blocks|key|2466488|text|您可以使用正则表达式：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2466489|import+re

arr+=+np.array([['Family+one206(%2B33%25)1,164(%2B179%25)0418'],
+++++++['Family+one206(%2B33%25)1,164(%2B179%25)0418'],
+++++++['Family+Two(-67%25)23(-47%25)23'],
+++++++['Family+Two(%2B56%25)322(-0.6%25)1080'],
+++++++['Family+Two(%2B56%25)322(-0.6%25)1080'],
+++++++['Family+Two(%2B56%25)322(-0.6%25)1080'],
+++++++['Family+Two(%2B56%25)322(-0.6%25)1080'],
+++++++['Family+Three5,250(%2B2.6%25)36,410(-2.7%25)260412'],
+++++++['Family+Three5,250(%2B2.6%25)36,410(-2.7%25)260412'],
+++++++['Family+Three5,250(%2B2.6%25)36,410(-2.7%25)260412'],
+++++++['Family+Three5,250(%2B2.6%25)36,410(-2.7%25)260412'],
+++++++['Family+Three5,250(%2B2.6%25)36,410(-2.7%25)260412'],
+++++++['Family+Three5,250(%2B2.6%25)36,410(-2.7%25)260412']])

new_array+=+np.array([re.findall('[A-Za-z\s]%2B',+i)+for+i+in+arr.squeeze()])

>>>+new_array
array([['Family+one'],
+++++++['Family+one'],
+++++++['Family+Two'],
+++++++['Family+Two'],
+++++++['Family+Two'],
+++++++['Family+Two'],
+++++++['Family+Two'],
+++++++['Family+Three'],
+++++++['Family+Three'],
+++++++['Family+Three'],
+++++++['Family+Three'],
+++++++['Family+Three'],
+++++++['Family+Three']],
++++++dtype='<U12')|code-block|syntax|javascript|2466490|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use a regex:

<pre><code>import re

arr = np.array([['Family one206(+33%)1,164(+179%)0418'],
 ['Family one206(+33%)1,164(+179%)0418'],
 ['Family Two(-67%)23(-47%)23'],
 ['Family Two(+56%)322(-0.6%)1080'],
 ['Family Two(+56%)322(-0.6%)1080'],
 ['Family Two(+56%)322(-0.6%)1080'],
 ['Family Two(+56%)322(-0.6%)1080'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412']])

new_array = np.array([re.findall('[A-Za-z\s]+', i) for i in arr.squeeze()])

&gt;&gt;&gt; new_array
array([['Family one'],
 ['Family one'],
 ['Family Two'],
 ['Family Two'],
 ['Family Two'],
 ['Family Two'],
 ['Family Two'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three']],
 dtype='&lt;U12')
</code></pre>

blocks|key|2466492|text|您可以决定用非空格替换从非单词开始的位置和下一个非单词到末尾的所有内容让a是上面的数组，然后我们可以这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2466493|import+re
s+=++np.array([[re.sub(r"(?i)[%5EA-Z](?![A-Z]).*","",i)]+for+i+in+a.squeeze()])
s
array([['Family+one'],
+++++++['Family+one'],
+++++++['Family+Two'],
+++++++['Family+Two'],
+++++++['Family+Two'],
+++++++['Family+Two'],
+++++++['Family+Two'],
+++++++['Family+Three'],
+++++++['Family+Three'],
+++++++['Family+Three'],
+++++++['Family+Three'],
+++++++['Family+Three'],
+++++++['Family+Three']],+dtype='<U12')|code-block|syntax|javascript|2466494|entityMap^0|10|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You can decide to replace everything from where a non-word starts and the next is also a non word to the end with non-space
Let <code>a</code> be your array above, then we can do: 

<pre><code>import re
s = np.array([[re.sub(r"(?i)[^A-Z](?![A-Z]).*","",i)] for i in a.squeeze()])
s
array([['Family one'],
 ['Family one'],
 ['Family Two'],
 ['Family Two'],
 ['Family Two'],
 ['Family Two'],
 ['Family Two'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three']], dtype='&lt;U12')
</code></pre>

This is my array:

<pre><code>array([['Family one206(+33%)1,164(+179%)0418'],
 ['Family one206(+33%)1,164(+179%)0418'],
 ['Family Two(-67%)23(-47%)23'],
 ['Family Two(+56%)322(-0.6%)1080'],
 ['Family Two(+56%)322(-0.6%)1080'],
 ['Family Two(+56%)322(-0.6%)1080'],
 ['Family Two(+56%)322(-0.6%)1080'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'],
 ['Family Three5,250(+2.6%)36,410(-2.7%)260412'])
</code></pre>

But i only want my array to looks like :

<pre><code>array([['Family one'],
 ['Family one'],
 ['Family Two'],
 ['Family Two'],
 ['Family Two'],
 ['Family Two'],
 ['Family Two'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three'],
 ['Family Three']])
</code></pre>

I am not sure how i can only select string from a mixed string.

How can I select only characters from a string?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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这是我的数组：array([['Family one206(+33%)1,164(+179%)0418'],       ['Family one206(+33%)1,164(+179%)0418'],       ['Family Two(-67%)23(-47%)23'],       ['Family Two(+...

问如何从字符串中仅选择字符？
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