我正在尝试将XML发布到asp.net核心2:
$.ajax({
type: "POST",
url: 'api/Test',
data: "<test>hello<test>",
contentType: "application/xml",
success: function (response) { alert(response); },
});我应该如何编写动作,让它接受xml作为参数?
IActionResult Post([FromBody]string xml) xml is nullIActionResult Post([FromBody]XElement xml) xml is nullIActionResult Post(XElement xml) -> InvalidOperationException:未能创建类型为'System.Xml.Linq.XElement‘的实例。绑定模型的复杂类型不能是抽象类型或值类型,并且必须具有无参数的constructor.IActionResult Post(string xml) -> xml is 在Startup.ConfigureServices中:
services.AddMvc()
.AddXmlSerializerFormatters();如何编写控制器,使其接受XML作为参数?我知道我可以从HttpContext.Request中读取它,但我希望它是参数
发布于 2017-09-20 19:52:54
我最终创建了自定义的InputFormatter,这非常简单,但是如果有更好的替代方案,非常欢迎你写一个答案!
public class XDocumentInputFormatter : InputFormatter, IInputFormatter, IApiRequestFormatMetadataProvider
{
public XDocumentInputFormatter()
{
SupportedMediaTypes.Add("application/xml");
}
protected override bool CanReadType(Type type)
{
if (type.IsAssignableFrom(typeof(XDocument))) return true;
return base.CanReadType(type);
}
public override async Task<InputFormatterResult> ReadRequestBodyAsync(InputFormatterContext context)
{
var xmlDoc = await XDocument.LoadAsync(context.HttpContext.Request.Body, LoadOptions.None, CancellationToken.None);
return InputFormatterResult.Success(xmlDoc);
}
}在startup.cs中注册XDocumentInputFormatter
public void ConfigureServices(IServiceCollection services)
{
services.AddMvc(options => options.InputFormatters.Insert(0, new XDocumentInputFormatter()));
}https://stackoverflow.com/questions/46302703
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