blocks|key|2672871|text|您可以将子请求与您的条件一起使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2672872|SELECT+*+FROM+Table+
INNER+JOIN+(
SELECT+animal_name,+sum(tag_name+=+'blue'+OR+tag_name+=+'cat')+as+sum_condition
FROM+TABLE
GROUP+BY+animal_name
HAVING+sum_condition+=+2)+datas+USING(animal_name)|code-block|syntax|javascript|2672873|编辑以回复评论|2672874|SELECT+*+FROM+Table+
INNER+JOIN+(
SELECT+animal_name,+sum(tag_name+=+'blue'+OR+(tag_name+IN+('cat','dog')))+as+sum_condition
FROM+TABLE
GROUP+BY+animal_name
HAVING+sum_condition+=+2)+datas+USING(animal_name)|2672875|编辑:我的错，我忘了带括号的http://sqlfiddle.com/#!9/e9e941/15/0|offset|length|2672876|entityMap|0|LINK|mutability|MUTABLE|url|http://sqlfiddle.com/#!9/e9e941/15/0^0|0|0|0|0|E|10|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

You can use a subrequest with your conditions:

<pre><code>SELECT * FROM Table 
INNER JOIN (
SELECT animal_name, sum(tag_name = 'blue' OR tag_name = 'cat') as sum_condition
FROM TABLE
GROUP BY animal_name
HAVING sum_condition = 2) datas USING(animal_name)
</code></pre>

EDIT to reply at the comment

<pre><code>SELECT * FROM Table 
INNER JOIN (
SELECT animal_name, sum(tag_name = 'blue' OR (tag_name IN ('cat','dog'))) as sum_condition
FROM TABLE
GROUP BY animal_name
HAVING sum_condition = 2) datas USING(animal_name)
</code></pre>

EDIT : My bad i had forgotten a parenthesis
<a href="http://sqlfiddle.com/#!9/e9e941/15/0" rel="nofollow noreferrer">http://sqlfiddle.com/#!9/e9e941/15/0</a>

blocks|key|15937|text|要获得拥有所有这些属性的animal_name，您可以使用条件聚合，如下所示|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|15938|SELECT+animal_name
FROM+table1
GROUP+BY+animal_name
HAVING+SUM(CASE+WHEN+tag_name+=+'cat'+AND+tag_group+=+'species'+THEN+1+ELSE+0+END++)+>+0
AND+SUM(CASE+WHEN+tag_name+=+'blue'+AND+tag_group+=+'colour'+THEN+1+ELSE+0+END++)+>+0
;|code-block|syntax|javascript|15939|使用Mysql，你也可以使用sum(a=b)，SUM(tag_name+=+'blue'+AND+tag_group+=+'colour')作为简写，在sum()中使用表达式将得到一个布尔值0/1，true/false|15940|Demo|15941|For+|15942|SELECT+animal_name
FROM+table1
GROUP+BY+animal_name
HAVING+SUM(CASE+WHEN+tag_name+=+'dog'+AND+tag_group+=+'species'+THEN+1+ELSE+0+END++)+>+0
AND+SUM(CASE+WHEN+tag_name+=+'blue'+AND+tag_group+=+'colour'+THEN+1+ELSE+0+END++)+>+0
;|15943|根据上一条评论，我需要蓝猫和蓝狗都加上OR标准才能拥有这两种动物的名字|15944|SELECT+animal_name
FROM+table1
GROUP+BY+animal_name
HAVING+(
++SUM(CASE+WHEN+tag_name+=+'dog'+AND+tag_group+=+'species'+THEN+1+ELSE+0+END++)+>+0
++AND+
++SUM(CASE+WHEN+tag_name+=+'blue'+AND+tag_group+=+'colour'+THEN+1+ELSE+0+END++)+>+0
)+OR+(
++SUM(CASE+WHEN+tag_name+=+'cat'+AND+tag_group+=+'species'+THEN+1+ELSE+0+END++)+>+0
++AND
++SUM(CASE+WHEN+tag_name+=+'blue'+AND+tag_group+=+'colour'+THEN+1+ELSE+0+END++)+>+0
)|15945|15946|entityMap|0|LINK|mutability|MUTABLE|url|http://sqlfiddle.com/#!9/e9e941/1|1|http://sqlfiddle.com/#!9/e9e941/6|2|http://rextester.com/CFBRH89477^0|C|B|0|0|E|8|N|1B|24|5|0|0|4|0|0|0|4|1|0|0|J|2|0|0|0|4|2|0^^$0|@$1|2|3|4|5|6|7|19|8|@$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1C|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1D|8|@$9|1E|A|1F|B|C]|$9|1G|A|1H|B|C]|$9|1I|A|1J|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|1K|8|@]|D|@$9|1L|A|1M|1|1N]]|E|$]]|$1|O|3|P|5|6|7|1O|8|@]|D|@$9|1P|A|1Q|1|1R]]|E|$]]|$1|Q|3|R|5|H|7|1S|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1T|8|@$9|1U|A|1V|B|C]]|D|@]|E|$]]|$1|U|3|V|5|H|7|1W|8|@]|D|@]|E|$I|J]]|$1|W|3|N|5|6|7|1X|8|@]|D|@$9|1Y|A|1Z|1|20]]|E|$]]|$1|X|3|-4|5|6|7|21|8|@]|D|@]|E|$]]]|Y|$Z|$5|10|11|12|E|$13|14]]|15|$5|10|11|12|E|$13|16]]|17|$5|10|11|12|E|$13|18]]]]

To to get the <code>animal_name</code> who have all these properties you can use conditional aggregation like 

<pre><code>SELECT animal_name
FROM table1
GROUP BY animal_name
HAVING SUM(CASE WHEN tag_name = 'cat' AND tag_group = 'species' THEN 1 ELSE 0 END ) &gt; 0
AND SUM(CASE WHEN tag_name = 'blue' AND tag_group = 'colour' THEN 1 ELSE 0 END ) &gt; 0
;
</code></pre>

Using Mysql you could also use <code>sum(a=b)</code>, <code>SUM(tag_name = 'blue' AND tag_group = 'colour')</code> as shorthand, using expression inside <code>sum()</code> will result you a boolean value 0/1, true/false

<a href="http://sqlfiddle.com/#!9/e9e941/1" rel="nofollow noreferrer">Demo</a>

<a href="http://sqlfiddle.com/#!9/e9e941/6" rel="nofollow noreferrer">For Blue dog</a>

<pre><code>SELECT animal_name
FROM table1
GROUP BY animal_name
HAVING SUM(CASE WHEN tag_name = 'dog' AND tag_group = 'species' THEN 1 ELSE 0 END ) &gt; 0
AND SUM(CASE WHEN tag_name = 'blue' AND tag_group = 'colour' THEN 1 ELSE 0 END ) &gt; 0
;
</code></pre>

As per last comment I need both the blue cat and the blue dog
Add <code>OR</code> criteria to have both animal names

<pre><code>SELECT animal_name
FROM table1
GROUP BY animal_name
HAVING (
 SUM(CASE WHEN tag_name = 'dog' AND tag_group = 'species' THEN 1 ELSE 0 END ) &gt; 0
 AND 
 SUM(CASE WHEN tag_name = 'blue' AND tag_group = 'colour' THEN 1 ELSE 0 END ) &gt; 0
) OR (
 SUM(CASE WHEN tag_name = 'cat' AND tag_group = 'species' THEN 1 ELSE 0 END ) &gt; 0
 AND
 SUM(CASE WHEN tag_name = 'blue' AND tag_group = 'colour' THEN 1 ELSE 0 END ) &gt; 0
)
</code></pre>

<a href="http://rextester.com/CFBRH89477" rel="nofollow noreferrer">Demo</a>

MySQL using column values in query

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

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+-------------+----------+-----------+| animal_name | tag_name | tag_group |+-------------+----------+-----------+| CatBlue     | cat      | species   || CatBlu...

问在查询中使用列值的MySQL
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