每隔10秒在andriod中的google地图上绘制一条折线
每隔10秒在andriod中的google地图上绘制一条折线
提问于 2016-09-25 23:26:47
我做了一个应用程序，按下start按钮后，每隔10秒获取用户的位置，并从旧位置绘制一条折线到新位置，直到按下stop按钮。现在的问题是，当折线代码在run函数中时，地图上没有绘制直线。但是如果我把代码放在run函数之外，它就能正常工作(就像当我重新按下start按钮时，我得到了polyline)，但我不想每次都按下按钮，我想要通过计时器自动绘制这条线。
以下是我的代码
track_record.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Toast.makeText(getApplication(), "Your Tracking is started now", Toast.LENGTH_SHORT).show();
///////*************************************////////
// create class object
gps = new GPSTracker(MapsActivity.this);
timer.scheduleAtFixedRate(new TimerTask() {
@SuppressLint("DefaultLocale")
@TargetApi(Build.VERSION_CODES.GINGERBREAD)
@Override
public void run() {
runOnUiThread(new Runnable() {
@Override
public void run() {
LatLng current = new LatLng(latitude = gps.getLatitude(),longitude = gps.getLongitude());
if (begin == 0) {
fixedBegin = current;
// create marker
MarkerOptions marker = new MarkerOptions().position(fixedBegin).title("Begin ");
// Changing the color babyyy
marker.icon(BitmapDescriptorFactory.defaultMarker(BitmapDescriptorFactory.HUE_RED));
// adding marker
mMap.addMarker(marker);
// Not working here, but should be
if(Flag==0) //when the first update comes, we have no previous points,hence this
{
prev=current;
Flag=1;
}
CameraUpdate update = CameraUpdateFactory.newLatLngZoom(current, 16);
mMap.animateCamera(update);
mMap.addPolyline((new PolylineOptions())
.add(prev, current).width(6).color(Color.BLUE)
.visible(true));
prev=current;
current = null;
}
begin++;
Log.i("OK", "lat------ " + latitude);
Log.i("OK", "lng-------- " + longitude);
arrLat.add(latitude);
arrLng.add(longitude);
//////////// TRYING ///////////
// And it Worked here
/*
if(Flag==0) //when the first update comes, we have no previous points,hence this
{
prev=current;
Flag=1;
}
CameraUpdate update = CameraUpdateFactory.newLatLngZoom(current, 16);
mMap.animateCamera(update);
mMap.addPolyline((new PolylineOptions())
.add(prev, current).width(6).color(Color.BLUE)
.visible(true));
prev=current;
current = null;
*/
}
});
}
}, 0, TIME_INTERVAL);
// check if GPS enabled
if (gps.canGetLocation()) {
latitude = gps.getLatitude();
longitude = gps.getLongitude();
String longlat = String.valueOf(latitude) + ":" + String.valueOf(longitude);
cordsList.add(longlat);
// \n is for new line
Toast.makeText(getApplicationContext(), "Your Location is - \nLat: " + latitude + "\nLong: " + longitude, Toast.LENGTH_LONG).show();
} else {
Toast.makeText(getApplicationContext(), "Sorry cant get location", Toast.LENGTH_LONG).show();
// can't get location
// GPS or Network is not enabled
// Ask user to enable GPS/network in settings
// gps.showSettingsAlert();
}
Log.i("Finall", "Location-> " + cordsList.toString());
}
}
);回答 1
Stack Overflow用户
发布于 2016-09-25 23:33:02
您可以使用Handler来实现此目的。
类变量。
Handler m_handler;
Runnable m_handlerTask ;
int t=0;在延迟10秒的情况下使用处理程序绘制多段线
m_handler = new Handler();
m_handlerTask = new Runnable()
{
@Override
public void run() {
if(t<listPoint.size()-1)
{
LatLng src = listPoint.get(t);
LatLng dest = listPoint.get(t + 1);
Polyline line = mMap.addPolyline(new PolylineOptions()
.add(new LatLng(src.latitude, src.longitude),
new LatLng(dest.latitude,dest.longitude))
.width(2).color(Color.BLUE).geodesic(true));
t++;
}
else
{
m_handler.removeCallbacks(m_handlerTask);
}
m_handler.postDelayed(m_handlerTask, 10000);
}
};
m_handlerTask.run(); 页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/39688563
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