我想给NavigationLink添加一个额外的函数。
示例代码如下所示:
struct ContentView: View {
func yes () {
print("yes")
}
var body: some View {
NavigationView {
NavigationLink(destination: level1()) {
Text("Next")
}}}}我知道这行不通,但有没有可能这样做呢?(转到目的地,同时调用函数)
NavigationLink(destination: level1(), yes()) {Text("Next")} 我试着把一个按钮放在NavigationLink里面,但也不起作用。当我这样做时,只有按钮中的函数有效,而NavigationLink不起作用。
NavigationLink(destination: level1()) {
Button(action: { self.yes() })
{ Text("Button")}
}发布于 2020-03-05 23:51:07
使用onAppear(perform:)。这将对View的出现执行一些功能。
struct ContentView: View {
var body: some View {
NavigationView {
NavigationLink(destination: DetailView().onAppear {
self.someFunc()
}) {
Text("First Screen")
}
}
}
func someFunc() {
print("Click")
}
}
struct DetailView: View {
var body: some View {
Text("Second Screen")
}
}发布于 2021-11-24 16:09:53
适用于SwiftUI、iOS 15.1和Xcode 13.1的解决方案。
import Foundation
import SwiftUI
// NavigationLink replacement with action
// Usage:
//var body: some View {
// NavigationButton(
// action: { print("tapped!") },
// destination: { Text("Pushed View") },
// label: { Text("Tap me") }
// )
//}
struct NavigationButton<Destination: View, Label: View>: View {
var action: () -> Void = { }
var destination: () -> Destination
var label: () -> Label
@State private var isActive: Bool = false
var body: some View {
Button(action: {
self.action()
self.isActive.toggle()
}) {
self.label()
.background(
ScrollView { // Fixes a bug where the navigation bar may become hidden on the pushed view
NavigationLink(destination: LazyDestination { self.destination() },
isActive: self.$isActive) { EmptyView() }
}
)
}
}
}
// This view lets us avoid instantiating our Destination before it has been pushed.
struct LazyDestination<Destination: View>: View {
var destination: () -> Destination
var body: some View {
self.destination()
}
}我找不到原始代码,但这个解决方案非常适合我。
https://stackoverflow.com/questions/60549028
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