SyntaxError:分析ast.literal_eval()时出现意外的EOF
SyntaxError:分析ast.literal_eval()时出现意外的EOF
提问于 2018-08-19 16:36:43
我正在编写一个函数来使用函数find_key(label)：来找出字母出现的计数。在我尝试将字符串转换为字典后，它显示了错误。我已经检查过了，但找不到正确的答案。下面是我的代码：
import ast
def find_key(label):
result={}
with open('test.txt', 'r') as f:
# print(f.readlines())
word_list=f.readlines()[0]
# new_list=ast.literal_eval(word_list)
print(type(word_list))
for word in word_list.split(','):
# for item in word_list:
word.strip(',{}')
print(type(word))
print(word)
new_word=ast.literal_eval(word)
print(type(new_word))
# print(i.keys())
if new_word.get(label):
key=new_word.get(label)
num=result.get(key)
if num is not None and num >= 1:
result[num] = num + 1
else:
result[num] = {key:1}
print(result)
if __name__ == '__main__':
find_key("6-15")
# dict = {'Name': 'Zara', 'Age': 27}
#
# print("Value : %s" % dict.get('Age'))
# print("Value : %s" % dict.get('Sex', "Never"))
#
# print(dict)这是我试图导入数据的"text.txt“文件中的格式：
{'6-15':'ab'},{'9-9':'bc'},{'6-11':'cd'},{'9-9':'ef'},{'11-6':'de'},{'6-8':'fg'},{'4-15':'gh'},{'16-13':'hi'},以下是我尝试打印输出以检查变量word_list、word和new_word的类型时的日志：
<class 'str'>
<class 'str'>
{'6-15':'ab'}
<class 'dict'>
<class 'str'>
{'9-9':'bc'}
<class 'dict'>
<class 'str'>
{'6-11':'cd'}
<class 'dict'>
<class 'str'>
{'9-9':'ef'}
<class 'dict'>
<class 'str'>
{'11-6':'de'}
<class 'dict'>
<class 'str'>
{'6-8':'fg'}
<class 'dict'>
<class 'str'>
{'4-15':'gh'}
<class 'dict'>
<class 'str'>
{'16-13':'hi'}
<class 'dict'>
<class 'str'>下面是我运行代码后显示的错误。
Traceback (most recent call last):
File "/Users/chenneyhuang/PycharmProjects/freestyle/test.py", line 49, in <module>
find_key("6-15")
File "/Users/chenneyhuang/PycharmProjects/freestyle/test.py", line 33, in find_key
new_word=ast.literal_eval(word)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ast.py", line 48, in literal_eval
node_or_string = parse(node_or_string, mode='eval')
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ast.py", line 35, in parse
return compile(source, filename, mode, PyCF_ONLY_AST)
File "<unknown>", line 0
^
SyntaxError: unexpected EOF while parsing我使用的是Python3.6。我使用的IDE是Pycharm。谢谢。
回答 1
Stack Overflow用户
回答已采纳
发布于 2018-08-19 17:05:56
你可以在你的文件-obj上使用next来简化你的代码，以获得以下行(而不是.readlines()[0])，然后循环遍历ast.literal_eval'ing返回的字典，使用一个Counter来计算匹配你的标签的每个键有多少个值，例如：
import ast
from collections import Counter
def find_key(label):
with open('test.txt') as fin:
# evaluate first line and default to empty tuple if file empty
dicts = ast.literal_eval(next(fin, '()'))
# Count occurrences of values for all dicts that have the label as a key
return Counter(d[label] for d in dicts if label in d)
res = find_key('6-15')
# Counter({'ab': 1})和：
res = find_key('9-9')
#Counter({'bc': 1, 'ef': 1})页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/51915920
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