我相信我正在从wikimedia API得到一个对象,但是我不知道如何解析它才能显示出来。
//app.component.ts
import { Component } from '@angular/core';
import { HttpClient, HttpParams } from '@angular/common/http';
import { Post } from './post';
import { Observable } from 'rxjs/Observable';
@Component({
  selector: 'app-root',
  templateUrl: './app.component.html',
  styleUrls: ['./app.component.css']
})
export class AppComponent {
  title = 'Wiki Search';
  // readonly ROOT_URL = 'https://en.wikipedia.org/w/api.php?action=query&list=search&srsearch=japan&origin=*&format=json';
  readonly ROOT_URL = 'https://en.wikipedia.org/w/api.php?format=json&action=query&generator=search&gsrnamespace=0&gsrlimit=10&prop=pageimages|extracts&pilimit=max&exintro&explaintext&exsentences=1&exlimit=max&gsrsearch=Harry Potter&origin=*&callback=JSON_CALLBACK';
  // https://en.wikipedia.org/w/api.php?action=query&format=json&gsrlimit=15&generator=search&origin=*&gsrsearch=japan"
  posts: Observable<any>;
  constructor(private http: HttpClient) {}
  getPosts(){
    this.posts = this.http.get(this.ROOT_URL)
  }
}
//app.component.html
<input type="text" placeholder="Search for pages..">
<button (click)="getPosts()">Get Posts</button>
<div *ngFor="let post of posts | async">
 {{ post | json }}
</div>
<ul class=filter-select>
  <li class="filter-select-list">
    <p class="wiki-page"></p>
  </li>
</ul>如果我将responseType: text插入到响应处理程序中,我就能够在开发控制台中将返回的数据作为错误读取。
发布于 2019-03-27 07:49:35
您正在调用的URL以queryString参数callback=JSON_CALLBACK结尾
https://en.wikipedia.org/w/api.php?format=json&action=query&generator=search&gsrnamespace=0&gsrlimit=10&prop=pageimages|extracts&pilimit=max&exintro&explaintext&exsentences=1&exlimit=max&gsrsearch=Harry%20Potter&origin=*&callback=JSON_CALLBACK这是将JSON包装在一个名为JSON_CALLBACK的回调方法中,该回调方法不是有效的JSON,不允许进行解析。我尝试不使用该queryString参数,现在响应是一个有效的纯JSON,您应该能够对其进行解析
https://en.wikipedia.org/w/api.php?format=json&action=query&generator=search&gsrnamespace=0&gsrlimit=10&prop=pageimages|extracts&pilimit=max&exintro&explaintext&exsentences=1&exlimit=max&gsrsearch=Harry%20Potter&origin=*https://stackoverflow.com/questions/55367739
复制相似问题