我试着比较两个列表:
assertThat(actual.getList(), is(Matchers.containsInAnyOrder(expectedList)));
但是想法
java: no suitable method found for assertThat(java.util.List<Agent>,org.hamcrest.Matcher<java.lang.Iterable<? extends model.Agents>>)
method org.junit.Assert.<T>assertThat(T,org.hamcrest.Matcher<T>) is not applicable
(no instance(s) of type variable(s) T exist so that argument type org.hamcrest.Matcher<java.lang.Iterable<? extends model.Agents>> conforms to formal parameter type org.hamcrest.Matcher<T>)
method org.junit.Assert.<T>assertThat(java.lang.String,T,org.hamcrest.Matcher<T>) is not applicable
(cannot instantiate from arguments because actual and formal argument lists differ in length)
我该怎么写呢?
发布于 2015-03-01 11:25:48
List<Long> actual = Arrays.asList(1L, 2L);
List<Long> expected = Arrays.asList(2L, 1L);
assertThat(actual, containsInAnyOrder(expected.toArray()));
@Joe答案的简短版本,没有多余的参数。
发布于 2017-05-18 00:40:44
为了补充@Joe的答案:
Hamcrest为您提供了三种主要方法来匹配列表:
contains
检查是否匹配所有元素,如果列表中有更多或更少的元素,它将失败
containsInAnyOrder
检查是否匹配所有元素,无论列表中的元素是多是少,顺序都无关紧要
hasItems
只检查指定的对象,列表中是否有更多对象并不重要
hasItem
只检查一个对象,列表中是否有多个对象无关紧要
它们都可以接收对象列表并使用equals
方法进行比较,也可以与前面提到的@borjab等其他匹配器混合使用:
assertThat(myList , contains(allOf(hasProperty("id", is(7L)),
hasProperty("name", is("testName1")),
hasProperty("description", is("testDesc1"))),
allOf(hasProperty("id", is(11L)),
hasProperty("name", is("testName2")),
hasProperty("description", is("testDesc2")))));
http://hamcrest.org/JavaHamcrest/javadoc/1.3/org/hamcrest/Matchers.html#contains(E...) http://hamcrest.org/JavaHamcrest/javadoc/1.3/org/hamcrest/Matchers.html#containsInAnyOrder(java.util.Collection) http://hamcrest.org/JavaHamcrest/javadoc/1.3/org/hamcrest/Matchers.html#hasItems(T...)
发布于 2016-07-08 16:57:59
对于现有的Hamcrest库(从v.2.0.0.0开始),您必须在集合上使用Collection.toArray()方法才能使用containsInAnyOrder匹配器。更好的做法是将其作为单独的方法添加到org.hamcrest.Matchers中:
public static <T> org.hamcrest.Matcher<java.lang.Iterable<? extends T>> containsInAnyOrder(Collection<T> items) {
return org.hamcrest.collection.IsIterableContainingInAnyOrder.<T>containsInAnyOrder((T[]) items.toArray());
}
实际上,我最终将这个方法添加到我的自定义测试库中,并使用它来增加我的测试用例的可读性(由于减少了冗长)。
https://stackoverflow.com/questions/21624592
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