根据c# LINQ中的子节点XML获取特定父节点
根据c# LINQ中的子节点XML获取特定父节点
提问于 2018-05-04 13:12:25
我有一个很长的XML，它的父节点是sdnEntry，每个父节点都有它的子sdnType，它定义了条目的类型。我正在尝试仅获取包含 sdnType to Individual**.**的节点
下面是我的xml的简短示例；
<sdnEntry>
<uid>6905</uid>
<lastName>abc</lastName>
<sdnType>Entity</sdnType> // type is entity
<akaList>
<aka>
<uid>4741</uid>
<type>a.k.a.</type>
<category>strong</category>
<lastName>ABC</lastName>
<firstName>ABCCCC</firstName>
</aka>
<aka>
<uid>4742</uid>
<type>a.k.a.</type>
<category>weak</category>
<lastName>ADCS</lastName>
</aka>
</akaList>
<nationalityList>
<nationality>
<uid>5416</uid>
<country>XYZ</country>
<mainEntry>true</mainEntry>
</nationality>
</nationalityList>
</sdnEntry>
<sdnEntry>
<uid>6905</uid>
<lastName>abc</lastName>
<sdnType>Individual</sdnType> // type is individual
<akaList>
<aka>
<uid>4741</uid>
<type>a.k.a.</type>
<category>strong</category>
<lastName>ABC</lastName>
<firstName>ABCCCC</firstName>
</aka>
<aka>
<uid>4742</uid>
<type>a.k.a.</type>
<category>weak</category>
<lastName>ADCS</lastName>
</aka>
</akaList>
<nationalityList>
<nationality>
<uid>5416</uid>
<country>XYZ</country>
<mainEntry>true</mainEntry>
</nationality>
</nationalityList>
</sdnEntry>
<sdnEntry>
<uid>6905</uid>
<lastName>abc</lastName>
<sdnType>Individual</sdnType>
<akaList>
<aka>
<uid>4741</uid>
<type>a.k.a.</type>
<category>strong</category>
<lastName>ABC</lastName>
<firstName>ABCCCC</firstName>
</aka>
<aka>
<uid>4742</uid>
<type>a.k.a.</type>
<category>weak</category>
<lastName>ADCS</lastName>
</aka>
</akaList>
<nationalityList>
<nationality>
<uid>5416</uid>
<country>XYZ</country>
<mainEntry>true</mainEntry>
</nationality>
</nationalityList>
</sdnEntry>
<sdnEntry>
<uid>6905</uid>
<lastName>abc</lastName>
<sdnType>Entity</sdnType>
<akaList>
<aka>
<uid>4741</uid>
<type>a.k.a.</type>
<category>strong</category>
<lastName>ABC</lastName>
<firstName>ABCCCC</firstName>
</aka>
<aka>
<uid>4742</uid>
<type>a.k.a.</type>
<category>weak</category>
<lastName>ADCS</lastName>
</aka>
</akaList>
<nationalityList>
<nationality>
<uid>5416</uid>
<country>XYZ</country>
<mainEntry>true</mainEntry>
</nationality>
</nationalityList>
</sdnEntry>我的代码是这样的，但我得到了错误；
var lXelements = XElement.Parse(xml);
var lParentNode = "sdnEntry";
if (lParentNode == "sdnEntry")
{
//lXelements = (XElement)lXelements.Descendants("sdnType").Where(x => x.Name.LocalName == "Individual");
lXelements = (XElement)lXelements.Descendants("sdnType").Where(x => (string)x.Value == "Individual");
}我得到了转换错误，我不知道我的这段代码会给我我想要的结果或不。
错误：
附加信息:无法将类型为'WhereEnumerableIterator`1System.Xml.Linq.XElement‘的对象强制转换为类型“”System.Xml.Linq.XElement“”。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/50167560
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