blocks|key|605815|text|这将在IEnumerable(Of+String)中返回上述深度的所有组合|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|605816|+Function+GetCombinations(ByVal+depth+As+Integer,+ByVal+values+As+String())+As+IEnumerable(Of+String)
++++++++If+depth+>+values.Count+%2B+1+Then+Return+New+List(Of+String)
++++++++Dim+result+=+New+List(Of+String)

++++++++For+i+=+0+To+depth+-+1
++++++++++++For+y+=+0+To+values.Count+-+1
++++++++++++++++If+i+=+0+Then
++++++++++++++++++++result.Add(values(y))
++++++++++++++++Else
++++++++++++++++++++result.Add(values(i+-+1)+%2B+values(y))
++++++++++++++++End+If
++++++++++++Next
++++++++Next
++++++++Return+result
++++End+Function|code-block|syntax|javascript|605817|编辑：|605818|示例用法：|605819|++++++++Dim+data_array+As+String()+=+{"1",+"2",+"3",+"4",+"5",+"6"}
++++++++Dim+reslt+=+GetCombinations(2,+data_array)|605820|entityMap^0|3|M|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|6|7|X|8|@]|D|@]|E|$]]|$1|O|3|P|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

This should returns all combinations of said depth in a <code>IEnumerable(Of String)</code>

<pre><code> Function GetCombinations(ByVal depth As Integer, ByVal values As String()) As IEnumerable(Of String)
 If depth &gt; values.Count + 1 Then Return New List(Of String)
 Dim result = New List(Of String)

 For i = 0 To depth - 1
 For y = 0 To values.Count - 1
 If i = 0 Then
 result.Add(values(y))
 Else
 result.Add(values(i - 1) + values(y))
 End If
 Next
 Next
 Return result
 End Function
</code></pre>

Edit:

Example usage:

<pre><code> Dim data_array As String() = {"1", "2", "3", "4", "5", "6"}
 Dim reslt = GetCombinations(2, data_array)
</code></pre>

blocks|key|389836|text|你说你想生成所有的组合，但在我看来，你想要生成所有的排列。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|389837|如果你愿意，你可以试着递归地做。如果您只想生成组合，那么在追加它之前测试Root参数，看看它是否包含myStr。|389838|Public+Class+Form1
++++Dim+data_array+As+String()+=+{"one",+"two",+"three",+"four",+"five",+"six"}
++++Dim+buffer+As+New+List(Of+String)

Public+Sub+Permute(ByVal+Root+As+String,+ByVal+Depth+As+Integer,+ByVal+Buffer+As+List(Of+String))

++++For+Each+myStr+As+String+In+data_array

++++++++++++If+Depth+<=+1+Then
++++++++++++++++Buffer.Add(Root+%2B+myStr)
++++++++++++Else
++++++++++++++++Permute(Root+%2B+myStr,+Depth+-+1,+Buffer)
++++++++++++End+If

++++Next

End+Sub

Private+Sub+Form1_Load(ByVal+sender+As+System.Object,+ByVal+e+As+System.EventArgs)+Handles+MyBase.Load
++++Permute("",+2,+buffer)
End+Sub
End+Class|code-block|syntax|javascript|389839|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You say you want to generate all combinations but it looks to me like to are trying to generate all permutations.

You might try to do it recursively if you wish. If you just want to generate combinations then test the Root parameter to see if it contains myStr before appending it.

<pre><code>Public Class Form1
 Dim data_array As String() = {"one", "two", "three", "four", "five", "six"}
 Dim buffer As New List(Of String)

Public Sub Permute(ByVal Root As String, ByVal Depth As Integer, ByVal Buffer As List(Of String))

 For Each myStr As String In data_array

 If Depth &lt;= 1 Then
 Buffer.Add(Root + myStr)
 Else
 Permute(Root + myStr, Depth - 1, Buffer)
 End If

 Next

End Sub

Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
 Permute("", 2, buffer)
End Sub
End Class
</code></pre>

I need to generate all combinations (not permutations) in VB .NET, I've been search and all I found is for permutations (some says combinations but when I was try it, all are permutations).

What I need is to generate combinations from string array:

<pre><code>Dim data_array As String() = {"one", "two", "three", "four", "five", "six"}
</code></pre>

I need that:

If I say just 1 length, it must returns:

<pre><code>one
two
three
four
five
six
</code></pre>

If I say 2 length, it must returs:

<pre><code>oneone
onetwo
onethree
onefour
... etc ...
twoone
twotwo
twothree
... etc ...
</code></pre>

And continues til end with all combinations.

If I say more length do it as well.

Generate all real combinations in VB .NET

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要在VB .NET中生成所有的组合(不是排列)，我已经搜索过了，所有我找到的都是排列(有些人说是组合，但当我尝试的时候，所有的都是排列)。我需要的是从字符串数组生成组合：Dim data_array As String() = {"one", "two", "three", "four", "five", "six...

问在VB .NET中生成所有实数组合
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