在一个快速仪表板上工作,我想从departments_by_dept_emp中删除第二个对象。如何通过Vue最好地实现这一点?
HTML
<tbody id="rows" v-for="result in results">
<tr>
<td>{{ result.first_name }} {{ result.last_name }}</td>
<td v-for="department in result.departments_by_dept_emp">{{ department.dept_name }}</td>
<td>{{ result.hire_date }}</td>
<td>{{ result.birth_date }}</td>
</tr>
</tbody>JavaScript
{
"emp_no": 10010,
"birth_date": "1963-06-01",
"first_name": "Duangkaew",
"last_name": "Piveteau",
"gender": "F",
"hire_date": "1989-08-24",
"departments_by_dept_emp": [
{
"dept_no": "d004",
"dept_name": "Production"
},
{
"dept_no": "d006",
"dept_name": "Quality Management"
}
]
}获取数据的Axios调用存储在一个空数组中
data () {
return {
results: [],
}
}Axios调用
getData() {
this.loading = true
axios.get('https://url', { 'headers': { 'Api-Key': '' } })
.then(response => {
this.results = response.data.resource
this.next = response.data.meta.next
this.loading = false
console.log(response.data.resource)
})
.catch(error => {
console.log(error)
})
}因此,从这个示例中,基本上我只想要生产部门的名称,并从我的表中删除Quality Management。我不相信slice()能做到这一点,因为它只会克隆一个维度。此外,任何像splice()或findIndex这样的东西都会收到错误"Cannot read property '{example}‘of undefined"“
发布于 2019-04-03 06:14:07
如果只想显示数组中的元素,可以传递要显示的元素的索引
var app = new Vue({
el: '#app',
data: {
results: [{
"emp_no": 10010,
"birth_date": "1963-06-01",
"first_name": "Duangkaew",
"last_name": "Piveteau",
"gender": "F",
"hire_date": "1989-08-24",
"departments_by_dept_emp": [
{
"dept_no": "d004",
"dept_name": "Production"
},
{
"dept_no": "d006",
"dept_name": "Quality Management"
}
]
}]
}
})<script src="https://unpkg.com/vue"></script>
<div id="app">
<table>
<tbody id="rows" >
<tr v-for="result in results">
<td>{{ result.first_name }} {{ result.last_name }}</td>
<td>{{ result.departments_by_dept_emp[0].dept_name }}</td>
<td>{{ result.hire_date }}</td>
<td>{{ result.birth_date }}</td>
</tr>
</tbody>
</table>
</div>
希望这对你有用。
https://stackoverflow.com/questions/55483915
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