name: 'alice',
groups: [2]
},
{
name: 'bob',
groups: [3],
},
{
name: 'eve',
groups: [2, 4],
},
];到目前为止，我写的代码如下：
function userHasPermission(userName, requiredPermission) {
//looping through first array
for (i = 0; i < users.length; i++) {
if (users[i].name === userName) {
// looping through the second array
for (j = 0; j < groups.length; j++) {
//here I don't know how to resolve this comparison, because as far as I understand it, the script has to check if userName is a valid ID inside groups array?
if (users[i].groups.includes(groups[j].id) && (groups[j].permissions.includes(requiredPermission))) {
return true;
} else {
return false;
}
}
}
}
};
userHasPermission("mary", "WRITE");我对Vanilla JavaScript是个新手，我被困在这一点上，任何帮助都将不胜感激！
回答 2
Stack Overflow用户
回答已采纳
发布于 2020-11-26 00:22:20
function userHasPermission(userName, requiredPermission) {
const user = users.find(u => u.name === userName);
let result = false;
user.groups.forEach(id => {
const group = groups.find(g => g.id === id);
result = group.permissions.includes(requiredPermission);
});
return result;
};
userHasPermission("mary", "WRITE");Stack Overflow用户
发布于 2020-11-26 00:10:13
function userHasPermission(userName, requiredPermission) {
//looping through first array
for (i = 0; i < users.length; i++) {
if (users[i].name === userName) {
// looping through the second array
for (j = 0; j < groups.length; j++) {
if (users[i].groups.includes(groups[j].id) && (groups[j].permissions.includes(requiredPermission))) {
return true;
} else {
continue; // don’t return false yet.
}
}
}
}
// only when you’ve checked all possibilities
// still find no match, now you can return definitely
return false;
};基于你的代码，上面的for循环风格是必不可少的。我个人更喜欢功能更强的代码风格。供您参考：
function userHasPermission(userName, requiredPermission) {
const targetUser = users.find(user => user.name === userName);
if (!targetUser) return false;
const userGroups = groups.filter(g => targetUser.groups.includes(g.id));
const permissions = userGroups.flatMap(g => g.permissions);
return permissions.includes(requiredPermission);
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/65008346
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