问使用Subject的react文本输入组件上的Rxjs去反弹不会在无状态/功能组件上批量输入文本

EN

import React, { Component, useState, useEffect, useRef } from 'react';
import { render } from 'react-dom';
import { debounceTime, map, tap, distinctUntilChanged } from 'rxjs/operators';
import { fromEvent, Subject } from 'rxjs';

import './style.css';
const App = props => {
  const [queryName, setQueryName] = useState("");
  const [debouncedName, setDebouncedName] = useState("");
  const [onSearch$] = useState(()=>new Subject());
  useEffect(() => {
    const subscription = onSearch$.pipe(
      debounceTime(400),
      distinctUntilChanged(),
      tap(a => console.log(a))
    ).subscribe(setDebouncedName);
  }, [])
  const handleSearch = e => {
    setQueryName(e.target.value);
    onSearch$.next(e.target.value);
  };

  return (
    <div>
      <input
        placeholder="Search Tags"
        value={queryName}
        onChange={handleSearch}
      />
      <p>Debounced: {debouncedName}</p>
    </div>
  );
}

render(<App />, document.getElementById('root'));

function useDebounce<T = any>(time: number, defaultValue: T): [T, (v: T) => void] {
  let [value, setValue] = React.useState<T>(defaultValue);
  let [value$] = React.useState(() => new Subject<T>());
  React.useEffect(() => {
    let sub = value$.pipe(debounceTime(time)).subscribe(setValue);
    return () => sub.unsubscribe();
  }, [time, value$]);
 return [value, (v) => value$.next(v)];
}

//useage: 
let [value,setValue] = useDebounce(200,"");