blocks|key|4367331|text|我已经测试了你的代码，修复了第4行缺少的左括号(looyd测验)，它工作得很好。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4367332|++++lloyd+=+{
++++"name":+"Lloyd",
++++"homework":+[90.0,+97.0,+75.0,+92.0],
++++"quizzes":+[88.0,+40.0,+94.0],
++++"tests":+[75.0,+90.0]
++++}
++++alice+=+{
++++"name":+"Alice",
++++"homework":+[100.0,+92.0,+98.0,+100.0],
++++"quizzes":+[82.0,+83.0,+91.0],
++++"tests":+[89.0,+97.0]
++++}
++++tyler+=+{
++++"name":+"Tyler",
+++++"homework":+[0.0,+87.0,+75.0,+22.0],
++++"quizzes":+[0.0,+75.0,+78.0],
++++"tests":+[100.0,+100.0]
++++}

++++#+Add+your+function+below!
++++def+average(numbers):
++++++++total+=+sum(numbers)
++++++++total+=+float(total)
++++++++result+=+total/len(numbers)
++++++++return+result

++++def+get_average(student):
++++++++homework+=+average(student["homework"])
++++++++quizzes+=+average(student["quizzes"])
++++++++tests+=+average(student["tests"])
++++++++Av+=+(0.1+*+homework)+%2B+(0.6+*+tests)+%2B(0.3+*+quizzes)
++++++++print+Av

++++get_average(alice)|code-block|syntax|javascript|4367333|这段代码在我的Python2.7上打印91.15|offset|length|style|CODE|4367334|entityMap^0|0|0|J|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I've tested your code, fixed the missing opening bracket at line 4 (looyd quizzes) and it's working well.

<pre><code> lloyd = {
 "name": "Lloyd",
 "homework": [90.0, 97.0, 75.0, 92.0],
 "quizzes": [88.0, 40.0, 94.0],
 "tests": [75.0, 90.0]
 }
 alice = {
 "name": "Alice",
 "homework": [100.0, 92.0, 98.0, 100.0],
 "quizzes": [82.0, 83.0, 91.0],
 "tests": [89.0, 97.0]
 }
 tyler = {
 "name": "Tyler",
 "homework": [0.0, 87.0, 75.0, 22.0],
 "quizzes": [0.0, 75.0, 78.0],
 "tests": [100.0, 100.0]
 }

 # Add your function below!
 def average(numbers):
 total = sum(numbers)
 total = float(total)
 result = total/len(numbers)
 return result

 def get_average(student):
 homework = average(student["homework"])
 quizzes = average(student["quizzes"])
 tests = average(student["tests"])
 Av = (0.1 * homework) + (0.6 * tests) +(0.3 * quizzes)
 print Av

 get_average(alice)
</code></pre>

This code is printing <code>91.15</code> on my python 2.7

blocks|key|4366940|text|或者，您也可以尝试执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4366941|import+numpy+as+np
def+weighted_average(d):
+"""Returns+weighted+average+of+values+corresponding+to+keys+homework,+
++++tests+&+quizzes+of+a+dictionary+d"""

++++#+bind+dict+keys+to+variables+homework,+test,+quiz
++++homework,+test,+quiz+=+[d["homework"]],+[d["tests"]],+[d["quizzes"]]
++++#+calculate+average+through+np.mean()+and+Return+the+value
++++return+"Average:+{}".format((0.1+*+np.mean(homework))+%2B+(0.6+*+np.mean(test))+%2B+(0.3+*+np.mean(quiz)))++++

d+=+lloyd+=+{"name":+"Lloyd","homework":+[90.0,+97.0,+75.0,+92.0],"quizzes":+[88.0,+40.0,+94.0],"tests":+[75.0,+90.0]}
averages(d)

>>>'Average:+80.55'|code-block|syntax|javascript|4366942|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Alternatively, you can also try this: 

<pre><code>import numpy as np
def weighted_average(d):
 """Returns weighted average of values corresponding to keys homework, 
 tests &amp; quizzes of a dictionary d"""

 # bind dict keys to variables homework, test, quiz
 homework, test, quiz = [d["homework"]], [d["tests"]], [d["quizzes"]]
 # calculate average through np.mean() and Return the value
 return "Average: {}".format((0.1 * np.mean(homework)) + (0.6 * np.mean(test)) + (0.3 * np.mean(quiz))) 

d = lloyd = {"name": "Lloyd","homework": [90.0, 97.0, 75.0, 92.0],"quizzes": [88.0, 40.0, 94.0],"tests": [75.0, 90.0]}
averages(d)

&gt;&gt;&gt;'Average: 80.55'
</code></pre>

I am new to python with great desire to learn the language. However, right now i need someone help with a code i am currently working on which keep flagging this error : 
Oops, try again. get_average(alice) returned None instead of the expected 91.15

This is the question with my solution below also:
Write a function called get_average that takes a student dictionary (like lloyd, alice, or tyler) as input and returns his/her weighted average.

Define a function called get_average that takes one argument called student.
Make a variable homework that stores the average() of student["homework"].
Repeat step 2 for "quizzes" and "tests".
Multiply the 3 averages by their weights and return the sum of those three. Homework is 10%, quizzes are 30% and tests are 60%.

MY SOLUTION:

<pre><code>lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": 88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = { 
"name": "Tyler",
 "homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

# Add your function below!
def average(numbers):
 total = sum(numbers)
 total = float(total)
 result = total/len(numbers)
 return result

def get_average(student):
 homework = average(student["homework"])
 quizzes = average(student["quizzes"])
 tests = average(student["tests"])
 Av = (0.1 * homework) + (0.6 * tests) +(0.3 * quizzes)
 print Av
</code></pre>

Error with my python code

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我是python的新手，有学习这门语言的强烈愿望。然而，现在我需要有人帮助我目前正在处理的代码，它不断标记这个错误:哦，再试一次。get_average(alice)返回None，而不是预期的91.15这也是我下面的解决方案的问题:编写一个名为get_average的函数，该函数将学生字典(如劳埃德、爱丽丝或泰勒)作为...

问我的python代码出错
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