blocks|key|1357708|text|尝试此脚本|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1357709|Get-ChildItem+-re+-in+*+%7C
++?{+-not+$_.PSIsContainer+}+%7C
++sort+Length+-descending+%7C
++select+-first+10|code-block|syntax|javascript|1357710|细目：|1357711|过滤器块"?{+-not+$_.PSIsContainer+}“用于过滤出目录。sort命令将按大小降序对所有剩余条目进行排序。select子句将只允许前10个通过，因此它将是最大的10个。|offset|length|style|CODE|1357712|entityMap^0|0|0|0|5|Q|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@$K|U|L|V|M|N]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Try this script 

<pre><code>Get-ChildItem -re -in * |
 ?{ -not $_.PSIsContainer } |
 sort Length -descending |
 select -first 10
</code></pre>

Breakdown:

The filter block "<code>?{ -not $_.PSIsContainer }</code>" is meant to filter out directories. The sort command will sort all of the remaining entries by size in descending order. The select clause will only allow the first 10 through so it will be the largest 10.

blocks|key|1572932|text|这可以简化一点，因为目录没有长度：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1572933|gci+.+-r+%7C+sort+Length+-desc+%7C+select+fullname+-f+10|code-block|syntax|javascript|1572934|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This can be simplified a bit because Directories have no length:

<pre><code>gci . -r | sort Length -desc | select fullname -f 10
</code></pre>

blocks|key|1357761|text|如果您关心结果集的一些格式，这里有两个输出更美观的函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1357762|#Function+to+get+the+largest+N+files+on+a+specific+computer's+drive
Function+Get-LargestFilesOnDrive
{
Param([String]$ComputerName+=+$env:COMPUTERNAME,[Char]$Drive+=+'C',+[Int]$Top+=+10)
Get-ChildItem+-Path+\\$ComputerName\$Drive$+-Recurse+%7C+Select-Object+Name,+@{Label='SizeMB';+Expression={"{0:N0}"+-f+($_.Length/1MB)}}+,+DirectoryName,++Length+%7C+Sort-Object+Length+-Descending++%7C+Select-Object+Name,+DirectoryName,+SizeMB+-First+$Top+%7C+Format-Table+-AutoSize+-Wrap++++
}

#Function+to+get+the+largest+N+files+on+a+specific+UNC+path+and+its+sub-paths
Function+Get-LargestFilesOnPath
{
++++Param([String]$Path+=+'.\',+[Int]$Top+=+10)
++++Get-ChildItem+-Path+$Path+-Recurse+%7C+Select-Object+Name,+@{Label='SizeMB';+Expression={"{0:N0}"+-f+($_.Length/1MB)}}+,+DirectoryName,++Length+%7C+Sort-Object+Length+-Descending++%7C+Select-Object+Name,+DirectoryName,+SizeMB+-First+$Top+%7C+Format-Table+-AutoSize+-Wrap
}|code-block|syntax|javascript|1357763|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

If you care about a bit of formatting of the result-set, here are two functions with nicer-looking outputs:

<pre><code>#Function to get the largest N files on a specific computer's drive
Function Get-LargestFilesOnDrive
{
Param([String]$ComputerName = $env:COMPUTERNAME,[Char]$Drive = 'C', [Int]$Top = 10)
Get-ChildItem -Path \\$ComputerName\$Drive$ -Recurse | Select-Object Name, @{Label='SizeMB'; Expression={"{0:N0}" -f ($_.Length/1MB)}} , DirectoryName, Length | Sort-Object Length -Descending | Select-Object Name, DirectoryName, SizeMB -First $Top | Format-Table -AutoSize -Wrap 
}

#Function to get the largest N files on a specific UNC path and its sub-paths
Function Get-LargestFilesOnPath
{
 Param([String]$Path = '.\', [Int]$Top = 10)
 Get-ChildItem -Path $Path -Recurse | Select-Object Name, @{Label='SizeMB'; Expression={"{0:N0}" -f ($_.Length/1MB)}} , DirectoryName, Length | Sort-Object Length -Descending | Select-Object Name, DirectoryName, SizeMB -First $Top | Format-Table -AutoSize -Wrap
}
</code></pre>

blocks|key|1357814|text|我有一个blogged+about+a+similar+problem，我希望在目录和所有子目录(例如整个C:驱动器)中查找最大的文件，并以易于理解的格式列出它们的大小(GB、MB和KB)。下面是我使用的PowerShell函数，它在一个漂亮的Out-GridView中列出了所有按大小排序的文件：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1357815|Get-ChildItem+-Path+'C:\somefolder'+-Recurse+-Force+-File+%7C
++++Select-Object+-Property+FullName+`
++++++++,@{Name='SizeGB';Expression={$_.Length+/+1GB}}+`
++++++++,@{Name='SizeMB';Expression={$_.Length+/+1MB}}+`
++++++++,@{Name='SizeKB';Expression={$_.Length+/+1KB}}+%7C
++++Sort-Object+{+$_.SizeKB+}+-Descending+%7C
++++Out-GridView|code-block|syntax|javascript|1357816|输出到PowerShell+GridView很好，因为它允许您轻松地过滤结果并滚动它们。这是较快的PowerShell+v3版本，但博客文章也显示了较慢的PowerShell+v2兼容版本。|1357817|当然，如果您只想要前10个最大的文件，只需在Select-Object调用中添加一个-First+10参数即可。|style|CODE|1357818|entityMap|0|LINK|mutability|MUTABLE|url|http://blog.danskingdom.com/find-largest-or-smallest-files-in-a-directory-or-drive-with-powershell/^0|4|V|0|0|0|0|16|9|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|F|7|10|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|11|8|@]|9|@]|C|$]]|$1|K|3|L|5|6|7|12|8|@$A|13|B|14|M|N]]|9|@]|C|$]]|$1|O|3|-4|5|6|7|15|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

I've <a href="http://blog.danskingdom.com/find-largest-or-smallest-files-in-a-directory-or-drive-with-powershell/" rel="nofollow noreferrer">blogged about a similar problem</a> where I want to find the largest files in a directory AND all subdirectories (the entire C: drive for example), as well as list their size in a nice easy to understand format (GB, MB, and KB). Here's the PowerShell function I use that lists all files sorted by size in a nice Out-GridView:
<pre><code>Get-ChildItem -Path 'C:\somefolder' -Recurse -Force -File |
 Select-Object -Property FullName `
 ,@{Name='SizeGB';Expression={$_.Length / 1GB}} `
 ,@{Name='SizeMB';Expression={$_.Length / 1MB}} `
 ,@{Name='SizeKB';Expression={$_.Length / 1KB}} |
 Sort-Object { $_.SizeKB } -Descending |
 Out-GridView
</code></pre>
Outputting to the PowerShell GridView is nice because it allows you to easily filter the results and scroll through them. This is the faster PowerShell v3 version, but the blog post also shows a slower PowerShell v2 compatible version.
And of course if you only want the top 10 largest files, you could just add a <code>-First 10</code> parameter to the Select-Object call.

blocks|key|1357859|text|将最大的10个文件放入本地目录的基本方法是使用h表示人类可读，按大小对文件进行S排序：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1357860|ls+-Sh+-l+%7Chead+-n+10|code-block|syntax|javascript|1357861|或者您可以使用|1357862|du+-ha+/home/directory+%7Csort+-n+-r+%7Chead+-n+10|1357863|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

The basic one to get the top 10 biggest files into the local directory use h for human-readable, S sort file by size : 

<pre><code>ls -Sh -l |head -n 10
</code></pre>

or you can use 

<pre><code>du -ha /home/directory |sort -n -r |head -n 10
</code></pre>

blocks|key|1573085|text|下面是我所知道的最快的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1573086|$folder++=+"$env:windir"+#+forder+to+be+scanned
$minSize+=+1MB

$stopwatch+=++[diagnostics.stopwatch]::StartNew()

$ErrorActionPreference+=+"silentlyContinue"
$list+=+New-Object+'Collections.ArrayList'
$files+=+&robocopy+/l+"$folder"+/s+\\localhost\C$\nul+/bytes+/njh+/njs+/np+/nc+/fp+/ndl+/min:$minSize
foreach($file+in+$files)+{
++++$data+=+$file.split("`t")
++++$null+=+$list.add([tuple]::create([uint64]$data[3],+$data[4]))
}

$list.sort()+#+sort+by+size+ascending
$result+=+$list.GetRange($list.count-10,10)+
$result+%7C+select+item2,+item1+%7C+sort+item1+-Descending

$stopwatch.Stop()
$t+=+$stopwatch.Elapsed.TotalSeconds
"done+in+$t+sec."|code-block|syntax|javascript|1573087|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is the fastest way to get this done I am aware of:

<pre><code>$folder = "$env:windir" # forder to be scanned
$minSize = 1MB

$stopwatch = [diagnostics.stopwatch]::StartNew()

$ErrorActionPreference = "silentlyContinue"
$list = New-Object 'Collections.ArrayList'
$files = &amp;robocopy /l "$folder" /s \\localhost\C$\nul /bytes /njh /njs /np /nc /fp /ndl /min:$minSize
foreach($file in $files) {
 $data = $file.split("`t")
 $null = $list.add([tuple]::create([uint64]$data[3], $data[4]))
}

$list.sort() # sort by size ascending
$result = $list.GetRange($list.count-10,10) 
$result | select item2, item1 | sort item1 -Descending

$stopwatch.Stop()
$t = $stopwatch.Elapsed.TotalSeconds
"done in $t sec."
</code></pre>

How do I find the 10 largest files in a directory structure?

How do I find the 10 largest files in a directory structure

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何找到目录结构中最大的10个文件？

问如何查找目录结构中最大的10个文件
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