blocks|key|4246647|text|Splice变异数组并返回数组-+https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4246648|如果您不关心重复，那么只需使用索引，或者使用第一个元素。|4246649|function+go(){

var+Numbers+=+['one',+'two',+'three','four','five'];
var+LuckyNumbers+=+['three',+'four',+'seven']

var+num1,+num2;

//+with+repetitions
num1+=+Numbers[Math.floor(Math.random()+*+Numbers.length)];
num2+=+Numbers[Math.floor(Math.random()+*+Numbers.length)];

//without+repetitions
num1+=+Numbers.splice(Math.floor(Math.random()+*+Numbers.length),+1)[0];
num2+=+Numbers.splice(Math.floor(Math.random()+*+Numbers.length),+1)[0];

if([num1,+num2].every(item+=>+LuckyNumbers.includes(item)))+{+//always+false+when+using+the+randoms.
++console.log("yep")
}+else{
++console.log('nope')+
}
}|code-block|syntax|javascript|4246650|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice^0|H|2L|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

Splice mutates the arrays and returns an array - <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice" rel="nofollow noreferrer">https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice</a>

Just use an index instead if you don't care about repetition, or use the first element.

<pre><code>function go(){

var Numbers = ['one', 'two', 'three','four','five'];
var LuckyNumbers = ['three', 'four', 'seven']

var num1, num2;

// with repetitions
num1 = Numbers[Math.floor(Math.random() * Numbers.length)];
num2 = Numbers[Math.floor(Math.random() * Numbers.length)];

//without repetitions
num1 = Numbers.splice(Math.floor(Math.random() * Numbers.length), 1)[0];
num2 = Numbers.splice(Math.floor(Math.random() * Numbers.length), 1)[0];

if([num1, num2].every(item =&gt; LuckyNumbers.includes(item))) { //always false when using the randoms.
 console.log("yep")
} else{
 console.log('nope') 
}
}
</code></pre>

blocks|key|4246721|text|这与您的if语句一点关系都没有。num1和num2并没有按照你所写的那样存储在你的代码中。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4246722|Array.prototype.splice在一个新数组中返回被删除的元素。即使只有一个，也需要在索引0中引用它|4246723|var+Numbers+=+['one',+'two',+'three','four','five'];
var+LuckyNumbers+=+['three',+'four',+'seven']

var+num1,+num2;

num1+=+Numbers.splice(Math.floor(Math.random()+*+Numbers.length),+1)[0];
num2+=+Numbers.splice(Math.floor(Math.random()+*+Numbers.length),+1)[0];

if([num1,+num2].every(item+=>+LuckyNumbers.includes(item)))+{
++console.log("yep")
}+else{
++console.log('nope')+
}|code-block|syntax|javascript|4246724|编辑:为了给您一个更完整的答案--请注意，在这里使用splice并不像其他人所指出的那样是个大问题。是的，它会修改Numbers数组，但每次调用go函数时都会重新创建Numbers数组。|4246725|在这种情况下，这是解决这个问题的一种完全合理的方法，不过，如果您想重构代码，以便将Numbers和LuckyNumbers存储在某个父作用域中，则需要注意其中的变化：|4246726|const+Numbers+=+['one',+'two',+'three','four','five'];
const+LuckyNumbers+=+['three',+'four',+'seven']

function+go()+{
++++//+Slice+with+no+arguments+creates+a+clone+of+an+array...
++++var+numbers+=+Numbers.slice();

++++//+Note+I'm+calling+splice+on+`numbers`+with+a+small+`n`+here...
++++var+num1+=+numbers.splice(Math.floor(Math.random()+*+Numbers.length),+1)[0];
++++var+num2+=+numbers.splice(Math.floor(Math.random()+*+Numbers.length),+1)[0];

++++if([num1,+num2].every(item+=>+LuckyNumbers.includes(item)))+{
++++++console.log("yep")
++++}+else{
++++++console.log('nope')
++++}
}|4246727|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice^0|4|2|G|4|L|4|0|0|M|1F|1|0|M|0|0|0|Q|6|1L|7|20|2|2B|7|0|15|7|1D|C|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]|$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|17|8|@$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@$9|1C|A|1D|1|1E]]|E|$]]|$1|H|3|I|5|J|7|1F|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1G|8|@$9|1H|A|1I|B|C]|$9|1J|A|1K|B|C]|$9|1L|A|1M|B|C]|$9|1N|A|1O|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|1P|8|@$9|1Q|A|1R|B|C]|$9|1S|A|1T|B|C]]|D|@]|E|$]]|$1|Q|3|R|5|J|7|1U|8|@]|D|@]|E|$K|L]]|$1|S|3|-4|5|6|7|1V|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

This isn't related to your <code>if</code> statement at all. <code>num1</code> and <code>num2</code> are not storing what you think they're storing in your code as written.

<a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/splice" rel="nofollow noreferrer"><code>Array.prototype.splice</code></a> returns the removed elements in a new array. Even if there is only one, you'll need to reference it at index <code>0</code>:

<pre><code>var Numbers = ['one', 'two', 'three','four','five'];
var LuckyNumbers = ['three', 'four', 'seven']

var num1, num2;

num1 = Numbers.splice(Math.floor(Math.random() * Numbers.length), 1)[0];
num2 = Numbers.splice(Math.floor(Math.random() * Numbers.length), 1)[0];

if([num1, num2].every(item =&gt; LuckyNumbers.includes(item))) {
 console.log("yep")
} else{
 console.log('nope') 
}
</code></pre>

Edit: In the interest of giving you a more complete answer-- note that using <code>splice</code> here is not nearily as much of a problem as others seem to indicate. Yes, it muates the <code>Numbers</code> array, but the <code>Numbers</code> array is created anew every time you invoke your <code>go</code> function.

In this case, it's a completely reasonable way to solve this problem, though if you ever want to refactor your code such that <code>Numbers</code> and <code>LuckyNumbers</code> are stored in some parent scope, you'll need to be aware of the mutations:

<pre><code>const Numbers = ['one', 'two', 'three','four','five'];
const LuckyNumbers = ['three', 'four', 'seven']

function go() {
 // Slice with no arguments creates a clone of an array...
 var numbers = Numbers.slice();

 // Note I'm calling splice on `numbers` with a small `n` here...
 var num1 = numbers.splice(Math.floor(Math.random() * Numbers.length), 1)[0];
 var num2 = numbers.splice(Math.floor(Math.random() * Numbers.length), 1)[0];

 if([num1, num2].every(item =&gt; LuckyNumbers.includes(item))) {
 console.log("yep")
 } else{
 console.log('nope')
 }
}
</code></pre>

blocks|key|4246782|text|你用来比较的数组实际上是一个嵌套的数组，它需要是平面的。例：[‘五’，‘一’]你做这件事的方式是无法与之相比的。希望这能有所帮助。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4246783|function+go+()+{
++var+Numbers+=+['one',+'two',+'three',+'four',+'five']
++var+LuckyNumbers+=+['three',+'four',+'seven']

++var+num1,+num2

++num1+=+Numbers.splice(Math.floor(Math.random()+*+Numbers.length),+1)
++num2+=+Numbers.splice(Math.floor(Math.random()+*+Numbers.length),+1)

++if+(flatten([num1,+num2]).every(item+=>+LuckyNumbers.includes(item)))+{
++++//+always+false+when+using+the+randoms.
++++console.log('yep')
++}+else+{
++++console.log('nope')
++}
}
go()

function+flatten+(arr)+{
++return+arr.reduce((accum,+curr)+=>+{
++++if+(Array.isArray(curr))+{
++++++return+accum.concat(flatten(curr))
++++}+else+{
++++++return+accum.concat(curr)
++++}
++},+[])
}|code-block|syntax|javascript|4246784|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

The array your using to compare against is actually a nested array of arrays it needs to be flat. ex: [['five'],['one']] couldnt be compared the way you were doing it. Hope this helps.

<pre><code>function go () {
 var Numbers = ['one', 'two', 'three', 'four', 'five']
 var LuckyNumbers = ['three', 'four', 'seven']

 var num1, num2

 num1 = Numbers.splice(Math.floor(Math.random() * Numbers.length), 1)
 num2 = Numbers.splice(Math.floor(Math.random() * Numbers.length), 1)

 if (flatten([num1, num2]).every(item =&gt; LuckyNumbers.includes(item))) {
 // always false when using the randoms.
 console.log('yep')
 } else {
 console.log('nope')
 }
}
go()

function flatten (arr) {
 return arr.reduce((accum, curr) =&gt; {
 if (Array.isArray(curr)) {
 return accum.concat(flatten(curr))
 } else {
 return accum.concat(curr)
 }
 }, [])
}
</code></pre>

I read about a loot box system and wanted to make my own kind of lucky number calculator.

I have 2 arrays, one with regular numbers and one with the winning ones.
Two numbers will be put in a variable and if both these numbers are in the winning array you win!

Now the thing i'm struggling with is that when i make the numbers random my if else statement doesn't work anymore. It will always say false even though the numbers are correct.

if you declare the variables not random, it does work ( it is shown in the code below).

How can i make the if else statement working with the random generator?

CODE:

<pre><code>function go(){

var Numbers = ['one', 'two', 'three','four','five'];
var LuckyNumbers = ['three', 'four', 'seven']

var num1, num2;

num1 = Numbers.splice(Math.floor(Math.random() * Numbers.length), 1);//This doesnt work..
num2 = Numbers.splice(Math.floor(Math.random() * Numbers.length), 1);//This doesnt work..

// num1 ="three"; -&gt; this works but it is not random
// num2 ="four"; -&gt; this works but it is not random

if([num1, num2].every(item =&gt; LuckyNumbers.includes(item))) { //always false when using the randoms.
 console.log("yep")
} else{
 console.log('nope') 
}
</code></pre>

}

Javascript if else statement with random variables

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我读到了一个奖品箱系统，想做一种属于我自己的幸运数字计算器。我有两个数组，一个是正则数组，另一个是胜出数组。两个数字将被放入一个变量中，如果这两个数字都在获胜的数组中，你就赢了！现在我正在努力解决的是，当我把数字随机的时候，我的if else语句就不再起作用了。即使这些数字是正确的，它也总是会显示false。如果你声明...

问带有随机变量的Javascript if else语句
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