如何获取Pandas时间增量中的总小时数?
例如:
>>> td = pd.Timedelta('1 days 2 hours')
>>> td.get_total_hours()
26
注意:根据文档,.hours
属性将返回小时组件
>>> td.hours
2
发布于 2015-07-08 11:32:31
只需找出其中包含多少个1小时的timedelta
:
import numpy as np
>> td / np.timedelta64(1, 'h')
26.0
发布于 2015-07-08 16:28:31
试着告诉我们为什么熊猫会返回2个小时。
import pandas as pd
td = pd.Timedelta('1 days 2 hours')
td.components
Out[45]: Components(days=1, hours=2, minutes=0, seconds=0, milliseconds=0, microseconds=0, nanoseconds=0)
td / pd.Timedelta('1 hour')
Out[46]: 26.0
发布于 2018-06-02 05:15:15
我得到以秒为单位的时间增量,然后除以3600得到小时数。
round(td.total_seconds() / 3600)
。
当我在jupyter notebook上测试时,这种方法运行得更快。
%timeit td / np.timedelta64(1, 'h')
The slowest run took 19.10 times longer than the fastest. This could mean that an intermediate result is being cached.
100000 loops, best of 3: 4.58 µs per loop
%timeit round(td.total_seconds() / 3600)
The slowest run took 18.08 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 401 ns per loop
https://stackoverflow.com/questions/31283001
复制相似问题