我想从下面的hashmap中获取公共时间集的工作日
我想从下面的hashmap中获取公共时间集的工作日
提问于 2018-02-06 16:32:27
我有一个如下的hashmap：
HashMap<String, String> days = new HashMap<String, String>(){
days.put("MON", "9-5");
days.put("TUE", "9-4");
days.put("WED", "9-5");
days.put("THU", "9-5");
days.put("FR", "9-5");
days.put("SAT", "Closed");
days.put("SUN", "Closed");
};我想要显示以下输出：
MON-WED-THU-FRI : 9-5, TUE: 9-4, SAT-SUN : Closed
注意: hashmap("9-5")的值可能会根据来自管理面板的输入而变化
我已经完成了以下代码，但它太长了：
private void days() {
String timing1 = null;
String timing2 = null;
String timing3 = null;
String timing4 = null;
String timing5 = null;
String timing6 = null;
String timing7 = null;
ArrayList<String> time1 =new ArrayList<>();
ArrayList<String> time2 =new ArrayList<>();
ArrayList<String> time3 =new ArrayList<>();
ArrayList<String> time4 =new ArrayList<>();
ArrayList<String> time5 =new ArrayList<>();
ArrayList<String> time6 =new ArrayList<>();
ArrayList<String> time7 =new ArrayList<>();迭代散列映射并取值(即存储在受尊重变量中的时间
for (Map.Entry<String, String> entry : days.entrySet()) {
String key = entry.getKey();
Object value = entry.getValue();
System.out.println("key" + key + "Val" + value.toString());
if (timing1 ==null || timing1.equals(value.toString())){
timing1 = value.toString();
continue;
}
if (timing2 ==null || timing2.equals(value.toString())){
timing2 = value.toString();
continue;
}
if (timing3 ==null || timing3.equals(value.toString())){
timing3 = value.toString();
continue;
}
if (timing4 ==null || timing4.equals(value.toString())){
timing4 = value.toString();
continue;
}
if (timing5 ==null || timing5.equals(value.toString())){
timing5 = value.toString();
continue;
}
if (timing6 ==null || timing6.equals(value.toString())){
timing6 = value.toString();
continue;
}
if (timing7 ==null || timing7.equals(value.toString())){
timing7 = value.toString();
}
}基于来自附加关键字ie的散列映射的值。天数名称(例如MON)添加到受人尊敬的array-list
for (Map.Entry<String, String> entry : days.entrySet()) {
String key = entry.getKey();
Object value = entry.getValue();
if (timing1!=null && timing1.equals(value.toString())){
time1.add(key);
continue;
}
if (timing2!=null && timing2.equals(value.toString())){
time2.add(key);
continue;
}
if (timing3!=null && timing3.equals(value.toString())){
time3.add(key);
continue;
}
if (timing4!=null && timing4.equals(value.toString())){
time4.add(key);
continue;
}
if (timing5!=null && timing5.equals(value.toString())){
time5.add(key);
continue;
}
if (timing6!=null && timing6.equals(value.toString())){
time6.add(key);
continue;
}
if (timing7!=null && timing7.equals(value.toString())){
time7.add(key);
// continue;
}
}回答 2
Stack Overflow用户
发布于 2018-02-06 17:05:55
请看看下面的内容是否有帮助。但是，这些值并没有按照此输出进行排序。
打印: 9-4 TUE
9-5清华WED FR MON
闭合SAT太阳
public void formatMap(HashMap<String,String> hMap){
HashMap<String, String> formattedMap = new HashMap<String, String>();
Set<String> lKeys = (Set)hMap.keySet();
for(String sKey : lKeys){
String sValue = hMap.get(sKey);
if(formattedMap.get(sValue) == null){
formattedMap.put(sValue, sKey);
}else{
String temp = formattedMap.get(sValue);
temp += " "+sKey;
formattedMap.put(sValue, temp);
}
}
lKeys = (Set)formattedMap.keySet();
for(String s : lKeys){
System.out.println(s +" "+formattedMap.get(s));
}
}Stack Overflow用户
发布于 2018-02-06 17:07:54
好吧，使用一些对象会更容易：
首先是一个用于存储时间表的类
package schedule;
public class DaySchedule {
String weekDay;
int minHour, maxHour;
boolean open;
public DaySchedule(String weekDay, int minHour, int maxHour, boolean open) {
this.weekDay = weekDay;
this.minHour = minHour;
this.maxHour = maxHour;
this.open = open;
}
public String getWeekDay() {
return weekDay;
}
/**
* Returns a unique key based on min and max hour
* -1 is the key for closed status
* @return int value
*/
public String getKey() {
if (open)
return String.valueOf(minHour)+"-"+String.valueOf(maxHour);
else
return "Closed";
}
}然后使用一个实用程序类来构建最终结果。
package schedule;
import java.util.HashMap;
import java.util.Iterator;
import java.util.Map;
public class ScheduleBuilder {
HashMap<String, StringBuilder> builderHashMap = new HashMap<>();
public void addSchedule(DaySchedule daySchedule) {
String key = daySchedule.getKey();
if (builderHashMap.containsKey(daySchedule.getKey())) {
StringBuilder stringBuilder = builderHashMap.get(key);
// If there is a string builder, there is already something in it, so add a -
stringBuilder.append('-');
stringBuilder.append(daySchedule.getWeekDay());
} else {
builderHashMap.put(key, new StringBuilder(daySchedule.getWeekDay()));
}
}
public String toString(){
StringBuilder result = new StringBuilder();
Iterator iterator = builderHashMap.entrySet().iterator();
while (iterator.hasNext()) {
if(result.length()>0){
result.append(',');
}
Map.Entry pair = (Map.Entry)iterator.next();
result.append(pair.getValue());
result.append(":");
result.append(pair.getKey());
iterator.remove(); // avoids a ConcurrentModificationException
}
return result.toString();
}
}为了测试..。
package schedule;
import java.util.ArrayList;
import java.util.Iterator;
public class Test {
public static void main(String[] args) {
ArrayList<DaySchedule> dayScheduleArrayList = new ArrayList<DaySchedule>(7);
dayScheduleArrayList.add(new DaySchedule("MON", 9, 5, true));
dayScheduleArrayList.add(new DaySchedule("TUE", 9, 4, true));
dayScheduleArrayList.add(new DaySchedule("WED", 9, 5, true));
dayScheduleArrayList.add(new DaySchedule("THU", 9, 5, true));
dayScheduleArrayList.add(new DaySchedule("FR", 9, 5, true));
dayScheduleArrayList.add(new DaySchedule("SAT", 0, 0, false));
dayScheduleArrayList.add(new DaySchedule("SUN", 0, 0, false));
ScheduleBuilder scheduleBuilder = new ScheduleBuilder();
for (Iterator<DaySchedule> iterator = dayScheduleArrayList.iterator(); iterator.hasNext(); ) {
DaySchedule daySchedule = iterator.next();
scheduleBuilder.addSchedule(daySchedule);
}
System.out.println("scheduleBuilder = " + scheduleBuilder);
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/48638589
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