blocks|key|835604|text|看起来不错。至少如果我们相信这个资源的话：http://msdn.microsoft.com/en-us/library/aa365247%2528v=vs.85%2529.aspx|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|835605|但我会简化代码的使用。只需查找这些字符中的一个即可表示名称无效，因此：|835606|public+static+boolean+isValidName(String+text)
{
++++Pattern+pattern+=+Pattern.compile("[%5E/./\\:*?\"<>%7C]");
++++return+!pattern.matcher(text).find();
}|code-block|syntax|javascript|835607|这个正则表达式更简单，运行速度也更快。|835608|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/aa365247%2528v=vs.85%2529.aspx^0|L|1U|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|6|7|Y|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|Z|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|C|$]]|$1|M|3|-4|5|6|7|11|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]]]

Looks good. At least if we believe to this resource: <a href="http://msdn.microsoft.com/en-us/library/aa365247%28v=vs.85%29.aspx" rel="nofollow">http://msdn.microsoft.com/en-us/library/aa365247%28v=vs.85%29.aspx</a>

But I'd simplify use the code. It is enough to look for one of these characters to say that the name is invalid, so:

<pre><code>public static boolean isValidName(String text)
{
 Pattern pattern = Pattern.compile("[^/./\\:*?\"&lt;&gt;|]");
 return !pattern.matcher(text).find();
}
</code></pre>

This regex is simpler and will work faster.

blocks|key|620065|text|好吧，我认为下面的方法可以保证一个有效的文件名：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|620066|public+static+boolean+isValidName(String+text)
{
++++try
++++{
++++++++File+file+=+new+File(text);
++++++++file.createNewFile();
++++++++if(file.exists())+file.delete();
++++++++return+true;
++++}
++++catch(Exception+ex){}
++++return+false;
}|code-block|syntax|javascript|620067|你认为如何？|620068|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Well, I think the following method would guarantee a valid file name:

<pre><code>public static boolean isValidName(String text)
{
 try
 {
 File file = new File(text);
 file.createNewFile();
 if(file.exists()) file.delete();
 return true;
 }
 catch(Exception ex){}
 return false;
}
</code></pre>

What do you think?

blocks|key|620112|text|考虑到前面的cited+MSDN+documentation中指定的要求，下面的正则表达式应该可以做得很好：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|620113|public+static+boolean+isValidName(String+text)
{
++++Pattern+pattern+=+Pattern.compile(
++++++++"#+Match+a+valid+Windows+filename+(unspecified+file+system).++++++++++\n"+%2B
++++++++"%5E++++++++++++++++++++++++++++++++#+Anchor+to+start+of+string.++++++++\n"+%2B
++++++++"(?!++++++++++++++++++++++++++++++#+Assert+filename+is+not:+CON,+PRN,+\n"+%2B
++++++++"++(?:++++++++++++++++++++++++++++#+AUX,+NUL,+COM1,+COM2,+COM3,+COM4,+\n"+%2B
++++++++"++++CON%7CPRN%7CAUX%7CNUL%7C+++++++++++++#+COM5,+COM6,+COM7,+COM8,+COM9,+++++\n"+%2B
++++++++"++++COM[1-9]%7CLPT[1-9]++++++++++++#+LPT1,+LPT2,+LPT3,+LPT4,+LPT5,+++++\n"+%2B
++++++++"++)++++++++++++++++++++++++++++++#+LPT6,+LPT7,+LPT8,+and+LPT9...+++++\n"+%2B
++++++++"++(?:\\.[%5E.]*)?++++++++++++++++++#+followed+by+optional+extension++++\n"+%2B
++++++++"++$++++++++++++++++++++++++++++++#+and+end+of+string+++++++++++++++++\n"+%2B
++++++++")++++++++++++++++++++++++++++++++#+End+negative+lookahead+assertion.+\n"+%2B
++++++++"[%5E<>:\"/\\\\%7C?*\\x00-\\x1F]*+++++#+Zero+or+more+valid+filename+chars.\n"+%2B
++++++++"[%5E<>:\"/\\\\%7C?*\\x00-\\x1F\\+.]++#+Last+char+is+not+a+space+or+dot.++\n"+%2B
++++++++"$++++++++++++++++++++++++++++++++#+Anchor+to+end+of+string.++++++++++++",+
++++++++Pattern.CASE_INSENSITIVE+%7C+Pattern.UNICODE_CASE+%7C+Pattern.COMMENTS);
++++Matcher+matcher+=+pattern.matcher(text);
++++boolean+isMatch+=+matcher.matches();
++++return+isMatch;
}|code-block|syntax|javascript|620114|请注意，此正则表达式不会对文件名的长度施加任何限制，但根据平台的不同，实际的文件名可能会被限制为260或32767个字符。|620115|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/aa365247(v=vs.85).aspx#file_and_directory_names)^0|6|O|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

Given the requirements specified in the previously <a href="http://msdn.microsoft.com/en-us/library/aa365247(v=vs.85).aspx#file_and_directory_names" rel="noreferrer">cited MSDN documentation</a>, the following regex should do a pretty good job:

<pre class="lang-cs prettyprint-override"><code>public static boolean isValidName(String text)
{
 Pattern pattern = Pattern.compile(
 "# Match a valid Windows filename (unspecified file system). \n" +
 "^ # Anchor to start of string. \n" +
 "(?! # Assert filename is not: CON, PRN, \n" +
 " (?: # AUX, NUL, COM1, COM2, COM3, COM4, \n" +
 " CON|PRN|AUX|NUL| # COM5, COM6, COM7, COM8, COM9, \n" +
 " COM[1-9]|LPT[1-9] # LPT1, LPT2, LPT3, LPT4, LPT5, \n" +
 " ) # LPT6, LPT7, LPT8, and LPT9... \n" +
 " (?:\\.[^.]*)? # followed by optional extension \n" +
 " $ # and end of string \n" +
 ") # End negative lookahead assertion. \n" +
 "[^&lt;&gt;:\"/\\\\|?*\\x00-\\x1F]* # Zero or more valid filename chars.\n" +
 "[^&lt;&gt;:\"/\\\\|?*\\x00-\\x1F\\ .] # Last char is not a space or dot. \n" +
 "$ # Anchor to end of string. ", 
 Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE | Pattern.COMMENTS);
 Matcher matcher = pattern.matcher(text);
 boolean isMatch = matcher.matches();
 return isMatch;
}
</code></pre>

Note that this regex does not impose any limit on the length of the filename, but a real filename may be limited to 260 or 32767 chars depending on the platform.

blocks|key|835731|text|发布一个新的答案，因为我没有对Eng.Fuad的代码进行评论的代表阈值|type|unstyled|depth|inlineStyleRanges|entityRanges|data|835732|public+static+boolean+isValidName(String+text)
{
++++try
++++{
++++++++File+file+=+new+File(text);
++++++++if(file.createNewFile())+file.delete();
++++++++return+true;
++++}
++++catch(Exception+ex){}
++++return+false;
}|code-block|syntax|javascript|835733|对您的答案所做的小更改，以防止删除预先存在的文件。只有在此方法调用期间创建的文件才会被删除，而返回值是相同的。|835734|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Posting a new answer because I dont have the rep threshold to comment on Eng.Fouad's code

<pre><code>public static boolean isValidName(String text)
{
 try
 {
 File file = new File(text);
 if(file.createNewFile()) file.delete();
 return true;
 }
 catch(Exception ex){}
 return false;
}
</code></pre>

A small change to your answer that prevents deleting a pre-existing file. Files only get deleted if they were created during this method call, while the return value is the same.

blocks|key|620201|text|让File类来做验证怎么样？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|620202|public+static+boolean+isValidName(String+text)+{
++++try+{
++++++++File+file+=+new+File(text);
++++++++return+file.getPath().equals(text);
++++}
++++catch(Exception+ex){}
++++return+false;
}|code-block|syntax|javascript|620203|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

How about letting the File class do your validation?

<pre><code>public static boolean isValidName(String text) {
 try {
 File file = new File(text);
 return file.getPath().equals(text);
 }
 catch(Exception ex){}
 return false;
}
</code></pre>

blocks|key|620283|text|此解决方案只会根据操作系统规则检查给定的文件名是否有效，而不会创建文件。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|620284|在实际创建文件时，您仍然需要处理其他故障(例如，权限不足、驱动器空间不足、安全限制)。|620285|import+java.io.File;
import+java.io.IOException;

public+class+FileUtils+{
++public+static+boolean+isFilenameValid(String+file)+{
++++File+f+=+new+File(file);
++++try+{
+++++++f.getCanonicalPath();
+++++++return+true;
++++}
++++catch+(IOException+e)+{
+++++++return+false;
++++}
++}

++public+static+void+main(String+args[])+throws+Exception+{
++++//+true
++++System.out.println(FileUtils.isFilenameValid("well.txt"));
++++System.out.println(FileUtils.isFilenameValid("well+well.txt"));
++++System.out.println(FileUtils.isFilenameValid(""));

++++//false
++++System.out.println(FileUtils.isFilenameValid("test.T*T"));
++++System.out.println(FileUtils.isFilenameValid("test%7C.TXT"));
++++System.out.println(FileUtils.isFilenameValid("te?st.TXT"));
++++System.out.println(FileUtils.isFilenameValid("con.TXT"));+//+windows
++++System.out.println(FileUtils.isFilenameValid("prn.TXT"));+//+windows
++++}
++}|code-block|syntax|javascript|620286|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This solution will only check if a given filename is valid according to the OS rules without creating a file.

You still need to handle other failures when actually creating the file (e.g. insufficient permissions, lack of drive space, security restrictions). 

<pre><code>import java.io.File;
import java.io.IOException;

public class FileUtils {
 public static boolean isFilenameValid(String file) {
 File f = new File(file);
 try {
 f.getCanonicalPath();
 return true;
 }
 catch (IOException e) {
 return false;
 }
 }

 public static void main(String args[]) throws Exception {
 // true
 System.out.println(FileUtils.isFilenameValid("well.txt"));
 System.out.println(FileUtils.isFilenameValid("well well.txt"));
 System.out.println(FileUtils.isFilenameValid(""));

 //false
 System.out.println(FileUtils.isFilenameValid("test.T*T"));
 System.out.println(FileUtils.isFilenameValid("test|.TXT"));
 System.out.println(FileUtils.isFilenameValid("te?st.TXT"));
 System.out.println(FileUtils.isFilenameValid("con.TXT")); // windows
 System.out.println(FileUtils.isFilenameValid("prn.TXT")); // windows
 }
 }
</code></pre>

<pre><code>public static boolean isValidName(String text)
{
 Pattern pattern = Pattern.compile("^[^/./\\:*?\"&lt;&gt;|]+$");
 Matcher matcher = pattern.matcher(text);
 boolean isMatch = matcher.matches();
 return isMatch;
}
</code></pre>

Does this method guarantee a valid filename on Windows?

Validate a file name on Windows

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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public static boolean isValidName(String text){ Pattern pattern = Pattern.compile("^[^/./\\:*?\"<>|]+$"); Matcher matcher = pattern.matcher(text); bool...

问在Windows上验证文件名
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