如何使SharePoint库中自定义列的按钮仅在文件类型为“文件夹”时可见
如何使SharePoint库中自定义列的按钮仅在文件类型为“文件夹”时可见
提问于 2021-03-19 17:49:42
我有一个自定义的按钮列(Test)
我想设置当文件类型= folder only时显示按钮的条件。下面是我的Json代码，但不幸的是它不能工作。
{
"$schema": "http://columnformatting.sharepointpnp.com/columnFormattingSchema.json",
"elmType": "button",
"customRowAction":
{
"action": "executeFlow",
"actionParams": "{\"id\": \"\"}"
},
"style": {
"border": "none",
"background-color": "transparent",
"color": "#0078d7",
"cursor": "pointer",
"display": "=if( ([$Type] == 'Folder' ), 'block', 'none')"
},
"children": [
{
"elmType": "span",
"attributes": {
"iconName": "FollowUser"
},
"style": {
"padding-right": "6px"
}
},
{
"elmType": "span",
"txtContent": "click to start"
}
]
}
回答 1
Stack Overflow用户
回答已采纳
发布于 2021-03-22 10:31:21
SharePoint库中有一个内容类型列，您可以通过判断该列的值来决定是否显示该按钮。
{
"$schema": "http://columnformatting.sharepointpnp.com/columnFormattingSchema.json",
"elmType": "button",
"customRowAction":
{
"action": "executeFlow",
"actionParams": "{\"id\": \"\"}"
},
"style": {
"border": "none",
"background-color": "transparent",
"color": "#0078d7",
"cursor": "pointer",
"display": "=if( ([$ContentType] == 'Folder' ), 'block', 'none')"
},
"children": [
{
"elmType": "span",
"attributes": {
"iconName": "FollowUser"
},
"style": {
"padding-right": "6px"
}
},
{
"elmType": "span",
"txtContent": "click to start"
}
]
}测试结果：
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原文链接：
https://stackoverflow.com/questions/66705898
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