下面的代码从通道获取worker并执行函数"call",所有的例程都完成并打印,它们已经完成但等待永远不会结束,我跟踪了WaitGroup的计数器,使变量计数器在添加到wg时递增,在完成时递减,并在for循环的末尾为零,请帮助
package mapreduce
import (
"fmt"
"sync"
)
func schedule(jobName string, mapFiles []string, nReduce int, phase jobPhase, registerChan chan string) {
var ntasks int
var n_other int // number of inputs (for reduce) or outputs (for map)
switch phase {
case mapPhase:
ntasks = len(mapFiles)
n_other = nReduce
case reducePhase:
ntasks = nReduce
n_other = len(mapFiles)
}
fmt.Printf("Schedule: %v %v tasks (%d I/Os)\n", ntasks, phase, n_other)
var wg sync.WaitGroup
for i := 0; i < ntasks; i++ {
worker := <-registerChan
doTaskArg := DoTaskArgs{jobName, mapFiles[i], phase, i, n_other}
wg.Add(1)
go func() {
defer wg.Done()
done := call(worker, "Worker.DoTask", doTaskArg, nil)
if done {
registerChan <- worker
} else {
i = i - 1
}
}()
}
wg.Wait()
fmt.Printf("Schedule: %v phase done\n", phase)
}发布于 2017-03-13 14:26:27
频道阻塞了你的goroutine。如果您将一些数据放入一个未缓冲的通道中,则goroutine将一直等待,直到接收器从该通道获取数据。在本例中,您在register <- worker和defer wg.Done()处的例程块永远不会被调用,因为函数正在等待。
https://stackoverflow.com/questions/42751814
复制相似问题