如何将数据从python客户端发送到Django web服务器？
如何将数据从python客户端发送到Django web服务器？
提问于 2021-05-29 00:53:01
我想python3程序发送JSON数据到Django网络服务器，并打印在网页上。这是我在Views.py中所拥有的：
def receive_json(request):
if request.method == 'POST':
received_data = json.loads(request.body.decode("utf-8"))
return StreamingHttpResponse('it was post request: ' + str(received_data))
return StreamingHttpResponse('it was get request')和python代码：
import requests
import json
url = "http://127.0.0.1:8000/"
data = {"data": [{'key1':'val1'}, {'key2':'val2'}]}
headers = {'content-type':'application/json'}
r = requests.post(url, data=json.dumps(data), headers=headers)
r.text但是，它显示以下消息：
Forbidden (CSRF cookie not set.): /
[28/May/2021 16:51:31] "POST / HTTP/1.1" 403 2864回答 2
Stack Overflow用户
发布于 2021-05-29 01:02:15
import requests
import json
url = "http://127.0.0.1:8000/"
data = {"data": [{'key1':'val1'}, {'key2':'val2'}]}
headers = {'content-type':'application/json','Cookie':'csrftoken=axXsa39e5hq8gqlTjJFHAbUWtg2FQgnSd3cxxkx9khatqgersthtSryDxtF0cVCk'}
r = requests.post(url, data=json.dumps(data), headers=headers)
r.text我认为可以通过添加Cookie来实现这些功能，但是如果您通过以下方式在receive_json函数中使用@csrf_exempt装饰器会更好
from django.views.decorators.csrf import csrf_exempt
@csrf_exempt
def receive_json(request):
if request.method == 'POST':
received_data = json.loads(request.body.decode("utf-8"))
return StreamingHttpResponse('it was post request: ' + str(received_data))
return StreamingHttpResponse('it was get request')Stack Overflow用户
发布于 2021-05-29 01:18:37
本质上，您首先需要执行GET请求来获取csrftoken，然后将其与数据一起post。有几种方法可以做到这一点。这里有一个(但未经过测试)：
import requests
import json
url = "http://127.0.0.1:8000/"
s = requests.Session()
s.get(url)
headers = {
'content-type':'application/json',
'X-CSRFToken': s.cookies["csrftoken"],
}
data = {"data": [{'key1':'val1'}, {'key2':'val2'}]}
r = s.post(url, data=json.dumps(data), headers=headers)
r.text你可以在Django's CSRF documentation上找到更多信息。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/67742823
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