Web抓取带有请求的JSON文件
Web抓取带有请求的JSON文件
提问于 2020-03-18 01:53:00
我正在尝试使用请求从this site检索时刻表。我让post发送正确的参数，并返回空的HTML框架，但我希望返回json file。
这是我在查看页面时看到的内容，并突出显示了您可以看到我想要检索的文件。
到目前为止，我的代码如下：
url = "https://alilauro-tickets.certusonline.com/"
headers = {'user-agent':'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/62.0.3202.94 Safari/537.3'}
data = "msg=TimeTable&req=%7B%22getAvailability%22%3A%22Y%22%2C%22getBasicPrice%22%3A%22Y%22%2C%22getRouteAnalysis%22%3A%22Y%22%2C%22directOnly%22%3A%22Y%22%2C%22legs%22%3A%224%22%2C%22pax%22%3A1%2C%22origin%22%3A%22BEV%22%2C%22destination%22%3A%22ISC%22%2C%22tripRequest%22%3A%5B%7B%22tripfrom%22%3A%22BEV%22%2C%22tripto%22%3A%22ISC%22%2C%22tripdate%22%3A%222020-03-19%22%2C%22tripleg%22%3A0%7D%2C%7B%22tripfrom%22%3A%22ISC%22%2C%22tripto%22%3A%22BEV%22%2C%22tripdate%22%3A%222020-03-19%22%2C%22tripleg%22%3A1%7D%2C%7B%22tripfrom%22%3A%22BEV%22%2C%22tripto%22%3A%22FOR%22%2C%22tripdate%22%3A%222020-03-19%22%2C%22tripleg%22%3A2%7D%2C%7B%22tripfrom%22%3A%22FOR%22%2C%22tripto%22%3A%22BEV%22%2C%22tripdate%22%3A%222020-03-19%22%2C%22tripleg%22%3A3%7D%5D%7D"
r = requests.post(url, data=data, headers=headers, timeout=20)回答 1
Stack Overflow用户
回答已采纳
发布于 2020-03-18 02:05:17
请求应如下所示：
url = 'https://alilauro-tickets.certusonline.com/php/proxy.php'
headers = {'user-agent':'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/62.0.3202.94 Safari/537.3'}
data = {
'msg': 'TimeTable',
'req': '{"getAvailability":"Y","getBasicPrice":"Y","getRouteAnalysis":"Y","directOnly":"Y","legs":1,"pax":1,"origin":"BEV","destination":"FOR","tripRequest":[{"tripfrom":"BEV","tripto":"FOR","tripdate":"2020-03-18","tripleg":0}]}'
}
response = requests.post(url, headers=headers, data=data)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/60727733
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