blocks|key|788073|text|listQuestion.findIndex((ques)=>ques=={target.value})；quesIndex+=+const+listQuestionquesIndex+=+{target.value}；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|788074|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

<p>const quesIndex = listQuestion.findIndex((ques)=>ques=={target.value});
listQuestion[quesIndex] = {target.value};</p>


blocks|key|795522|text|首先，你需要在你的render返回值中基于你的listQuestion呈现所有的输入。我假设在listQuestion数组中，对于每个问题，它都有唯一的id，根据这个id，我们可以检测到哪个值正在发生变化。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|795523|{
+listQuestion.map((item,+index)+=>+{
+++return+(
+++++++<Input+value+=+{item.value}+onChange+=+{(e)+=>+{this.handleOnChange(e,+
+item.id)}+}></Input>
+++);
+});
}
//+item.id+<=+it+is+the+unique+identifier+for+each+question+object.|code-block|syntax|javascript|795524|现在，您需要创建一个处理onChange的函数|795525|handleOnChange(e,+id)+{
+const+{listQuestion}+=+this.state;
+listQuestion.forEach((item,+index)+=>+{
+++(item.id+==+id)+{
+++++item.value+=+e.target.value;
+++}
+})
+this.setState({listQuestion})
}|795526|也在你的构造函数中|795527|constructor(props)+{
+super(props);
+this.state+=+{
++listQuestion:+[]
+}
+this.handleOnChange+=+this.handleOnChange.bind(this);
}|795528|假设你没有唯一的id，那么你可以依赖索引，这样你就可以改变这一点……|795529|<Input+value+=+{item.value}+onChange+=+{(e)+=>+{this.handleOnChange(e,+
+index)}+}></Input>
//+it+will+send+the+index+along+with+event,+hence+we+can+change+value+in+listQuestion+on+the+basis+of+index.|795530|只需在onChange函数中更改此设置|795531|handleOnChange(e,+questionIndex)+{
+const+{listQuestion}+=+this.state;
+listQuestion.forEach((item,+index)+=>+{
+++(questionIndex+==+id)+{
+++++item.value+=+e.target.value;
+++}
+})
+this.setState({listQuestion})
}

//+hence+it+will+find+the+index+in+listQuestion+array+and+change+value+of+that+particular+index.|795532|entityMap^0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|12|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|14|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|16|8|@]|9|@]|A|$]]|$1|U|3|V|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|W|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|X|$]]

<p>first you need to render all the input based on your listQuestion inside your render return. I am assuming in listQuestion array for every question it will have unique id for each question on which basis we will detect which value is being change.</p>

<pre><code>{
 listQuestion.map((item, index) =&gt; {
   return (
       &lt;Input value = {item.value} onChange = {(e) =&gt; {this.handleOnChange(e, 
 item.id)} }&gt;&lt;/Input&gt;
   );
 });
}
// item.id &lt;= it is the unique identifier for each question object.
</code></pre>

<p>now you need to create a function which will handle onChange</p>

<pre><code>handleOnChange(e, id) {
 const {listQuestion} = this.state;
 listQuestion.forEach((item, index) =&gt; {
   (item.id == id) {
     item.value = e.target.value;
   }
 })
 this.setState({listQuestion})
}
</code></pre>

<p>also inside your constructor</p>

<pre><code>constructor(props) {
 super(props);
 this.state = {
  listQuestion: []
 }
 this.handleOnChange = this.handleOnChange.bind(this);
}
</code></pre>

<p>let's say you have no unique id then you can rely on the index so you can change this...</p>

<pre><code>&lt;Input value = {item.value} onChange = {(e) =&gt; {this.handleOnChange(e, 
 index)} }&gt;&lt;/Input&gt;
// it will send the index along with event, hence we can change value in listQuestion on the basis of index.
</code></pre>

<p>and just change this in onChange function</p>

<pre><code>handleOnChange(e, questionIndex) {
 const {listQuestion} = this.state;
 listQuestion.forEach((item, index) =&gt; {
   (questionIndex == id) {
     item.value = e.target.value;
   }
 })
 this.setState({listQuestion})
}

// hence it will find the index in listQuestion array and change value of that particular index.
</code></pre>


blocks|key|788076|text|添加了一个新状态以保存表单中的答案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|788077|listAnswers+=+{
+question1:+value,
+...
};|code-block|syntax|javascript|788078|为文本输入创建一个自定义组件，这样我们就可以提供额外的支持。|788079|state+=+{
+listQuestion:+[],
++listAnswers:+{},
};
handleInput+=+(name,+value)+=>+{
+this.setState({listAnswers[name]:+value+});+
}

renderTableData()+{
+return+this.state.listQuestion.map(ques+=>+{
++const+{+question+}+=+ques;
++return+(
++++<View+style={styles.headerBottom}>
++++++<View+style={styles.nameView}>
++++++++<TextInput+style={styles.textName}>{question}+</Text>+//+display+question
++++++++<Input+name={question}+value={this.state.listanswers[question]+%7C%7C+''}+onPress={this.handleInput}></Input>
++++++</View>
++++</View>
++);
+});
}|788080|TextInput组件|788081|const+TextInputComponent+=+({value,+onChangeText,+name,+...props})+=>+(
+<Input
++++value={value}
++++onChangeText={(value)+=>+onPress(name,+value)}+//...+Bind+the+name+here
++++{...props}
+/>
);|788082|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

<p>Added a newstate to hold the answers in the form:</p>

<pre><code>listAnswers = {
 question1: value,
 ...
};
</code></pre>

<p>Make a custom component for text input, so that we can give additional props.</p>

<pre><code>state = {
 listQuestion: [],
  listAnswers: {},
};
handleInput = (name, value) =&gt; {
 this.setState({listAnswers[name]: value }); 
}

renderTableData() {
 return this.state.listQuestion.map(ques =&gt; {
  const { question } = ques;
  return (
    &lt;View style={styles.headerBottom}&gt;
      &lt;View style={styles.nameView}&gt;
        &lt;TextInput style={styles.textName}&gt;{question} &lt;/Text&gt; // display question
        &lt;Input name={question} value={this.state.listanswers[question] || ''} onPress={this.handleInput}&gt;&lt;/Input&gt;
      &lt;/View&gt;
    &lt;/View&gt;
  );
 });
}
</code></pre>

<h2>TextInput Component</h2>

<pre><code>const TextInputComponent = ({value, onChangeText, name, ...props}) =&gt; (
 &lt;Input
    value={value}
    onChangeText={(value) =&gt; onPress(name, value)} //... Bind the name here
    {...props}
 /&gt;
);
</code></pre>


<p>There is a list of question saved in the state of listQuestion. Each question will have an answer input field. How to store the inputted value and how to use onChangetext to save the value for each question? </p>

<pre><code>state = {
    listQuestion: [],
  };
async componentDidMount() {
   let question = await AsyncStorage.getItem("QuestionUser");
   if (question) {
      this.setState({ listQuestion: JSON.parse(question) });
    }
 }
renderTableData() {
    return this.state.listQuestion.map(ques =&gt; {
      const { question } = ques;
      return (
        &lt;View style={styles.headerBottom}&gt;
          &lt;View style={styles.nameView}&gt;
            &lt;Text style={styles.textName}&gt;{question} &lt;/Text&gt; // display question
            &lt;Input&gt;&lt;/Input&gt; // how to use value and onChangeText for each question
          &lt;/View&gt;
        &lt;/View&gt;
      );
    });
  }
</code></pre>


how to make input based on number of elements in array react

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有一个保存在listQuestion状态下的问题列表。每个问题都有一个答案输入字段。如何存储输入的值，以及如何使用onChangetext保存每个问题的值？state = {    listQuestion: [],  };async componentDidMount() {   let question = awa...

问如何根据数组中的元素数进行输入react
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问如何根据数组中的元素数进行输入reactEN