使用java8特性实现for循环
使用java8特性实现for循环
提问于 2021-05-20 20:09:01
有没有人可以帮我用java8的特性来重组下面的代码。
这是我的代码。
private List<CreateChildItemResponse> createChildItems(String[] childUpcNumbers, String[] childItemNbrs,
ItemVo parentItem, UserVo user, boolean isEnableReverseSyncFlag, Integer parentItemNbr, Long parentUpcNbr,int childUpcNbrsize, ItemManagerDelegate managerDelegate) throws NumberFormatException, ValidationException,ChildNotFoundException, ResourceException, ChildItemException {
List<ItemVo> resultList = new ArrayList<ItemVo>();
List<CreateChildItemAssortmentResponse> relations = null;
CreateChildItemResponse response = new CreateChildItemResponse();
try {
for (int i = 0; i < childUpcNumbers.length; i++) {
// parentItem.setItemNbr(itemNumberList.get(i));
logger.info("-------Item Nbrs-----" + parentItem.getItemNbr());
ItemVo child = createItemForMigration(
populateChildItemVo(parentItem, getGtin(childUpcNumbers[i]), Integer.valueOf(childItemNbrs[i])),
user, isEnableReverseSyncFlag, managerDelegate);// null scales for all except scales integration
resultList.add(child);
}
relations = this.populateAssortmentRelationVo(parentItem.getItemNbr(), resultList);
response = getSuccessResponse(parentItemNbr, relations, parentUpcNbr);
// utx.commit();
} catch (Exception e) {
logger.info("Exception occurs while creating child item", e);
relations = this.populateAssortmentRelationVoForException(e, resultList);
response = getFailureResponseForException(parentItemNbr, relations, parentUpcNbr, e, resultList.size(),
childUpcNbrsize);
finalResponse.add(response);
throw new ChildItemException(e.getMessage(), finalResponse, e);
}
finalResponse.add(response);
return finalResponse;
}在上面的代码中，我调用了下面的方法
relations = this.populateAssortmentRelationVo(parentItem.getItemNbr(), resultList);它的实现是
private List<CreateChildItemAssortmentResponse> populateAssortmentRelationVo(Integer parentItemNumber,
List<ItemVo> childs) {
List<CreateChildItemAssortmentResponse> relationList = new ArrayList<CreateChildItemAssortmentResponse>();
for (ItemVo child : childs) {
CreateChildItemAssortmentResponse relation = new CreateChildItemAssortmentResponse();
relation.setItemNbr(child.getItemNbr());
relation.setUpcNbr(convertUpcToString(child.getEachGtin().getGtinNbr()));
relation.setStatus("SUCCESS");
relation.setMessage("");
relationList.add(relation);
}
return relationList;
}在这里，我想获取populateAssortmentRelationVo()的构造函数，以及如何在其中使用流和映射器。
回答 1
Stack Overflow用户
发布于 2021-05-20 20:56:24
首先声明一个映射函数：
private CreateChildItemAssortmentResponse> itemVoToResponse(ItemVo item) {
CreateChildItemAssortmentResponse response = new CreateChildItemAssortmentResponse();
response.setItemNbr(item.getItemNbr());
response.setUpcNbr(convertUpcToString(item.getEachGtin().getGtinNbr()));
response.setStatus("SUCCESS");
response.setMessage("");
return relationList;
}并简单地将一个列表的所有元素映射到另一个列表中：
relations = resultList.stream()
.map(this::itemVoToResponse)
.collect(toList());页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/67620067
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