一般来说,我是Python和Stackoverflow的新手,所以如果我的格式很糟糕,而且我不擅长英语,我很抱歉。但是我对这段代码有一个问题。
n = int(input("Fibonacci sequence (2-10): "))
a = 0
b = 1
sum = 0
count = 1
f = True
print("Fibonacci sequence up to {}: ".format(n), end = " ")
while(count <= n):
print(sum, end = " ")
count += 1
a = b
b = sum
sum = a + b
这是代码的结果
Fibonacci sequence (2-10): 2
Fibonacci sequence up to 2: 0 1
这就是我所期望的结果。
Fibonacci sequence (2-10): 1
Invalid Number!
Fibonacci sequence (2-10): 15
Invalid Number!
Fibonacci sequence (2-10): 10
Fibonacci sequence up to 10: 0 1 1 2 3 5 8 13 21 34
发布于 2020-05-11 23:00:57
看起来您只需要添加一个额外的验证步骤,以确保输入在所需的范围内。这个应该可以了。
while True:
n = int(input("Fibonacci sequence (2-10): "))
if n<2 or n>10:
print("Invalid Number!")
else:
a = 0
b = 1
sum = 0
count = 1
f = True
print("Fibonacci sequence up to {}: ".format(n), end = " ")
while(count <= n):
print(sum, end = " ")
count += 1
a = b
b = sum
sum = a + b
break
编辑:根据@Barmar的观点,如果输入不在所需的范围内,外部的循环将有助于避免重新运行代码。
https://stackoverflow.com/questions/61732749
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