blocks|key|432002|text|我想知道你的老师是否因为你的输入字符串默认没有空格而在输入中添加了他们自己的空格。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|432003|试试这个：|432004|duckcount+=+0
animal+=+''
while+True:
++++animal+=+input('enter+animal:+').strip()
++++if+animal+==+'duck':
++++++++duckcount+%2B=+1
++++elif+animal+==+'goose':
++++++++break

if+duckcount+==+1:
++++print('There+is+{}+duck!'.format(duckcount))
else:
++++print('There+are+{}+ducks!'.format(duckcount))|code-block|syntax|javascript|432005|结果：|432006|enter+animal:+duck+++
enter+animal:++++duck
enter+animal:++duck
enter+animal:+goose
There+are+3+ducks!|432007|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I am wondering if your teacher added their own spaces to the input due to your input string not having any by default.

Try this:

<pre><code>duckcount = 0
animal = ''
while True:
 animal = input('enter animal: ').strip()
 if animal == 'duck':
 duckcount += 1
 elif animal == 'goose':
 break

if duckcount == 1:
 print('There is {} duck!'.format(duckcount))
else:
 print('There are {} ducks!'.format(duckcount))
</code></pre>

Results:

<pre><code>enter animal: duck 
enter animal: duck
enter animal: duck
enter animal: goose
There are 3 ducks!
</code></pre>

blocks|key|432009|text|好的，我想出来了，user10987432给了我这个想法。我所做的就是把“进入动物”换成“”。我想我应该只使用空格作为输入。(这是可行的，但我喜欢有一条关于如何做的小消息作为首选)。感谢所有的回复！|type|unstyled|depth|inlineStyleRanges|entityRanges|data|432010|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

OK I figured it out, user10987432 gave me this idea.
All i did was replace 'enter animal' with ''. 
I guess I was supposed to just use a blank space for an input. (Which works but I like having a little message on what to do as a preference).
thanks for all the responses!

blocks|key|390576|text|_stdout是程序在命令行上打印内容时写入的输出。你的程序的逻辑是完美无缺的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|390577|由于输出被标记为不正确，我会首先询问老师是否需要特定的措辞。我预计他/她可能会将特定的输出硬编码到作业解析器中。如果是这样，那么只需将您的print(duckcounter)更改为老师硬编码的任何句子/输出(正如我所说的，最好的做法是询问他/她是否这样做了)。|offset|length|style|CODE|390578|正如Mike+-+SMT所说，老师也可以修改input语句。您可以将输入看作由两部分组成的命令。首先，它将输出内容打印到_stdout+(在命令行上输出)，然后等待特定的操作(通常是您键入内容并按enter键)。|390579|你也可以这样做：|390580|animal+=+''
counter+=+0
while+animal+!=+'goose':
++animal+=+input('Please+enter+either+"Goose"+or+"Duck":+')
++animal+=+animal.lower()+#+make+everything+lowercase
++if+animal+==+'duck':
++++counter+%2B=+1
print('You+have+typed+"duck"+{}+times'.format(counter))|code-block|syntax|javascript|390581|如果你有任何问题，请告诉我。|390582|entityMap^0|0|1X|I|0|M|5|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|Y|8|@$D|Z|E|10|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|11|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|12|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|T|$]]

_stdout is the output that your program is writing to when it prints things on the command line.
The logic of your program is perfetly fine as it is.

Since the output is marked as being incorrect I would first ask the teacher if he wants a specific wording.
I expect that he/she probably hardcoded a specific output into the Homework-Parser. If that's the case then just change your <code>print(duckcounter)</code> to whatever sentence/output the teacher hardcoded (as I said the best was would be to ask him/her if she/he has done that).

As said by Mike - SMT the teacher could have modified the <code>input</code> statement as well. You can think about the input as a two-part command. First it prints something out to _stdout (output on the command line) and then waits for a specific action (usually that you type something in and hit enter).

You could as well do something like this:

<pre><code>animal = ''
counter = 0
while animal != 'goose':
 animal = input('Please enter either "Goose" or "Duck": ')
 animal = animal.lower() # make everything lowercase
 if animal == 'duck':
 counter += 1
print('You have typed "duck" {} times'.format(counter))
</code></pre>

If you have any questions let me know.

blocks|key|390572|text|感谢你分享这篇文章！我最近也在研究这个问题，但有一个特定的指令，让输入函数不带提示字符串。您的原始代码在IDLE中运行得很好，但我必须执行以下操作才能得到我的Pearson教科书接受的答案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|390573|duckcount+=+0
animal+=+''
while+True:
++++animal+=+input()
++++if+animal+==+'duck':
++++++duckcount+%2B=1
elif+animal+==+'goose':
+++++++break
print(duckcount)|code-block|syntax|javascript|390574|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Thank you for sharing this! I was recently working on this question as well, but with the specific instruction to leave the input function without a prompt string. Your original code ran just fine for me in IDLE, but I had to do the following to get the answer accepted by my Pearson textbook:
<pre><code>duckcount = 0
animal = ''
while True:
 animal = input()
 if animal == 'duck':
 duckcount +=1
elif animal == 'goose':
 break
print(duckcount)
</code></pre>

So I am working on Python homework, and I prefer to write the answers to the homework in an IDE, then copy and paste my answer. 
For this specific problem I did just that, and while the code works in the IDE just fine, it is marked as incorrect on the homework.

Homework question: 
Write a loop that reads strings from standard input, where the string is either "duck" or "goose". The loop terminates when "goose" is read in. After the loop, your code should print out the number of "duck" strings that were read.

What my homework says: 
Problems Detected:
 ⇒ The value of _stdout is incorrect.

My answer:

<pre><code>duckcount = 0
animal = ''
while True:
 animal = input('enter animal')
 if animal == 'duck':
 duckcount +=1
 elif animal == 'goose':
 break
print(duckcount)
</code></pre>

The code works fine in my IDE, but the error message I get on my homework is: The value of _stdout is incorrect.

Python: Code in IDE is correct, but is incorrect in homework

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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因此，我正在做Python作业，我更喜欢在IDE中编写作业的答案，然后复制并粘贴我的答案。对于这个特定的问题，我就是这么做的，虽然代码在IDE中运行良好，但它在作业中被标记为不正确。家庭作业问题:编写一个从标准输入中读取字符串的循环，其中字符串是“鸭子”或“鹅”。当"goose“被读入时，循环终止。在循环之后，您的代码...

问Python: IDE中的代码是正确的，但作业中的代码是错误的
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问Python: IDE中的代码是正确的，但作业中的代码是错误的EN