我正在实现一个名为"Signal<args>
“的可变函数式泛型,它管理匹配函数签名类型的函数器的内部队列。在调用Signal<args>::operator()
时,队列中的每个函数器都使用相同的输入参数执行。这个想法是,它是一个纯粹的C++11对象类型,它重新创建了一些与Qt的Signal/Slot构造相同的设计行为,但静态编译的依赖性最小。我已经做好了所有的工作,但是我想提高这个泛型的可读性。
我有以下语法:
Signal<int, double> signal;
signal.add(BLOCK, [](int EmployeeID, double FavoriteNumber) {
std::cout << EmployeeNames[EmployeeID]
<< " has favorite number of "
<< FavoriteNumber << std::endl;
});
signal.add(BLOCK, [](int EmployeeID, double FavoriteNumber) {
if (EmployeeID > FavoriteNumber) {
std::cout << EmployeeNames[EmployeeID]
<< " has ID bigger than favorite number.\n";
}
});
signal(5, 3.1415); //execute both functors with args = (5, 3.1415)
我想要的是:
Signal<int EmployeeID, double FavoriteNumber> signal;
signal.add(BLOCK, [](int EmployeeID, double FavoriteNumber) {
std::cout << EmployeeNames[EmployeeID]
<< " has favorite number of "
<< FavoriteNumber << std::endl;
});
signal.add(BLOCK, [](int EmployeeID, double FavoriteNumber) {
if (EmployeeID > FavoriteNumber) {
std::cout << EmployeeNames[EmployeeID]
<< " has ID bigger than favorite number.\n";
}
});
signal(5, 3.1415); //execute both functors with args = (5, 3.1415)
唯一的区别是,出于可读性的考虑,我希望模板信号类型的声明为参数指定一个名称。理想情况下,我希望这些名称是强制的,如果未指定,则无法编译。
有没有办法做到这一点?
https://stackoverflow.com/questions/50630239
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