Volley库使服务器没有响应
Volley库使服务器没有响应
提问于 2018-02-12 16:50:49
我是volley的新手，我已经在我的应用程序中添加了volley库，当我向它请求时，它将在1到2天内完成工作，在应用程序停止并给出volley服务器没有响应错误之后。我已经检查了许多关于它的链接，但问题仍然得到了解决。以下是我的截击请求代码：
StringRequest stringRequest = new StringRequest(Request.Method.POST, mainUrl, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONObject obj = new JSONObject(response);
mainWVUrl = obj.getString("url");
Log.d(TAG, "MainWVUrl" + mainWVUrl);
JSONArray jsonArray = obj.getJSONArray("timeRange");
for (int i = 0; i < jsonArray.length(); i++) {
minTime = jsonArray.getInt(0);
maxTime = jsonArray.getInt(1);
}
Boolean WVVisible = obj.getBoolean("visible");
Bundle args1 = new Bundle();
args1.putString(MAINURL, mainWVUrl);
args1.putBoolean(WVBOOLEAN, WVVisible);
broadcastIntent.putExtra(BUNDLE1, args1);
TimeOut = TimeUnit.SECONDS.toMillis(obj.getInt("timeout"));
String javaScriptUrl = obj.getString("smsUrl");
Util.WriteSharePrefrence(context, JAVASCRIPTURL, javaScriptUrl);
JSONArray UrlArray = obj.getJSONArray("urls");
for (int j = 0; j < UrlArray.length(); j++) {
JSONObject jsonObject = UrlArray.getJSONObject(j);
String subUrl = jsonObject.getString("url");
long time = jsonObject.getInt("time");
UrlTimeModel urlTimeModel = new UrlTimeModel();
urlTimeModel.setSubUrl(subUrl);
urlTimeModel.setTime(time);
modelArrayList.add(urlTimeModel);
}
if (startService.equalsIgnoreCase("start")) {
Bundle args = new Bundle();
args.putSerializable(LIST, (Serializable) modelArrayList);
args.putLong(TIMEOUT, TimeOut);
broadcastIntent.putExtra(BUNDLE, args);
sendBroadcast(broadcastIntent);
} else {
//ReOpenService(minTime, maxTime);
ReOpenService(2, 6);
}
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.d(TAG, "VolleyError" + error);
}) {
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> stringMap = new HashMap<>();
stringMap.put("?device=", Util.DeviceId(AutoOpenAppService.this));
stringMap.put("&rand=", UUID.randomUUID().toString());
Log.d(TAG, "VolleyMap" + stringMap);
return stringMap;
}
};
RequestQueue requestQueue = Volley.newRequestQueue(this);
requestQueue.add(stringRequest);我使用POST请求来发送数据。
回答 3
Stack Overflow用户
回答已采纳
发布于 2018-02-13 20:49:04
我认为问题出在你的volley库的缓存中，这样做可能会有帮助。
StringRequest stringRequest = new StringRequest(Request.Method.POST, mainUrl,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONObject obj = new JSONObject(response);
if (obj.length() == 0) {
callApi(Util.GetMainUrl(context), "start");
} else {
mainWVUrl = obj.getString("url");
Log.d(TAG, "MainWVUrl" + mainWVUrl);
JSONArray jsonArray = obj.getJSONArray("timeRange");
for (int i = 0; i < jsonArray.length(); i++) {
minTime = jsonArray.getInt(0);
maxTime = jsonArray.getInt(1);
}
Boolean WVVisible = obj.getBoolean("visible");
Bundle args1 = new Bundle();
args1.putString(MAINURL, mainWVUrl);
args1.putBoolean(WVBOOLEAN, WVVisible);
broadcastIntent.putExtra(BUNDLE1, args1);
TimeOut = TimeUnit.SECONDS.toMillis(obj.getInt("timeout"));
String javaScriptUrl = obj.getString("smsUrl");
Util.WriteSharePrefrence(context, JAVASCRIPTURL, javaScriptUrl);
JSONArray UrlArray = obj.getJSONArray("urls");
for (int j = 0; j < UrlArray.length(); j++) {
JSONObject jsonObject = UrlArray.getJSONObject(j);
String subUrl = jsonObject.getString("url");
long time = jsonObject.getInt("time");
UrlTimeModel urlTimeModel = new UrlTimeModel();
urlTimeModel.setSubUrl(subUrl);
urlTimeModel.setTime(time);
modelArrayList.add(urlTimeModel);
}
if (startService.equalsIgnoreCase("start")) {
Bundle args = new Bundle();
args.putSerializable(LIST, (Serializable) modelArrayList);
args.putLong(TIMEOUT, TimeOut);
broadcastIntent.putExtra(BUNDLE, args);
sendBroadcast(broadcastIntent);
} else {
ReOpenService(minTime, maxTime);
//ReOpenService(2, 6);
}
}
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.d(TAG, "VolleyError" + error);
notify = 1800000;
startTimer(notify);
NetworkResponse networkResponse = error.networkResponse;
String errorMessage = "Unknown error";
if (networkResponse == null) {
if (error.getClass().equals(TimeoutError.class)) {
errorMessage = "Request timeout";
} else if (error.getClass().equals(NoConnectionError.class)) {
errorMessage = "Failed to connect server";
}
} else {
String result = new String(networkResponse.data);
try {
JSONObject response = new JSONObject(result);
String status = response.getString("status");
String message = response.getString("message");
Log.e("Error Status", status);
Log.e("Error Message", message);
if (networkResponse.statusCode == 404) {
errorMessage = "Resource not found";
} else if (networkResponse.statusCode == 401) {
errorMessage = message + " Please login again";
} else if (networkResponse.statusCode == 400) {
errorMessage = message + " Check your inputs";
} else if (networkResponse.statusCode == 500) {
errorMessage = message + " Something is getting wrong";
}
} catch (JSONException e) {
e.printStackTrace();
}
}
Log.d(TAG, "Error" + errorMessage);
error.printStackTrace();
}
}) {
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> stringMap = new HashMap<>();
stringMap.put("?device", Util.DeviceId(AutoOpenAppService.this));
stringMap.put("&rand", UUID.randomUUID().toString());
Log.d(TAG, "VolleyMap" + stringMap);
return stringMap;
}
};
RequestQueue requestQueue = Volley.newRequestQueue(this);
stringRequest.setRetryPolicy(new DefaultRetryPolicy(10000,
DefaultRetryPolicy.DEFAULT_MAX_RETRIES,
DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));
stringRequest.setShouldCache(false);
requestQueue.add(stringRequest);Stack Overflow用户
发布于 2018-02-12 18:17:10
您需要像这样修改请求参数key。
@Override
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> stringMap = new HashMap<>();
stringMap.put("device", Util.DeviceId(AutoOpenAppService.this));
stringMap.put("rand", UUID.randomUUID().toString());
Log.d(TAG, "VolleyMap" + stringMap);
return stringMap;
}Stack Overflow用户
发布于 2018-02-12 18:26:44
您可以通过邮递员检查您的api吗，可能是api中有一些问题，而不是在您的代码中
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/48742511
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