blocks|key|502284|text|还有一种不使用filter()或every()的解决方案|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|502285|//+function

function+AndArray(start,+check)+{

++++this.stripArray+=+function(element,+array)+{
++++++++var+_array+=+[];
++++++++for(var+i+=+0;+i+<+array.length;+i%2B%2B)
++++++++++++for(var+j+=+0;+j+<+array[i].length;+j%2B%2B)
++++++++++++++++if(element+==+array[i][j])+_array.push(array[i]);
++++++++return+_array;
++++++++}

++++for(var+k+=+0;+k+<+start.length;+k%2B%2B)
++++++++if(start.length+>+0)+start+=+this.stripArray(check[k],+start);

++++return+start;

++++}

//+use

var+check+=+[15,+21];

var+start=+[[+15,+6+,+8],+[3,+21,+56],+[15,+3,+21]];

console.log(AndArray(start,+check));++++|code-block|syntax|javascript|502286|entityMap^0|7|8|G|7|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

There is also a solution that is not using <code>filter()</code> or <code>every()</code>:

<pre><code>// function

function AndArray(start, check) {

 this.stripArray = function(element, array) {
 var _array = [];
 for(var i = 0; i &lt; array.length; i++)
 for(var j = 0; j &lt; array[i].length; j++)
 if(element == array[i][j]) _array.push(array[i]);
 return _array;
 }

 for(var k = 0; k &lt; start.length; k++)
 if(start.length &gt; 0) start = this.stripArray(check[k], start);

 return start;

 }

// use

var check = [15, 21];

var start= [[ 15, 6 , 8], [3, 21, 56], [15, 3, 21]];

console.log(AndArray(start, check)); 
</code></pre>

blocks|key|285578|text|您可以使用.filter()+method|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|285579|var+mainArray+=+[+/*+your+array+here+*/+],
++++check+=+["15",+"21"],
++++result;

result+=+mainArray.filter(function(val)+{
++++for+(var+i+=+0;+i+<+check.length;+i%2B%2B)
++++++++if+(val.indexOf(check[i])+===+-1)
++++++++++++return+false;++++
++++return+true;
});

console.log(result);|code-block|syntax|javascript|285580|演示：http://jsfiddle.net/nnnnnn/Dq6YR/|285581|请注意，IE在版本9之前不支持.filter()，但支持you+can+fix+that。|285582|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/filter|1|http://jsfiddle.net/nnnnnn/Dq6YR/|2|https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/filter#Compatibility^0|5|9|5|G|0|0|0|3|X|1|0|F|9|S|G|2|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@$9|13|A|14|1|15]]|E|$]]|$1|F|3|G|5|H|7|16|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|17|8|@]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|M|3|N|5|6|7|1B|8|@$9|1C|A|1D|B|C]]|D|@$9|1E|A|1F|1|1G]]|E|$]]|$1|O|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]|Y|$5|R|S|T|E|$U|Z]]]]

You can use the <a href="https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/filter" rel="noreferrer"><code>.filter()</code> method</a>:

<pre><code>var mainArray = [ /* your array here */ ],
 check = ["15", "21"],
 result;

result = mainArray.filter(function(val) {
 for (var i = 0; i &lt; check.length; i++)
 if (val.indexOf(check[i]) === -1)
 return false; 
 return true;
});

console.log(result);
</code></pre>

Demo: <a href="http://jsfiddle.net/nnnnnn/Dq6YR/" rel="noreferrer">http://jsfiddle.net/nnnnnn/Dq6YR/</a>

Note that <code>.filter()</code> is not supported by IE until version 9, but <a href="https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/filter#Compatibility" rel="noreferrer">you can fix that</a>.

blocks|key|502377|text|使用.filter和.every，您可以筛选行中每个参数都明显的行：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|502378|var+filter+=+function(args)+{
++return+arr.filter(function(row)+{
++++return+args.every(function(arg)+{
++++++return+~row.indexOf(String(arg));++//+[15]+should+search+for+["15"]
++++});
++});
};|code-block|syntax|javascript|502379|在这里，.every可以有效地执行AND操作；对于OR，您可以使用.some代替。这些数组函数在较新的浏览器中可用。|502380|entityMap^0|2|7|A|6|0|0|4|6|H|3|P|2|X|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|N|$]]

Using <code>.filter</code> and <code>.every</code>, you can filter the rows for which every argument is apparent in the row:

<pre><code>var filter = function(args) {
 return arr.filter(function(row) {
 return args.every(function(arg) {
 return ~row.indexOf(String(arg)); // [15] should search for ["15"]
 });
 });
};
</code></pre>

<code>.every</code> effectively does an <code>AND</code> operation here; for <code>OR</code> you could use <code>.some</code> instead. Those array functions are available on newer browsers.

blocks|key|502401|text|这应该就行了|type|unstyled|depth|inlineStyleRanges|entityRanges|data|502402|​|502403|var+checkURL+=+function+(url)+{
++var+final+=+false;
++if+(url.indexOf('jpg')+>+-1)+{
++++final+=+true
++}

++if+(url.indexOf('jpeg')+>+-1)+{
++++final+=+true
++}

++if+(url.indexOf('gif')+>+-1)+{
++++final+=+true
++}

++if+(url.indexOf('png')+>+-1)+{
++++final+=+true
++}

++return+final
}|code-block|syntax|javascript|502404|502405|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

This should do it

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var checkURL = function (url) {
 var final = false;
 if (url.indexOf('jpg') &gt; -1) {
 final = true
 }

 if (url.indexOf('jpeg') &gt; -1) {
 final = true
 }

 if (url.indexOf('gif') &gt; -1) {
 final = true
 }

 if (url.indexOf('png') &gt; -1) {
 final = true
 }

 return final
}</code></pre>
</div>
</div>

Im having a multdimensional javascript arrays like this.

<pre><code>[
["9", "16", "19", "24", "29", "38"],
["9", "15", "19", "24", "29", "38"],
["10", "16", "19", "24", "29", "38"],
["9", "16", "17", "19", "24", "29", "39"],
["10", "16", "17", "19", "24", "29", "39"],
["9", "15", "21", "24", "29", "38"]

.......
.......
]
</code></pre>

Around 40 to be exact

and im having an another array called check with the following values

<pre><code> [9,10] //This is of size two for example,it may contain any number of elements BUT it only contains elements(digits) from the multidimensional array above
</code></pre>

What i want is i need to make the multidimensional array unique based for the check array elements

1.Example if check array is <code>[15]</code>
Then multidimensional array would be

<pre><code>[
 ["9", "15", "19", "24", "29", "38"],
 //All the results which contain 15

]
</code></pre>

2.Example if check array is <code>[15,21]</code>
Then multidimensional array would be

<pre><code>[
 ["9", "15", "21", "24", "29", "38"]
 //simply containing 15 AND 21.Please note previous example has only 15 in it not 21
 //I need an AND not an OR

]
</code></pre>

I had tried the JavaScript IndexOf method BUt it is getting me an OR'ed result not AND

Thanks in Advance

Javascript index of for multiple values

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个像这样的多维javascript数组。[["9", "16", "19", "24", "29", "38"],["9", "15", "19", "24", "29", "38"],["10", "16", "19", "24", "29", "38"],["9", "16", "17", "19", "24...

问多个值的Javascript索引
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